How can I grep for empty functions?
I'm recursively looking in a directory for all functions containing only a blank one-line comment, such as the following:
public function index()
{
//
}
I tried grep -PR "//$" * with no luck. Any help would be much appreciated, and thanks in advance.
shell grep regular-expression
asked 19 mins ago
Brandon M.Brandon M.
1062
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I'm recursively looking in a directory for all functions containing only a blank one-line comment, such as the following:
public function index()
{
//
}
I tried grep -PR "//$" * with no luck. Any help would be much appreciated, and thanks in advance.
shell grep regular-expression
asked 19 mins ago
Brandon M.Brandon M.
1062
New contributor
Brandon M. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Doesn'tgrep -PR "^s*//s*$" *work?
– terdon♦
16 mins ago
It does. Thanks!
– Brandon M.
7 mins ago
add a comment |
I'm recursively looking in a directory for all functions containing only a blank one-line comment, such as the following:
public function index()
{
//
}
I tried grep -PR "//$" * with no luck. Any help would be much appreciated, and thanks in advance.
shell grep regular-expression
asked 19 mins ago
Brandon M.Brandon M.
1062
New contributor
Brandon M. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm recursively looking in a directory for all functions containing only a blank one-line comment, such as the following:
public function index()
{
//
}
I tried grep -PR "//$" * with no luck. Any help would be much appreciated, and thanks in advance.
shell grep regular-expression
shell grep regular-expression
asked 19 mins ago
Brandon M.Brandon M.
1062
New contributor
Brandon M. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 19 mins ago
Brandon M.Brandon M.
1062
New contributor
Brandon M. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 19 mins ago
Brandon M.Brandon M.
1062
New contributor
Brandon M. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 19 mins ago
Brandon M.Brandon M.
1062
asked 19 mins ago
Brandon M.Brandon M.
1062
1062
New contributor
Brandon M. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Brandon M. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Brandon M. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Doesn'tgrep -PR "^s*//s*$" *work?
– terdon♦
16 mins ago
It does. Thanks!
– Brandon M.
7 mins ago
add a comment |
1
Doesn'tgrep -PR "^s*//s*$" *work?
– terdon♦
16 mins ago
It does. Thanks!
– Brandon M.
7 mins ago
1
1
Doesn't
grep -PR "^s*//s*$" * work?– terdon♦
16 mins ago
Doesn't
grep -PR "^s*//s*$" * work?– terdon♦
16 mins ago
It does. Thanks!
– Brandon M.
7 mins ago
It does. Thanks!
– Brandon M.
7 mins ago
add a comment |
1 Answer
1
active
oldest
votes
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered 4 mins ago
terdon♦terdon
129k31252427
add a comment |
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1 Answer
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1 Answer
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active
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votes
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered 4 mins ago
terdon♦terdon
129k31252427
add a comment |
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered 4 mins ago
terdon♦terdon
129k31252427
add a comment |
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered 4 mins ago
terdon♦terdon
129k31252427
Your grep is only matching // that are at the very end of the line. Your functions probably have whitespace characters after that. You might also want to allow whitespace before the //. so search for lines that consist entirely of 0 or more whitespace characters, then the // and then 0 or more whitespace characters:
grep -PR '^s*//s*$'
answered 4 mins ago
terdon♦terdon
129k31252427
answered 4 mins ago
terdon♦terdon
129k31252427
answered 4 mins ago
terdon♦terdon
129k31252427
answered 4 mins ago
terdon♦terdon
129k31252427
129k31252427
add a comment |
add a comment |
Brandon M. is a new contributor. Be nice, and check out our Code of Conduct.
Brandon M. is a new contributor. Be nice, and check out our Code of Conduct.
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1
Doesn't
grep -PR "^s*//s*$" *work?– terdon♦
16 mins ago
It does. Thanks!
– Brandon M.
7 mins ago