Yrurtj

2 $begingroup$ From what I understand about distribution coefficient is straight from my book-- which does NOT give any practice examples-- is that: D= CA(ext) ÷ CA(orig) where CA(ext) and CA(orig) represent the total concentration of all analyte species present in the two phases regardless of chemical state. Below is a homework problem that I'm try to solve, but having no luck, since I'm not given any concentrations, only weight and volume. In an extraction experiment, it is found that 0.0376 g of an analyte are extracted into 50 mL of solvent from 150 mL of a water sample. If there was originally 0.192 g of analyte in this volume of the water sample, what is the distribution coefficient? The answer for this problem is 0.731%, but no matter which way I plug in the numbers that are given do I reach...