Get row data for non-matching column values
2
I want to read the file (1600 rows) and get rows only the columns have different values (sno1, sno2, sno3 & sno4-should be not be equal value) and it should be above
50%.The example of output given below
input.txt (tab-delimited)
id sno1 sno2 sno3 sno4
R1 98.4 88.8 98.4 67.6
R2 100 100 100 100
R3 33.4 23.5 98.8 45.5
R4 53.5 78.7 88.8 67.5
R5 0 0 0 0
R6 88.8 98.8 67.6 100
ouput.txt
R4 53.5 78.7 88.8 67.5
R6 88.8 98.8 67.6 100
Here in R4 & R6 rows- all column values have not equal to each other and all are above 50%. Any help in awk/sed/perl is appreciated.
sed awk perl
asked Aug 6 '12 at 21:52
jackjack
1,203102329
add a comment |
2
I want to read the file (1600 rows) and get rows only the columns have different values (sno1, sno2, sno3 & sno4-should be not be equal value) and it should be above
50%.The example of output given below
input.txt (tab-delimited)
id sno1 sno2 sno3 sno4
R1 98.4 88.8 98.4 67.6
R2 100 100 100 100
R3 33.4 23.5 98.8 45.5
R4 53.5 78.7 88.8 67.5
R5 0 0 0 0
R6 88.8 98.8 67.6 100
ouput.txt
R4 53.5 78.7 88.8 67.5
R6 88.8 98.8 67.6 100
Here in R4 & R6 rows- all column values have not equal to each other and all are above 50%. Any help in awk/sed/perl is appreciated.
sed awk perl
asked Aug 6 '12 at 21:52
jackjack
1,203102329
add a comment |
2
2
2
I want to read the file (1600 rows) and get rows only the columns have different values (sno1, sno2, sno3 & sno4-should be not be equal value) and it should be above
50%.The example of output given below
input.txt (tab-delimited)
id sno1 sno2 sno3 sno4
R1 98.4 88.8 98.4 67.6
R2 100 100 100 100
R3 33.4 23.5 98.8 45.5
R4 53.5 78.7 88.8 67.5
R5 0 0 0 0
R6 88.8 98.8 67.6 100
ouput.txt
R4 53.5 78.7 88.8 67.5
R6 88.8 98.8 67.6 100
Here in R4 & R6 rows- all column values have not equal to each other and all are above 50%. Any help in awk/sed/perl is appreciated.
sed awk perl
asked Aug 6 '12 at 21:52
jackjack
1,203102329
I want to read the file (1600 rows) and get rows only the columns have different values (sno1, sno2, sno3 & sno4-should be not be equal value) and it should be above
50%.The example of output given below
input.txt (tab-delimited)
id sno1 sno2 sno3 sno4
R1 98.4 88.8 98.4 67.6
R2 100 100 100 100
R3 33.4 23.5 98.8 45.5
R4 53.5 78.7 88.8 67.5
R5 0 0 0 0
R6 88.8 98.8 67.6 100
ouput.txt
R4 53.5 78.7 88.8 67.5
R6 88.8 98.8 67.6 100
Here in R4 & R6 rows- all column values have not equal to each other and all are above 50%. Any help in awk/sed/perl is appreciated.
sed awk perl
sed awk perl
asked Aug 6 '12 at 21:52
jackjack
1,203102329
asked Aug 6 '12 at 21:52
jackjack
1,203102329
asked Aug 6 '12 at 21:52
jackjack
1,203102329
asked Aug 6 '12 at 21:52
jackjack
1,203102329
asked Aug 6 '12 at 21:52
jackjack
1,203102329
1,203102329
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
3
A perl-oneliner:
perl -nae 'undef %saw ; next if $. == 1; shift @F; next if grep { $_ < 50 or $saw{$_}++ } @F; print ' input.txt
This basically translates to:
#!/usr/bin/env perl
use strict;
while (<>) {
my @F = split(' '); # split the current line
my %seen;
next if $. == 1; # skip the heading
shift @F; # ignore first element
next if grep { $_ < 50 or $seen{$_}++ } @F; # ignore lines with
# duplicate entries and
# entries less than 50
print; # print current line
}
answered Aug 6 '12 at 22:35
Ulrich DangelUlrich Dangel
20.6k25971
add a comment |
2
This might work for you (GNU sed):
sed '1d;/S+ (S+) .* 1/d;/S+ S+ (S+) .* 1/d;/S+ S+ S+ (S+) .* 1/d;/S+( (100|[56789][0-9]..)){4}/!d' file
edited Aug 7 '12 at 20:25
jw013
36.6k7101125
answered Aug 7 '12 at 19:59
potongpotong
23612
wow impressive, care to explain?
– Ulrich Dangel
Aug 7 '12 at 20:04
add a comment |
-1
awk '($2!=$3) &&($2!=$4) && ($2!=$5) && ($3!=$4) &&($3!=$5) &&($4!=$5) && ($2>50) && ($3>50) && ($4>50) && ($5>50) {print $0}' input.txt
edited 1 hour ago
Jeff Schaller
43.1k1159137
answered 1 hour ago
Deepika Reddy BilluriDeepika Reddy Billuri
11
New contributor
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
This answer would be improved with some explanation of what your code block does and how.
– Michael Homer
1 hour ago
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
A perl-oneliner:
perl -nae 'undef %saw ; next if $. == 1; shift @F; next if grep { $_ < 50 or $saw{$_}++ } @F; print ' input.txt
This basically translates to:
#!/usr/bin/env perl
use strict;
while (<>) {
my @F = split(' '); # split the current line
my %seen;
next if $. == 1; # skip the heading
shift @F; # ignore first element
next if grep { $_ < 50 or $seen{$_}++ } @F; # ignore lines with
# duplicate entries and
# entries less than 50
print; # print current line
}
answered Aug 6 '12 at 22:35
Ulrich DangelUlrich Dangel
20.6k25971
add a comment |
3
A perl-oneliner:
perl -nae 'undef %saw ; next if $. == 1; shift @F; next if grep { $_ < 50 or $saw{$_}++ } @F; print ' input.txt
This basically translates to:
#!/usr/bin/env perl
use strict;
while (<>) {
my @F = split(' '); # split the current line
my %seen;
next if $. == 1; # skip the heading
shift @F; # ignore first element
next if grep { $_ < 50 or $seen{$_}++ } @F; # ignore lines with
# duplicate entries and
# entries less than 50
print; # print current line
}
answered Aug 6 '12 at 22:35
Ulrich DangelUlrich Dangel
20.6k25971
add a comment |
3
3
3
A perl-oneliner:
perl -nae 'undef %saw ; next if $. == 1; shift @F; next if grep { $_ < 50 or $saw{$_}++ } @F; print ' input.txt
This basically translates to:
#!/usr/bin/env perl
use strict;
while (<>) {
my @F = split(' '); # split the current line
my %seen;
next if $. == 1; # skip the heading
shift @F; # ignore first element
next if grep { $_ < 50 or $seen{$_}++ } @F; # ignore lines with
# duplicate entries and
# entries less than 50
print; # print current line
}
answered Aug 6 '12 at 22:35
Ulrich DangelUlrich Dangel
20.6k25971
A perl-oneliner:
perl -nae 'undef %saw ; next if $. == 1; shift @F; next if grep { $_ < 50 or $saw{$_}++ } @F; print ' input.txt
This basically translates to:
#!/usr/bin/env perl
use strict;
while (<>) {
my @F = split(' '); # split the current line
my %seen;
next if $. == 1; # skip the heading
shift @F; # ignore first element
next if grep { $_ < 50 or $seen{$_}++ } @F; # ignore lines with
# duplicate entries and
# entries less than 50
print; # print current line
}
answered Aug 6 '12 at 22:35
Ulrich DangelUlrich Dangel
20.6k25971
answered Aug 6 '12 at 22:35
Ulrich DangelUlrich Dangel
20.6k25971
answered Aug 6 '12 at 22:35
Ulrich DangelUlrich Dangel
20.6k25971
answered Aug 6 '12 at 22:35
Ulrich DangelUlrich Dangel
20.6k25971
20.6k25971
add a comment |
add a comment |
2
This might work for you (GNU sed):
sed '1d;/S+ (S+) .* 1/d;/S+ S+ (S+) .* 1/d;/S+ S+ S+ (S+) .* 1/d;/S+( (100|[56789][0-9]..)){4}/!d' file
edited Aug 7 '12 at 20:25
jw013
36.6k7101125
answered Aug 7 '12 at 19:59
potongpotong
23612
wow impressive, care to explain?
– Ulrich Dangel
Aug 7 '12 at 20:04
add a comment |
2
This might work for you (GNU sed):
sed '1d;/S+ (S+) .* 1/d;/S+ S+ (S+) .* 1/d;/S+ S+ S+ (S+) .* 1/d;/S+( (100|[56789][0-9]..)){4}/!d' file
edited Aug 7 '12 at 20:25
jw013
36.6k7101125
answered Aug 7 '12 at 19:59
potongpotong
23612
wow impressive, care to explain?
– Ulrich Dangel
Aug 7 '12 at 20:04
add a comment |
2
2
2
This might work for you (GNU sed):
sed '1d;/S+ (S+) .* 1/d;/S+ S+ (S+) .* 1/d;/S+ S+ S+ (S+) .* 1/d;/S+( (100|[56789][0-9]..)){4}/!d' file
edited Aug 7 '12 at 20:25
jw013
36.6k7101125
answered Aug 7 '12 at 19:59
potongpotong
23612
This might work for you (GNU sed):
sed '1d;/S+ (S+) .* 1/d;/S+ S+ (S+) .* 1/d;/S+ S+ S+ (S+) .* 1/d;/S+( (100|[56789][0-9]..)){4}/!d' file
edited Aug 7 '12 at 20:25
jw013
36.6k7101125
answered Aug 7 '12 at 19:59
potongpotong
23612
edited Aug 7 '12 at 20:25
jw013
36.6k7101125
edited Aug 7 '12 at 20:25
jw013
36.6k7101125
edited Aug 7 '12 at 20:25
jw013
36.6k7101125
36.6k7101125
answered Aug 7 '12 at 19:59
potongpotong
23612
answered Aug 7 '12 at 19:59
potongpotong
23612
answered Aug 7 '12 at 19:59
potongpotong
23612
23612
wow impressive, care to explain?
– Ulrich Dangel
Aug 7 '12 at 20:04
add a comment |
wow impressive, care to explain?
– Ulrich Dangel
Aug 7 '12 at 20:04
wow impressive, care to explain?
– Ulrich Dangel
Aug 7 '12 at 20:04
wow impressive, care to explain?
– Ulrich Dangel
Aug 7 '12 at 20:04
add a comment |
-1
awk '($2!=$3) &&($2!=$4) && ($2!=$5) && ($3!=$4) &&($3!=$5) &&($4!=$5) && ($2>50) && ($3>50) && ($4>50) && ($5>50) {print $0}' input.txt
edited 1 hour ago
Jeff Schaller
43.1k1159137
answered 1 hour ago
Deepika Reddy BilluriDeepika Reddy Billuri
11
New contributor
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
This answer would be improved with some explanation of what your code block does and how.
– Michael Homer
1 hour ago
add a comment |
-1
awk '($2!=$3) &&($2!=$4) && ($2!=$5) && ($3!=$4) &&($3!=$5) &&($4!=$5) && ($2>50) && ($3>50) && ($4>50) && ($5>50) {print $0}' input.txt
edited 1 hour ago
Jeff Schaller
43.1k1159137
answered 1 hour ago
Deepika Reddy BilluriDeepika Reddy Billuri
11
New contributor
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
This answer would be improved with some explanation of what your code block does and how.
– Michael Homer
1 hour ago
add a comment |
-1
-1
-1
awk '($2!=$3) &&($2!=$4) && ($2!=$5) && ($3!=$4) &&($3!=$5) &&($4!=$5) && ($2>50) && ($3>50) && ($4>50) && ($5>50) {print $0}' input.txt
edited 1 hour ago
Jeff Schaller
43.1k1159137
answered 1 hour ago
Deepika Reddy BilluriDeepika Reddy Billuri
11
New contributor
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
awk '($2!=$3) &&($2!=$4) && ($2!=$5) && ($3!=$4) &&($3!=$5) &&($4!=$5) && ($2>50) && ($3>50) && ($4>50) && ($5>50) {print $0}' input.txt
edited 1 hour ago
Jeff Schaller
43.1k1159137
answered 1 hour ago
Deepika Reddy BilluriDeepika Reddy Billuri
11
New contributor
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Jeff Schaller
43.1k1159137
edited 1 hour ago
Jeff Schaller
43.1k1159137
edited 1 hour ago
Jeff Schaller
43.1k1159137
43.1k1159137
answered 1 hour ago
Deepika Reddy BilluriDeepika Reddy Billuri
11
New contributor
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 1 hour ago
Deepika Reddy BilluriDeepika Reddy Billuri
11
answered 1 hour ago
Deepika Reddy BilluriDeepika Reddy Billuri
11
11
New contributor
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Deepika Reddy Billuri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
This answer would be improved with some explanation of what your code block does and how.
– Michael Homer
1 hour ago
add a comment |
This answer would be improved with some explanation of what your code block does and how.
– Michael Homer
1 hour ago
This answer would be improved with some explanation of what your code block does and how.
– Michael Homer
1 hour ago
This answer would be improved with some explanation of what your code block does and how.
– Michael Homer
1 hour ago
add a comment |
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