Arbitrary Dice with Probability
I wrote a script that gives a "generalized" function of an arbitrary dice. Is this any good? How can it improve so to make it cleaner?
import random
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6] #num lists
def inptchacc():
ending_conditions = ['stop','Stop','quit','Quit']
end = False
inpu = input('what number would you like to add to the new face of the Die? (to end the die please type "stop or Stop or quit or Quit to finish the DIE" )')
while end == False:
if not(inpu in ending_conditions):
try:
retr = int(inpu)
return retr
except:
string = 'invalid input please try again'
inpu = input('invalid input please try again ')
else:
stop = 'stop'
return stop
def deeper(IDie):
list =
Adding = True
while Adding:
print('The Die ' + IDie + ' is currently ' + str(list) )
toadd = inptchacc()
if toadd != 'stop':
list.append(toadd)
else:
Adding = False
return list
def chance_overlap(Die1,Die2):
highnumber = 1000
counter = 0
for n in range(highnumber):
x = roll(Die1)
y = roll(Die2)
if x == y:
counter += 1
chance = counter/highnumber
return chance
chance = chance_overlap(Die1,Die2)
print(chance)
Doing = True
while Doing:
try:
IDie1 = deeper('IDie1')
IDie2 = deeper('IDie1')
chance2 = chance_overlap(IDie1,IDie2)
Doing = False
except:
print ('incompatible options selected returning....... ')
print(chance2)
python python-3.x
add a comment |
I wrote a script that gives a "generalized" function of an arbitrary dice. Is this any good? How can it improve so to make it cleaner?
import random
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6] #num lists
def inptchacc():
ending_conditions = ['stop','Stop','quit','Quit']
end = False
inpu = input('what number would you like to add to the new face of the Die? (to end the die please type "stop or Stop or quit or Quit to finish the DIE" )')
while end == False:
if not(inpu in ending_conditions):
try:
retr = int(inpu)
return retr
except:
string = 'invalid input please try again'
inpu = input('invalid input please try again ')
else:
stop = 'stop'
return stop
def deeper(IDie):
list =
Adding = True
while Adding:
print('The Die ' + IDie + ' is currently ' + str(list) )
toadd = inptchacc()
if toadd != 'stop':
list.append(toadd)
else:
Adding = False
return list
def chance_overlap(Die1,Die2):
highnumber = 1000
counter = 0
for n in range(highnumber):
x = roll(Die1)
y = roll(Die2)
if x == y:
counter += 1
chance = counter/highnumber
return chance
chance = chance_overlap(Die1,Die2)
print(chance)
Doing = True
while Doing:
try:
IDie1 = deeper('IDie1')
IDie2 = deeper('IDie1')
chance2 = chance_overlap(IDie1,IDie2)
Doing = False
except:
print ('incompatible options selected returning....... ')
print(chance2)
python python-3.x
What is the overall function of this, just rolling some arbitrary dice? It looks awfully complicated for such a simple task if that's it.
– Mast
4 hours ago
" The assignment deals with a game in which two players both have a set of dice. In the game, each player casts his/her dice and sums the outcomes of the dice. The player with the highest sum wins. If the sums are equal, it's a draw. Usually the dice within one set are equal, but different from the kind of dice in the other set." This is the assignment
– Beginner-Coder123
4 hours ago
As we all want to make our code more efficient or improve it in one way or another, try to write a title that summarizes what your code does, not what you want to get out of a review. Please see How to get the best value out of Code Review - Asking Questions for guidance on writing good question titles.
– BCdotWEB
4 hours ago
1
@Beginner-Coder123: You should add that description to the question body.
– Graipher
3 hours ago
add a comment |
I wrote a script that gives a "generalized" function of an arbitrary dice. Is this any good? How can it improve so to make it cleaner?
import random
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6] #num lists
def inptchacc():
ending_conditions = ['stop','Stop','quit','Quit']
end = False
inpu = input('what number would you like to add to the new face of the Die? (to end the die please type "stop or Stop or quit or Quit to finish the DIE" )')
while end == False:
if not(inpu in ending_conditions):
try:
retr = int(inpu)
return retr
except:
string = 'invalid input please try again'
inpu = input('invalid input please try again ')
else:
stop = 'stop'
return stop
def deeper(IDie):
list =
Adding = True
while Adding:
print('The Die ' + IDie + ' is currently ' + str(list) )
toadd = inptchacc()
if toadd != 'stop':
list.append(toadd)
else:
Adding = False
return list
def chance_overlap(Die1,Die2):
highnumber = 1000
counter = 0
for n in range(highnumber):
x = roll(Die1)
y = roll(Die2)
if x == y:
counter += 1
chance = counter/highnumber
return chance
chance = chance_overlap(Die1,Die2)
print(chance)
Doing = True
while Doing:
try:
IDie1 = deeper('IDie1')
IDie2 = deeper('IDie1')
chance2 = chance_overlap(IDie1,IDie2)
Doing = False
except:
print ('incompatible options selected returning....... ')
print(chance2)
python python-3.x
I wrote a script that gives a "generalized" function of an arbitrary dice. Is this any good? How can it improve so to make it cleaner?
import random
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6] #num lists
def inptchacc():
ending_conditions = ['stop','Stop','quit','Quit']
end = False
inpu = input('what number would you like to add to the new face of the Die? (to end the die please type "stop or Stop or quit or Quit to finish the DIE" )')
while end == False:
if not(inpu in ending_conditions):
try:
retr = int(inpu)
return retr
except:
string = 'invalid input please try again'
inpu = input('invalid input please try again ')
else:
stop = 'stop'
return stop
def deeper(IDie):
list =
Adding = True
while Adding:
print('The Die ' + IDie + ' is currently ' + str(list) )
toadd = inptchacc()
if toadd != 'stop':
list.append(toadd)
else:
Adding = False
return list
def chance_overlap(Die1,Die2):
highnumber = 1000
counter = 0
for n in range(highnumber):
x = roll(Die1)
y = roll(Die2)
if x == y:
counter += 1
chance = counter/highnumber
return chance
chance = chance_overlap(Die1,Die2)
print(chance)
Doing = True
while Doing:
try:
IDie1 = deeper('IDie1')
IDie2 = deeper('IDie1')
chance2 = chance_overlap(IDie1,IDie2)
Doing = False
except:
print ('incompatible options selected returning....... ')
print(chance2)
python python-3.x
python python-3.x
edited 4 hours ago
Beginner-Coder123
asked 4 hours ago
Beginner-Coder123Beginner-Coder123
162
162
What is the overall function of this, just rolling some arbitrary dice? It looks awfully complicated for such a simple task if that's it.
– Mast
4 hours ago
" The assignment deals with a game in which two players both have a set of dice. In the game, each player casts his/her dice and sums the outcomes of the dice. The player with the highest sum wins. If the sums are equal, it's a draw. Usually the dice within one set are equal, but different from the kind of dice in the other set." This is the assignment
– Beginner-Coder123
4 hours ago
As we all want to make our code more efficient or improve it in one way or another, try to write a title that summarizes what your code does, not what you want to get out of a review. Please see How to get the best value out of Code Review - Asking Questions for guidance on writing good question titles.
– BCdotWEB
4 hours ago
1
@Beginner-Coder123: You should add that description to the question body.
– Graipher
3 hours ago
add a comment |
What is the overall function of this, just rolling some arbitrary dice? It looks awfully complicated for such a simple task if that's it.
– Mast
4 hours ago
" The assignment deals with a game in which two players both have a set of dice. In the game, each player casts his/her dice and sums the outcomes of the dice. The player with the highest sum wins. If the sums are equal, it's a draw. Usually the dice within one set are equal, but different from the kind of dice in the other set." This is the assignment
– Beginner-Coder123
4 hours ago
As we all want to make our code more efficient or improve it in one way or another, try to write a title that summarizes what your code does, not what you want to get out of a review. Please see How to get the best value out of Code Review - Asking Questions for guidance on writing good question titles.
– BCdotWEB
4 hours ago
1
@Beginner-Coder123: You should add that description to the question body.
– Graipher
3 hours ago
What is the overall function of this, just rolling some arbitrary dice? It looks awfully complicated for such a simple task if that's it.
– Mast
4 hours ago
What is the overall function of this, just rolling some arbitrary dice? It looks awfully complicated for such a simple task if that's it.
– Mast
4 hours ago
" The assignment deals with a game in which two players both have a set of dice. In the game, each player casts his/her dice and sums the outcomes of the dice. The player with the highest sum wins. If the sums are equal, it's a draw. Usually the dice within one set are equal, but different from the kind of dice in the other set." This is the assignment
– Beginner-Coder123
4 hours ago
" The assignment deals with a game in which two players both have a set of dice. In the game, each player casts his/her dice and sums the outcomes of the dice. The player with the highest sum wins. If the sums are equal, it's a draw. Usually the dice within one set are equal, but different from the kind of dice in the other set." This is the assignment
– Beginner-Coder123
4 hours ago
As we all want to make our code more efficient or improve it in one way or another, try to write a title that summarizes what your code does, not what you want to get out of a review. Please see How to get the best value out of Code Review - Asking Questions for guidance on writing good question titles.
– BCdotWEB
4 hours ago
As we all want to make our code more efficient or improve it in one way or another, try to write a title that summarizes what your code does, not what you want to get out of a review. Please see How to get the best value out of Code Review - Asking Questions for guidance on writing good question titles.
– BCdotWEB
4 hours ago
1
1
@Beginner-Coder123: You should add that description to the question body.
– Graipher
3 hours ago
@Beginner-Coder123: You should add that description to the question body.
– Graipher
3 hours ago
add a comment |
3 Answers
3
active
oldest
votes
The right functions
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Can be:
def roll(die):
return random.choice(die)
inptchacc()
You could instead check only the first character of the input (case insensitive), rather than expecting the whole keyword.
Your return variable stop
isn't needed. Just return directly.
stop = 'stop'
return stop
Should be:
return 'stop'
Likewise elsewhere in your code.
Use __main__
Rather than putting code between functions and also at the end of the file, instead use:
if __name__ == '__main__':
See here for more details.
add a comment |
Since you need to roll many times in the chance_overlap
function, you might want to optimize making n
rolls, using random.choices
(Python 3.6+):
from itertools import groupby
def roll(die, n=1):
if n == 1:
return random.choice(die)
return random.choices(die, k=n)
def all_equal(iterable):
"Returns True if all the elements are equal to each other"
g = groupby(iterable)
return next(g, True) and not next(g, False)
def overlap_chance(*dice, n=1000):
rolls = [roll(die, n) for die in dice]
equal_rolls = sum(all_equal(roll) for roll in zip(*rolls))
return equal_rolls / n
Here I chose to include it in your roll
function, which is nice because you only have on function, but you do have different return types depending on the value of k
, which is not so nice. If you want to you can make it into two separate functions instead.
I made chance_overlap
take a variable number of dice so it even works for more than two (and also for one, which is a bit boring).
In addition, I followed Python's official style-guide, PEP8 for variable names (lower_case
).
The all_equal
function is directly taken from the itertools
recipes.
add a comment |
Make the computer count
These:
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6]
should be
die1 = list(range(1, 5))
die2 = list(range(1, 7))
Only compare once
This list:
ending_conditions = ['stop','Stop','quit','Quit']
has two problems. First, don't store multiple cases for one word - just store lower (or upper) case - I prefer lower, because no shouting.
Also, it shouldn't be a list. It's getting tested for membership, so make it a set. In other words,
ending_conditions = {'stop', 'quiet'}
then for use, write "not in", instead of "not x in"; i.e.
if inpu.lower() not in ending_conditions:
PEP8
Run your code through a linter. It will catch several things, including
- Don't capitalize your variables (
Die1
,Die2
,Adding
,Doing
) if they're local. If they're global constants, they need to be all-uppercase. In the case ofDie*
, they probably shouldn't be global at all. - Add a couple of newlines after your
import
s
Grammar
Write:
print('Incompatible options selected. Returning...')
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The right functions
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Can be:
def roll(die):
return random.choice(die)
inptchacc()
You could instead check only the first character of the input (case insensitive), rather than expecting the whole keyword.
Your return variable stop
isn't needed. Just return directly.
stop = 'stop'
return stop
Should be:
return 'stop'
Likewise elsewhere in your code.
Use __main__
Rather than putting code between functions and also at the end of the file, instead use:
if __name__ == '__main__':
See here for more details.
add a comment |
The right functions
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Can be:
def roll(die):
return random.choice(die)
inptchacc()
You could instead check only the first character of the input (case insensitive), rather than expecting the whole keyword.
Your return variable stop
isn't needed. Just return directly.
stop = 'stop'
return stop
Should be:
return 'stop'
Likewise elsewhere in your code.
Use __main__
Rather than putting code between functions and also at the end of the file, instead use:
if __name__ == '__main__':
See here for more details.
add a comment |
The right functions
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Can be:
def roll(die):
return random.choice(die)
inptchacc()
You could instead check only the first character of the input (case insensitive), rather than expecting the whole keyword.
Your return variable stop
isn't needed. Just return directly.
stop = 'stop'
return stop
Should be:
return 'stop'
Likewise elsewhere in your code.
Use __main__
Rather than putting code between functions and also at the end of the file, instead use:
if __name__ == '__main__':
See here for more details.
The right functions
def roll(die):
number = random.randint(0,len(die)-1)
b = die[number]
return b
Can be:
def roll(die):
return random.choice(die)
inptchacc()
You could instead check only the first character of the input (case insensitive), rather than expecting the whole keyword.
Your return variable stop
isn't needed. Just return directly.
stop = 'stop'
return stop
Should be:
return 'stop'
Likewise elsewhere in your code.
Use __main__
Rather than putting code between functions and also at the end of the file, instead use:
if __name__ == '__main__':
See here for more details.
answered 2 hours ago
esoteesote
1,9891933
1,9891933
add a comment |
add a comment |
Since you need to roll many times in the chance_overlap
function, you might want to optimize making n
rolls, using random.choices
(Python 3.6+):
from itertools import groupby
def roll(die, n=1):
if n == 1:
return random.choice(die)
return random.choices(die, k=n)
def all_equal(iterable):
"Returns True if all the elements are equal to each other"
g = groupby(iterable)
return next(g, True) and not next(g, False)
def overlap_chance(*dice, n=1000):
rolls = [roll(die, n) for die in dice]
equal_rolls = sum(all_equal(roll) for roll in zip(*rolls))
return equal_rolls / n
Here I chose to include it in your roll
function, which is nice because you only have on function, but you do have different return types depending on the value of k
, which is not so nice. If you want to you can make it into two separate functions instead.
I made chance_overlap
take a variable number of dice so it even works for more than two (and also for one, which is a bit boring).
In addition, I followed Python's official style-guide, PEP8 for variable names (lower_case
).
The all_equal
function is directly taken from the itertools
recipes.
add a comment |
Since you need to roll many times in the chance_overlap
function, you might want to optimize making n
rolls, using random.choices
(Python 3.6+):
from itertools import groupby
def roll(die, n=1):
if n == 1:
return random.choice(die)
return random.choices(die, k=n)
def all_equal(iterable):
"Returns True if all the elements are equal to each other"
g = groupby(iterable)
return next(g, True) and not next(g, False)
def overlap_chance(*dice, n=1000):
rolls = [roll(die, n) for die in dice]
equal_rolls = sum(all_equal(roll) for roll in zip(*rolls))
return equal_rolls / n
Here I chose to include it in your roll
function, which is nice because you only have on function, but you do have different return types depending on the value of k
, which is not so nice. If you want to you can make it into two separate functions instead.
I made chance_overlap
take a variable number of dice so it even works for more than two (and also for one, which is a bit boring).
In addition, I followed Python's official style-guide, PEP8 for variable names (lower_case
).
The all_equal
function is directly taken from the itertools
recipes.
add a comment |
Since you need to roll many times in the chance_overlap
function, you might want to optimize making n
rolls, using random.choices
(Python 3.6+):
from itertools import groupby
def roll(die, n=1):
if n == 1:
return random.choice(die)
return random.choices(die, k=n)
def all_equal(iterable):
"Returns True if all the elements are equal to each other"
g = groupby(iterable)
return next(g, True) and not next(g, False)
def overlap_chance(*dice, n=1000):
rolls = [roll(die, n) for die in dice]
equal_rolls = sum(all_equal(roll) for roll in zip(*rolls))
return equal_rolls / n
Here I chose to include it in your roll
function, which is nice because you only have on function, but you do have different return types depending on the value of k
, which is not so nice. If you want to you can make it into two separate functions instead.
I made chance_overlap
take a variable number of dice so it even works for more than two (and also for one, which is a bit boring).
In addition, I followed Python's official style-guide, PEP8 for variable names (lower_case
).
The all_equal
function is directly taken from the itertools
recipes.
Since you need to roll many times in the chance_overlap
function, you might want to optimize making n
rolls, using random.choices
(Python 3.6+):
from itertools import groupby
def roll(die, n=1):
if n == 1:
return random.choice(die)
return random.choices(die, k=n)
def all_equal(iterable):
"Returns True if all the elements are equal to each other"
g = groupby(iterable)
return next(g, True) and not next(g, False)
def overlap_chance(*dice, n=1000):
rolls = [roll(die, n) for die in dice]
equal_rolls = sum(all_equal(roll) for roll in zip(*rolls))
return equal_rolls / n
Here I chose to include it in your roll
function, which is nice because you only have on function, but you do have different return types depending on the value of k
, which is not so nice. If you want to you can make it into two separate functions instead.
I made chance_overlap
take a variable number of dice so it even works for more than two (and also for one, which is a bit boring).
In addition, I followed Python's official style-guide, PEP8 for variable names (lower_case
).
The all_equal
function is directly taken from the itertools
recipes.
answered 50 mins ago
GraipherGraipher
23.6k53585
23.6k53585
add a comment |
add a comment |
Make the computer count
These:
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6]
should be
die1 = list(range(1, 5))
die2 = list(range(1, 7))
Only compare once
This list:
ending_conditions = ['stop','Stop','quit','Quit']
has two problems. First, don't store multiple cases for one word - just store lower (or upper) case - I prefer lower, because no shouting.
Also, it shouldn't be a list. It's getting tested for membership, so make it a set. In other words,
ending_conditions = {'stop', 'quiet'}
then for use, write "not in", instead of "not x in"; i.e.
if inpu.lower() not in ending_conditions:
PEP8
Run your code through a linter. It will catch several things, including
- Don't capitalize your variables (
Die1
,Die2
,Adding
,Doing
) if they're local. If they're global constants, they need to be all-uppercase. In the case ofDie*
, they probably shouldn't be global at all. - Add a couple of newlines after your
import
s
Grammar
Write:
print('Incompatible options selected. Returning...')
add a comment |
Make the computer count
These:
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6]
should be
die1 = list(range(1, 5))
die2 = list(range(1, 7))
Only compare once
This list:
ending_conditions = ['stop','Stop','quit','Quit']
has two problems. First, don't store multiple cases for one word - just store lower (or upper) case - I prefer lower, because no shouting.
Also, it shouldn't be a list. It's getting tested for membership, so make it a set. In other words,
ending_conditions = {'stop', 'quiet'}
then for use, write "not in", instead of "not x in"; i.e.
if inpu.lower() not in ending_conditions:
PEP8
Run your code through a linter. It will catch several things, including
- Don't capitalize your variables (
Die1
,Die2
,Adding
,Doing
) if they're local. If they're global constants, they need to be all-uppercase. In the case ofDie*
, they probably shouldn't be global at all. - Add a couple of newlines after your
import
s
Grammar
Write:
print('Incompatible options selected. Returning...')
add a comment |
Make the computer count
These:
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6]
should be
die1 = list(range(1, 5))
die2 = list(range(1, 7))
Only compare once
This list:
ending_conditions = ['stop','Stop','quit','Quit']
has two problems. First, don't store multiple cases for one word - just store lower (or upper) case - I prefer lower, because no shouting.
Also, it shouldn't be a list. It's getting tested for membership, so make it a set. In other words,
ending_conditions = {'stop', 'quiet'}
then for use, write "not in", instead of "not x in"; i.e.
if inpu.lower() not in ending_conditions:
PEP8
Run your code through a linter. It will catch several things, including
- Don't capitalize your variables (
Die1
,Die2
,Adding
,Doing
) if they're local. If they're global constants, they need to be all-uppercase. In the case ofDie*
, they probably shouldn't be global at all. - Add a couple of newlines after your
import
s
Grammar
Write:
print('Incompatible options selected. Returning...')
Make the computer count
These:
Die1 = [1,2,3,4]
Die2 = [1,2,3,4,5,6]
should be
die1 = list(range(1, 5))
die2 = list(range(1, 7))
Only compare once
This list:
ending_conditions = ['stop','Stop','quit','Quit']
has two problems. First, don't store multiple cases for one word - just store lower (or upper) case - I prefer lower, because no shouting.
Also, it shouldn't be a list. It's getting tested for membership, so make it a set. In other words,
ending_conditions = {'stop', 'quiet'}
then for use, write "not in", instead of "not x in"; i.e.
if inpu.lower() not in ending_conditions:
PEP8
Run your code through a linter. It will catch several things, including
- Don't capitalize your variables (
Die1
,Die2
,Adding
,Doing
) if they're local. If they're global constants, they need to be all-uppercase. In the case ofDie*
, they probably shouldn't be global at all. - Add a couple of newlines after your
import
s
Grammar
Write:
print('Incompatible options selected. Returning...')
answered 53 mins ago
ReinderienReinderien
3,977821
3,977821
add a comment |
add a comment |
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What is the overall function of this, just rolling some arbitrary dice? It looks awfully complicated for such a simple task if that's it.
– Mast
4 hours ago
" The assignment deals with a game in which two players both have a set of dice. In the game, each player casts his/her dice and sums the outcomes of the dice. The player with the highest sum wins. If the sums are equal, it's a draw. Usually the dice within one set are equal, but different from the kind of dice in the other set." This is the assignment
– Beginner-Coder123
4 hours ago
As we all want to make our code more efficient or improve it in one way or another, try to write a title that summarizes what your code does, not what you want to get out of a review. Please see How to get the best value out of Code Review - Asking Questions for guidance on writing good question titles.
– BCdotWEB
4 hours ago
1
@Beginner-Coder123: You should add that description to the question body.
– Graipher
3 hours ago