Simple-looking horrifyingly difficult (to me) resistance circuits
I'm doing some physics homework calculating the total resistance between points A and B and while some circuits are comprehensible, there are two that I can't understand how they work at all.
So, it is my pleasure to present to you these two monstrosities:
How do I approach the crossing resistances in each one? Here's where I am as of writing this post:
THE DIVIDED SQUARE:
- The two 10k resistances are parallel to each other
- The 20k and 9k resistances are parallel to each other
- I don't know what to do with the 5k one
THE HELLBORN TRIANGLES OF DEATH:
- The first and last pair of 5k resistances are parallel to each other
- The bottom center 5k resistance is in series with the previous two couples
- I don't know what to do with the 15k ones
So, long story short, how should I approach the problem when the resistances are connected by both sides and the circuit looks like the voltage should converge inside them and start burning?
homework-and-exercises electric-circuits electrical-resistance
New contributor
add a comment |
I'm doing some physics homework calculating the total resistance between points A and B and while some circuits are comprehensible, there are two that I can't understand how they work at all.
So, it is my pleasure to present to you these two monstrosities:
How do I approach the crossing resistances in each one? Here's where I am as of writing this post:
THE DIVIDED SQUARE:
- The two 10k resistances are parallel to each other
- The 20k and 9k resistances are parallel to each other
- I don't know what to do with the 5k one
THE HELLBORN TRIANGLES OF DEATH:
- The first and last pair of 5k resistances are parallel to each other
- The bottom center 5k resistance is in series with the previous two couples
- I don't know what to do with the 15k ones
So, long story short, how should I approach the problem when the resistances are connected by both sides and the circuit looks like the voltage should converge inside them and start burning?
homework-and-exercises electric-circuits electrical-resistance
New contributor
1
Do you ever tried also to take in consideration the Y-$Delta$ transformations? (en.wikipedia.org/wiki/Y-%CE%94_transform) they are useful whenever you reach a triangle-like or a delta like group, like in your case...
– Pietro Oliva
1 hour ago
I haven't been taught that transformation. Could you elaborate a bit on it or send me a link please? Oooooh I can see it now. Thanks for the link! You saved my degree :p
– Groctel
1 hour ago
1
Have you tried redrawing the diagrams? You'd be surprised how helpful it can be to draw them in the way your brain wants to see them :)
– N. Steinle
1 hour ago
yes @N.Steinle is right, sometimes is just a matter of drawing them in order. I personally use the transformations Y-$Delta$ (that in Italy are just called "triangle-star")seldomly while i prefere to re-draw like Steinle said. But in some cases that transformations are really time-saving!
– Pietro Oliva
1 hour ago
add a comment |
I'm doing some physics homework calculating the total resistance between points A and B and while some circuits are comprehensible, there are two that I can't understand how they work at all.
So, it is my pleasure to present to you these two monstrosities:
How do I approach the crossing resistances in each one? Here's where I am as of writing this post:
THE DIVIDED SQUARE:
- The two 10k resistances are parallel to each other
- The 20k and 9k resistances are parallel to each other
- I don't know what to do with the 5k one
THE HELLBORN TRIANGLES OF DEATH:
- The first and last pair of 5k resistances are parallel to each other
- The bottom center 5k resistance is in series with the previous two couples
- I don't know what to do with the 15k ones
So, long story short, how should I approach the problem when the resistances are connected by both sides and the circuit looks like the voltage should converge inside them and start burning?
homework-and-exercises electric-circuits electrical-resistance
New contributor
I'm doing some physics homework calculating the total resistance between points A and B and while some circuits are comprehensible, there are two that I can't understand how they work at all.
So, it is my pleasure to present to you these two monstrosities:
How do I approach the crossing resistances in each one? Here's where I am as of writing this post:
THE DIVIDED SQUARE:
- The two 10k resistances are parallel to each other
- The 20k and 9k resistances are parallel to each other
- I don't know what to do with the 5k one
THE HELLBORN TRIANGLES OF DEATH:
- The first and last pair of 5k resistances are parallel to each other
- The bottom center 5k resistance is in series with the previous two couples
- I don't know what to do with the 15k ones
So, long story short, how should I approach the problem when the resistances are connected by both sides and the circuit looks like the voltage should converge inside them and start burning?
homework-and-exercises electric-circuits electrical-resistance
homework-and-exercises electric-circuits electrical-resistance
New contributor
New contributor
edited 1 hour ago
G. Smith
4,7871020
4,7871020
New contributor
asked 1 hour ago
GroctelGroctel
435
435
New contributor
New contributor
1
Do you ever tried also to take in consideration the Y-$Delta$ transformations? (en.wikipedia.org/wiki/Y-%CE%94_transform) they are useful whenever you reach a triangle-like or a delta like group, like in your case...
– Pietro Oliva
1 hour ago
I haven't been taught that transformation. Could you elaborate a bit on it or send me a link please? Oooooh I can see it now. Thanks for the link! You saved my degree :p
– Groctel
1 hour ago
1
Have you tried redrawing the diagrams? You'd be surprised how helpful it can be to draw them in the way your brain wants to see them :)
– N. Steinle
1 hour ago
yes @N.Steinle is right, sometimes is just a matter of drawing them in order. I personally use the transformations Y-$Delta$ (that in Italy are just called "triangle-star")seldomly while i prefere to re-draw like Steinle said. But in some cases that transformations are really time-saving!
– Pietro Oliva
1 hour ago
add a comment |
1
Do you ever tried also to take in consideration the Y-$Delta$ transformations? (en.wikipedia.org/wiki/Y-%CE%94_transform) they are useful whenever you reach a triangle-like or a delta like group, like in your case...
– Pietro Oliva
1 hour ago
I haven't been taught that transformation. Could you elaborate a bit on it or send me a link please? Oooooh I can see it now. Thanks for the link! You saved my degree :p
– Groctel
1 hour ago
1
Have you tried redrawing the diagrams? You'd be surprised how helpful it can be to draw them in the way your brain wants to see them :)
– N. Steinle
1 hour ago
yes @N.Steinle is right, sometimes is just a matter of drawing them in order. I personally use the transformations Y-$Delta$ (that in Italy are just called "triangle-star")seldomly while i prefere to re-draw like Steinle said. But in some cases that transformations are really time-saving!
– Pietro Oliva
1 hour ago
1
1
Do you ever tried also to take in consideration the Y-$Delta$ transformations? (en.wikipedia.org/wiki/Y-%CE%94_transform) they are useful whenever you reach a triangle-like or a delta like group, like in your case...
– Pietro Oliva
1 hour ago
Do you ever tried also to take in consideration the Y-$Delta$ transformations? (en.wikipedia.org/wiki/Y-%CE%94_transform) they are useful whenever you reach a triangle-like or a delta like group, like in your case...
– Pietro Oliva
1 hour ago
I haven't been taught that transformation. Could you elaborate a bit on it or send me a link please? Oooooh I can see it now. Thanks for the link! You saved my degree :p
– Groctel
1 hour ago
I haven't been taught that transformation. Could you elaborate a bit on it or send me a link please? Oooooh I can see it now. Thanks for the link! You saved my degree :p
– Groctel
1 hour ago
1
1
Have you tried redrawing the diagrams? You'd be surprised how helpful it can be to draw them in the way your brain wants to see them :)
– N. Steinle
1 hour ago
Have you tried redrawing the diagrams? You'd be surprised how helpful it can be to draw them in the way your brain wants to see them :)
– N. Steinle
1 hour ago
yes @N.Steinle is right, sometimes is just a matter of drawing them in order. I personally use the transformations Y-$Delta$ (that in Italy are just called "triangle-star")seldomly while i prefere to re-draw like Steinle said. But in some cases that transformations are really time-saving!
– Pietro Oliva
1 hour ago
yes @N.Steinle is right, sometimes is just a matter of drawing them in order. I personally use the transformations Y-$Delta$ (that in Italy are just called "triangle-star")seldomly while i prefere to re-draw like Steinle said. But in some cases that transformations are really time-saving!
– Pietro Oliva
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
Try then to apply the Y-$Delta$ tranformations! I am glad you found the light! If you cannot carry calculation drop again here a line and i'll try to work more on the answer!
New contributor
add a comment |
As Pietro Oliva (is there a way to mention a user?) pointed out, I have to use the Y-Δ transformations to change how the circuit is viewed.
Thanks for the super fast answer!
New contributor
I doubt that your teacher expects you to know about this obscure transformation. You should be able to solve both problems just by using Kirchoff’s circuit laws.
– G. Smith
1 hour ago
I've only studied Kirchoff's laws for voltage and intensity. How do I apply them in this type of circuit?
– Groctel
1 hour ago
1
Assign an unknown current ($I_1$, $I_2$, etc.) to each wire. Write down Kirchoff’s equations for each node and each loop. Solve for all the currents.
– G. Smith
1 hour ago
add a comment |
For the top one, you can separate out the $9 kOmega$ resistor at the top, since it's in series with the rest. Now you have a graph with four nodes and five edges. You can assign the variables $V_1$ through $V_4$ to the nodes, but WLOG you can consider the top node to be 0 and the bottom to be 1, so that leaves just the left and right voltages. You then have currents $I_1$ through $I_5$ through the edges. You can then start applying the circuit laws to these variables: for each edge, the current is equal to change in voltage divided by the resistance. The net current through each edge is zero (if you take current flowing in to be positive and current flowing out to be negative, that is). You'll then get a bunch of equations, and solving them will give the effective resistances.
It's probably best to work out what the effective resistances are from basic principles and algebra first, and then try to work through applying Y-Δ to get a sense of how that works.
Also, any symmetry in the diagram should be preserved in the values. The second circuit has left-right symmetries, so the currents should be symmetrical: the two top resistors should have the same currents as each other, the two outsides diagonal resistors should have the same as each other, and the two inside diagonal should have the same as each other. So you can use just four variables to represent the nine different currents.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try then to apply the Y-$Delta$ tranformations! I am glad you found the light! If you cannot carry calculation drop again here a line and i'll try to work more on the answer!
New contributor
add a comment |
Try then to apply the Y-$Delta$ tranformations! I am glad you found the light! If you cannot carry calculation drop again here a line and i'll try to work more on the answer!
New contributor
add a comment |
Try then to apply the Y-$Delta$ tranformations! I am glad you found the light! If you cannot carry calculation drop again here a line and i'll try to work more on the answer!
New contributor
Try then to apply the Y-$Delta$ tranformations! I am glad you found the light! If you cannot carry calculation drop again here a line and i'll try to work more on the answer!
New contributor
New contributor
answered 1 hour ago
Pietro OlivaPietro Oliva
1137
1137
New contributor
New contributor
add a comment |
add a comment |
As Pietro Oliva (is there a way to mention a user?) pointed out, I have to use the Y-Δ transformations to change how the circuit is viewed.
Thanks for the super fast answer!
New contributor
I doubt that your teacher expects you to know about this obscure transformation. You should be able to solve both problems just by using Kirchoff’s circuit laws.
– G. Smith
1 hour ago
I've only studied Kirchoff's laws for voltage and intensity. How do I apply them in this type of circuit?
– Groctel
1 hour ago
1
Assign an unknown current ($I_1$, $I_2$, etc.) to each wire. Write down Kirchoff’s equations for each node and each loop. Solve for all the currents.
– G. Smith
1 hour ago
add a comment |
As Pietro Oliva (is there a way to mention a user?) pointed out, I have to use the Y-Δ transformations to change how the circuit is viewed.
Thanks for the super fast answer!
New contributor
I doubt that your teacher expects you to know about this obscure transformation. You should be able to solve both problems just by using Kirchoff’s circuit laws.
– G. Smith
1 hour ago
I've only studied Kirchoff's laws for voltage and intensity. How do I apply them in this type of circuit?
– Groctel
1 hour ago
1
Assign an unknown current ($I_1$, $I_2$, etc.) to each wire. Write down Kirchoff’s equations for each node and each loop. Solve for all the currents.
– G. Smith
1 hour ago
add a comment |
As Pietro Oliva (is there a way to mention a user?) pointed out, I have to use the Y-Δ transformations to change how the circuit is viewed.
Thanks for the super fast answer!
New contributor
As Pietro Oliva (is there a way to mention a user?) pointed out, I have to use the Y-Δ transformations to change how the circuit is viewed.
Thanks for the super fast answer!
New contributor
New contributor
answered 1 hour ago
GroctelGroctel
435
435
New contributor
New contributor
I doubt that your teacher expects you to know about this obscure transformation. You should be able to solve both problems just by using Kirchoff’s circuit laws.
– G. Smith
1 hour ago
I've only studied Kirchoff's laws for voltage and intensity. How do I apply them in this type of circuit?
– Groctel
1 hour ago
1
Assign an unknown current ($I_1$, $I_2$, etc.) to each wire. Write down Kirchoff’s equations for each node and each loop. Solve for all the currents.
– G. Smith
1 hour ago
add a comment |
I doubt that your teacher expects you to know about this obscure transformation. You should be able to solve both problems just by using Kirchoff’s circuit laws.
– G. Smith
1 hour ago
I've only studied Kirchoff's laws for voltage and intensity. How do I apply them in this type of circuit?
– Groctel
1 hour ago
1
Assign an unknown current ($I_1$, $I_2$, etc.) to each wire. Write down Kirchoff’s equations for each node and each loop. Solve for all the currents.
– G. Smith
1 hour ago
I doubt that your teacher expects you to know about this obscure transformation. You should be able to solve both problems just by using Kirchoff’s circuit laws.
– G. Smith
1 hour ago
I doubt that your teacher expects you to know about this obscure transformation. You should be able to solve both problems just by using Kirchoff’s circuit laws.
– G. Smith
1 hour ago
I've only studied Kirchoff's laws for voltage and intensity. How do I apply them in this type of circuit?
– Groctel
1 hour ago
I've only studied Kirchoff's laws for voltage and intensity. How do I apply them in this type of circuit?
– Groctel
1 hour ago
1
1
Assign an unknown current ($I_1$, $I_2$, etc.) to each wire. Write down Kirchoff’s equations for each node and each loop. Solve for all the currents.
– G. Smith
1 hour ago
Assign an unknown current ($I_1$, $I_2$, etc.) to each wire. Write down Kirchoff’s equations for each node and each loop. Solve for all the currents.
– G. Smith
1 hour ago
add a comment |
For the top one, you can separate out the $9 kOmega$ resistor at the top, since it's in series with the rest. Now you have a graph with four nodes and five edges. You can assign the variables $V_1$ through $V_4$ to the nodes, but WLOG you can consider the top node to be 0 and the bottom to be 1, so that leaves just the left and right voltages. You then have currents $I_1$ through $I_5$ through the edges. You can then start applying the circuit laws to these variables: for each edge, the current is equal to change in voltage divided by the resistance. The net current through each edge is zero (if you take current flowing in to be positive and current flowing out to be negative, that is). You'll then get a bunch of equations, and solving them will give the effective resistances.
It's probably best to work out what the effective resistances are from basic principles and algebra first, and then try to work through applying Y-Δ to get a sense of how that works.
Also, any symmetry in the diagram should be preserved in the values. The second circuit has left-right symmetries, so the currents should be symmetrical: the two top resistors should have the same currents as each other, the two outsides diagonal resistors should have the same as each other, and the two inside diagonal should have the same as each other. So you can use just four variables to represent the nine different currents.
add a comment |
For the top one, you can separate out the $9 kOmega$ resistor at the top, since it's in series with the rest. Now you have a graph with four nodes and five edges. You can assign the variables $V_1$ through $V_4$ to the nodes, but WLOG you can consider the top node to be 0 and the bottom to be 1, so that leaves just the left and right voltages. You then have currents $I_1$ through $I_5$ through the edges. You can then start applying the circuit laws to these variables: for each edge, the current is equal to change in voltage divided by the resistance. The net current through each edge is zero (if you take current flowing in to be positive and current flowing out to be negative, that is). You'll then get a bunch of equations, and solving them will give the effective resistances.
It's probably best to work out what the effective resistances are from basic principles and algebra first, and then try to work through applying Y-Δ to get a sense of how that works.
Also, any symmetry in the diagram should be preserved in the values. The second circuit has left-right symmetries, so the currents should be symmetrical: the two top resistors should have the same currents as each other, the two outsides diagonal resistors should have the same as each other, and the two inside diagonal should have the same as each other. So you can use just four variables to represent the nine different currents.
add a comment |
For the top one, you can separate out the $9 kOmega$ resistor at the top, since it's in series with the rest. Now you have a graph with four nodes and five edges. You can assign the variables $V_1$ through $V_4$ to the nodes, but WLOG you can consider the top node to be 0 and the bottom to be 1, so that leaves just the left and right voltages. You then have currents $I_1$ through $I_5$ through the edges. You can then start applying the circuit laws to these variables: for each edge, the current is equal to change in voltage divided by the resistance. The net current through each edge is zero (if you take current flowing in to be positive and current flowing out to be negative, that is). You'll then get a bunch of equations, and solving them will give the effective resistances.
It's probably best to work out what the effective resistances are from basic principles and algebra first, and then try to work through applying Y-Δ to get a sense of how that works.
Also, any symmetry in the diagram should be preserved in the values. The second circuit has left-right symmetries, so the currents should be symmetrical: the two top resistors should have the same currents as each other, the two outsides diagonal resistors should have the same as each other, and the two inside diagonal should have the same as each other. So you can use just four variables to represent the nine different currents.
For the top one, you can separate out the $9 kOmega$ resistor at the top, since it's in series with the rest. Now you have a graph with four nodes and five edges. You can assign the variables $V_1$ through $V_4$ to the nodes, but WLOG you can consider the top node to be 0 and the bottom to be 1, so that leaves just the left and right voltages. You then have currents $I_1$ through $I_5$ through the edges. You can then start applying the circuit laws to these variables: for each edge, the current is equal to change in voltage divided by the resistance. The net current through each edge is zero (if you take current flowing in to be positive and current flowing out to be negative, that is). You'll then get a bunch of equations, and solving them will give the effective resistances.
It's probably best to work out what the effective resistances are from basic principles and algebra first, and then try to work through applying Y-Δ to get a sense of how that works.
Also, any symmetry in the diagram should be preserved in the values. The second circuit has left-right symmetries, so the currents should be symmetrical: the two top resistors should have the same currents as each other, the two outsides diagonal resistors should have the same as each other, and the two inside diagonal should have the same as each other. So you can use just four variables to represent the nine different currents.
answered 33 mins ago
AcccumulationAcccumulation
1,856210
1,856210
add a comment |
add a comment |
Groctel is a new contributor. Be nice, and check out our Code of Conduct.
Groctel is a new contributor. Be nice, and check out our Code of Conduct.
Groctel is a new contributor. Be nice, and check out our Code of Conduct.
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1
Do you ever tried also to take in consideration the Y-$Delta$ transformations? (en.wikipedia.org/wiki/Y-%CE%94_transform) they are useful whenever you reach a triangle-like or a delta like group, like in your case...
– Pietro Oliva
1 hour ago
I haven't been taught that transformation. Could you elaborate a bit on it or send me a link please? Oooooh I can see it now. Thanks for the link! You saved my degree :p
– Groctel
1 hour ago
1
Have you tried redrawing the diagrams? You'd be surprised how helpful it can be to draw them in the way your brain wants to see them :)
– N. Steinle
1 hour ago
yes @N.Steinle is right, sometimes is just a matter of drawing them in order. I personally use the transformations Y-$Delta$ (that in Italy are just called "triangle-star")seldomly while i prefere to re-draw like Steinle said. But in some cases that transformations are really time-saving!
– Pietro Oliva
1 hour ago