Bash Script Wind Chill using getopt and bc
Thanks to Fox I am now getting the correct output, however it is not scaling to only 3 places. Anyone know how to do that?
function windchill {
to=32
v=10
vel=`echo 'e(l('$v')*0.16)' | bc -l`
w=$(echo "scale=3; $vel" | bc -l)
twc=`echo "35.74 + (0.6215 * $to) - (35.75 * $w) + (0.4275 * $to * $w)" | bc`
echo ''
echo 'Windchill Calculator'
echo 'Outside Air Temperature (F): '"$to"
echo 'Wind Speed: '"$v"
echo 'Wind-Chill (F): '"$twc"
echo ''
exit
}
I am getting the correct $tf and $v the $wc is my problem. Using a calculator I get the correct answer just not in my bash file. The problem is my $w is coming back as a 1 not 1.4454.
The next area is the getopt to my case switch and the values aren't being passed from the input to the function
ARGS=$(getopt -o "chqv" -l "airtemp=$temp::,velocity=$speed::,cout:,cin:,file=$filename:,help,quiet:,version" -- "$@")
eval set -- "$ARGS"
# handle options
while true; do
case "$1" in
--airtemp=$temp)
temp=$temp
windchill
shift;;
--velocity=$speed)
speed=$speed
windchill
shift;;
-c | --cout)
cout
shift;;
--cin)
cin
shift;;
--file=$filename)
file
shift;;
-h | --help)
help
exit;;
-q | --quiet)
quiet
shift;;
-v | --version)
version
exit;;
*)
echo "Illegal Input"
exit
esac
done
exit
bash bc getopts
asked 2 hours ago
Trinity ZamrzlaTrinity Zamrzla
295
add a comment |
Thanks to Fox I am now getting the correct output, however it is not scaling to only 3 places. Anyone know how to do that?
function windchill {
to=32
v=10
vel=`echo 'e(l('$v')*0.16)' | bc -l`
w=$(echo "scale=3; $vel" | bc -l)
twc=`echo "35.74 + (0.6215 * $to) - (35.75 * $w) + (0.4275 * $to * $w)" | bc`
echo ''
echo 'Windchill Calculator'
echo 'Outside Air Temperature (F): '"$to"
echo 'Wind Speed: '"$v"
echo 'Wind-Chill (F): '"$twc"
echo ''
exit
}
I am getting the correct $tf and $v the $wc is my problem. Using a calculator I get the correct answer just not in my bash file. The problem is my $w is coming back as a 1 not 1.4454.
The next area is the getopt to my case switch and the values aren't being passed from the input to the function
ARGS=$(getopt -o "chqv" -l "airtemp=$temp::,velocity=$speed::,cout:,cin:,file=$filename:,help,quiet:,version" -- "$@")
eval set -- "$ARGS"
# handle options
while true; do
case "$1" in
--airtemp=$temp)
temp=$temp
windchill
shift;;
--velocity=$speed)
speed=$speed
windchill
shift;;
-c | --cout)
cout
shift;;
--cin)
cin
shift;;
--file=$filename)
file
shift;;
-h | --help)
help
exit;;
-q | --quiet)
quiet
shift;;
-v | --version)
version
exit;;
*)
echo "Illegal Input"
exit
esac
done
exit
bash bc getopts
asked 2 hours ago
Trinity ZamrzlaTrinity Zamrzla
295
I don't quite nee why you callwindchillinside the option parsing loop, ofter settingspeedandtemp. Wouldn't you want to set all parameters and then callwindchillafter the loop?
– Kusalananda
1 hour ago
I was under the impression that the shift means it would check the first one and then shift to the next one. I completely guessing on how to do this. My professor gave me a web site and said figure it out. linuxaria.com/howto/… this is what he gave us as a reference
– Trinity Zamrzla
1 hour ago
add a comment |
Thanks to Fox I am now getting the correct output, however it is not scaling to only 3 places. Anyone know how to do that?
function windchill {
to=32
v=10
vel=`echo 'e(l('$v')*0.16)' | bc -l`
w=$(echo "scale=3; $vel" | bc -l)
twc=`echo "35.74 + (0.6215 * $to) - (35.75 * $w) + (0.4275 * $to * $w)" | bc`
echo ''
echo 'Windchill Calculator'
echo 'Outside Air Temperature (F): '"$to"
echo 'Wind Speed: '"$v"
echo 'Wind-Chill (F): '"$twc"
echo ''
exit
}
I am getting the correct $tf and $v the $wc is my problem. Using a calculator I get the correct answer just not in my bash file. The problem is my $w is coming back as a 1 not 1.4454.
The next area is the getopt to my case switch and the values aren't being passed from the input to the function
ARGS=$(getopt -o "chqv" -l "airtemp=$temp::,velocity=$speed::,cout:,cin:,file=$filename:,help,quiet:,version" -- "$@")
eval set -- "$ARGS"
# handle options
while true; do
case "$1" in
--airtemp=$temp)
temp=$temp
windchill
shift;;
--velocity=$speed)
speed=$speed
windchill
shift;;
-c | --cout)
cout
shift;;
--cin)
cin
shift;;
--file=$filename)
file
shift;;
-h | --help)
help
exit;;
-q | --quiet)
quiet
shift;;
-v | --version)
version
exit;;
*)
echo "Illegal Input"
exit
esac
done
exit
bash bc getopts
asked 2 hours ago
Trinity ZamrzlaTrinity Zamrzla
295
Thanks to Fox I am now getting the correct output, however it is not scaling to only 3 places. Anyone know how to do that?
function windchill {
to=32
v=10
vel=`echo 'e(l('$v')*0.16)' | bc -l`
w=$(echo "scale=3; $vel" | bc -l)
twc=`echo "35.74 + (0.6215 * $to) - (35.75 * $w) + (0.4275 * $to * $w)" | bc`
echo ''
echo 'Windchill Calculator'
echo 'Outside Air Temperature (F): '"$to"
echo 'Wind Speed: '"$v"
echo 'Wind-Chill (F): '"$twc"
echo ''
exit
}
I am getting the correct $tf and $v the $wc is my problem. Using a calculator I get the correct answer just not in my bash file. The problem is my $w is coming back as a 1 not 1.4454.
The next area is the getopt to my case switch and the values aren't being passed from the input to the function
ARGS=$(getopt -o "chqv" -l "airtemp=$temp::,velocity=$speed::,cout:,cin:,file=$filename:,help,quiet:,version" -- "$@")
eval set -- "$ARGS"
# handle options
while true; do
case "$1" in
--airtemp=$temp)
temp=$temp
windchill
shift;;
--velocity=$speed)
speed=$speed
windchill
shift;;
-c | --cout)
cout
shift;;
--cin)
cin
shift;;
--file=$filename)
file
shift;;
-h | --help)
help
exit;;
-q | --quiet)
quiet
shift;;
-v | --version)
version
exit;;
*)
echo "Illegal Input"
exit
esac
done
exit
bash bc getopts
bash bc getopts
asked 2 hours ago
Trinity ZamrzlaTrinity Zamrzla
295
asked 2 hours ago
Trinity ZamrzlaTrinity Zamrzla
295
edited 58 mins ago
Trinity Zamrzla
asked 2 hours ago
Trinity ZamrzlaTrinity Zamrzla
295
asked 2 hours ago
Trinity ZamrzlaTrinity Zamrzla
295
asked 2 hours ago
Trinity ZamrzlaTrinity Zamrzla
295
295
I don't quite nee why you callwindchillinside the option parsing loop, ofter settingspeedandtemp. Wouldn't you want to set all parameters and then callwindchillafter the loop?
– Kusalananda
1 hour ago
I was under the impression that the shift means it would check the first one and then shift to the next one. I completely guessing on how to do this. My professor gave me a web site and said figure it out. linuxaria.com/howto/… this is what he gave us as a reference
– Trinity Zamrzla
1 hour ago
add a comment |
I don't quite nee why you callwindchillinside the option parsing loop, ofter settingspeedandtemp. Wouldn't you want to set all parameters and then callwindchillafter the loop?
– Kusalananda
1 hour ago
I was under the impression that the shift means it would check the first one and then shift to the next one. I completely guessing on how to do this. My professor gave me a web site and said figure it out. linuxaria.com/howto/… this is what he gave us as a reference
– Trinity Zamrzla
1 hour ago
I don't quite nee why you call
windchill inside the option parsing loop, ofter setting speed and temp. Wouldn't you want to set all parameters and then call windchill after the loop?– Kusalananda
1 hour ago
I don't quite nee why you call
windchill inside the option parsing loop, ofter setting speed and temp. Wouldn't you want to set all parameters and then call windchill after the loop?– Kusalananda
1 hour ago
I was under the impression that the shift means it would check the first one and then shift to the next one. I completely guessing on how to do this. My professor gave me a web site and said figure it out. linuxaria.com/howto/… this is what he gave us as a reference
– Trinity Zamrzla
1 hour ago
I was under the impression that the shift means it would check the first one and then shift to the next one. I completely guessing on how to do this. My professor gave me a web site and said figure it out. linuxaria.com/howto/… this is what he gave us as a reference
– Trinity Zamrzla
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
In bc, the ^ operator is integer exponentiation, so you're actually raising v to the 0 power, not 0.16. You can make use of logarithms to compute general exponents though: instead of x^y, you can use e(y*l(x)). So here, instead of v^0.16, you'll want e(0.16*l(v)).
Note that this requires the -l option to bc to include the standard math library.
answered 2 hours ago
FoxFox
5,55711233
okay thanks for the help I got this to work however I need it only the the 3rd digit after the decimal vel=echo 'e(l('$v')*0.16)' | bc -l
– Trinity Zamrzla
1 hour ago
That's whatscaleis for
– Fox
1 hour ago
I have tried and I am still getting a long output, maybe I am not inputting it correctly. w=$(echo "scale=3; $vel" | bc -l) and my output is 1.44543977074592751192
– Trinity Zamrzla
58 mins ago
w=$(echo "scale=3; e(0.16 * l($v))" | bc -l)works for me, at least for settingwcorrectly
– Fox
7 mins ago
add a comment |
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votes
In bc, the ^ operator is integer exponentiation, so you're actually raising v to the 0 power, not 0.16. You can make use of logarithms to compute general exponents though: instead of x^y, you can use e(y*l(x)). So here, instead of v^0.16, you'll want e(0.16*l(v)).
Note that this requires the -l option to bc to include the standard math library.
answered 2 hours ago
FoxFox
5,55711233
okay thanks for the help I got this to work however I need it only the the 3rd digit after the decimal vel=echo 'e(l('$v')*0.16)' | bc -l
– Trinity Zamrzla
1 hour ago
That's whatscaleis for
– Fox
1 hour ago
I have tried and I am still getting a long output, maybe I am not inputting it correctly. w=$(echo "scale=3; $vel" | bc -l) and my output is 1.44543977074592751192
– Trinity Zamrzla
58 mins ago
w=$(echo "scale=3; e(0.16 * l($v))" | bc -l)works for me, at least for settingwcorrectly
– Fox
7 mins ago
add a comment |
In bc, the ^ operator is integer exponentiation, so you're actually raising v to the 0 power, not 0.16. You can make use of logarithms to compute general exponents though: instead of x^y, you can use e(y*l(x)). So here, instead of v^0.16, you'll want e(0.16*l(v)).
Note that this requires the -l option to bc to include the standard math library.
answered 2 hours ago
FoxFox
5,55711233
okay thanks for the help I got this to work however I need it only the the 3rd digit after the decimal vel=echo 'e(l('$v')*0.16)' | bc -l
– Trinity Zamrzla
1 hour ago
That's whatscaleis for
– Fox
1 hour ago
I have tried and I am still getting a long output, maybe I am not inputting it correctly. w=$(echo "scale=3; $vel" | bc -l) and my output is 1.44543977074592751192
– Trinity Zamrzla
58 mins ago
w=$(echo "scale=3; e(0.16 * l($v))" | bc -l)works for me, at least for settingwcorrectly
– Fox
7 mins ago
add a comment |
In bc, the ^ operator is integer exponentiation, so you're actually raising v to the 0 power, not 0.16. You can make use of logarithms to compute general exponents though: instead of x^y, you can use e(y*l(x)). So here, instead of v^0.16, you'll want e(0.16*l(v)).
Note that this requires the -l option to bc to include the standard math library.
answered 2 hours ago
FoxFox
5,55711233
In bc, the ^ operator is integer exponentiation, so you're actually raising v to the 0 power, not 0.16. You can make use of logarithms to compute general exponents though: instead of x^y, you can use e(y*l(x)). So here, instead of v^0.16, you'll want e(0.16*l(v)).
Note that this requires the -l option to bc to include the standard math library.
answered 2 hours ago
FoxFox
5,55711233
answered 2 hours ago
FoxFox
5,55711233
answered 2 hours ago
FoxFox
5,55711233
answered 2 hours ago
FoxFox
5,55711233
5,55711233
okay thanks for the help I got this to work however I need it only the the 3rd digit after the decimal vel=echo 'e(l('$v')*0.16)' | bc -l
– Trinity Zamrzla
1 hour ago
That's whatscaleis for
– Fox
1 hour ago
I have tried and I am still getting a long output, maybe I am not inputting it correctly. w=$(echo "scale=3; $vel" | bc -l) and my output is 1.44543977074592751192
– Trinity Zamrzla
58 mins ago
w=$(echo "scale=3; e(0.16 * l($v))" | bc -l)works for me, at least for settingwcorrectly
– Fox
7 mins ago
add a comment |
okay thanks for the help I got this to work however I need it only the the 3rd digit after the decimal vel=echo 'e(l('$v')*0.16)' | bc -l
– Trinity Zamrzla
1 hour ago
That's whatscaleis for
– Fox
1 hour ago
I have tried and I am still getting a long output, maybe I am not inputting it correctly. w=$(echo "scale=3; $vel" | bc -l) and my output is 1.44543977074592751192
– Trinity Zamrzla
58 mins ago
w=$(echo "scale=3; e(0.16 * l($v))" | bc -l)works for me, at least for settingwcorrectly
– Fox
7 mins ago
okay thanks for the help I got this to work however I need it only the the 3rd digit after the decimal vel=
echo 'e(l('$v')*0.16)' | bc -l– Trinity Zamrzla
1 hour ago
okay thanks for the help I got this to work however I need it only the the 3rd digit after the decimal vel=
echo 'e(l('$v')*0.16)' | bc -l– Trinity Zamrzla
1 hour ago
That's what
scale is for– Fox
1 hour ago
That's what
scale is for– Fox
1 hour ago
I have tried and I am still getting a long output, maybe I am not inputting it correctly. w=$(echo "scale=3; $vel" | bc -l) and my output is 1.44543977074592751192
– Trinity Zamrzla
58 mins ago
I have tried and I am still getting a long output, maybe I am not inputting it correctly. w=$(echo "scale=3; $vel" | bc -l) and my output is 1.44543977074592751192
– Trinity Zamrzla
58 mins ago
w=$(echo "scale=3; e(0.16 * l($v))" | bc -l) works for me, at least for setting w correctly– Fox
7 mins ago
w=$(echo "scale=3; e(0.16 * l($v))" | bc -l) works for me, at least for setting w correctly– Fox
7 mins ago
add a comment |
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I don't quite nee why you call
windchillinside the option parsing loop, ofter settingspeedandtemp. Wouldn't you want to set all parameters and then callwindchillafter the loop?– Kusalananda
1 hour ago
I was under the impression that the shift means it would check the first one and then shift to the next one. I completely guessing on how to do this. My professor gave me a web site and said figure it out. linuxaria.com/howto/… this is what he gave us as a reference
– Trinity Zamrzla
1 hour ago