Check if object is null and return null
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null){
return null;
}
apex visualforce visualforce-component
asked 5 hours ago
ebarebar
182
add a comment |
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null){
return null;
}
apex visualforce visualforce-component
asked 5 hours ago
ebarebar
182
add a comment |
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null){
return null;
}
apex visualforce visualforce-component
asked 5 hours ago
ebarebar
182
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null){
return null;
}
apex visualforce visualforce-component
apex visualforce visualforce-component
asked 5 hours ago
ebarebar
182
asked 5 hours ago
ebarebar
182
asked 5 hours ago
ebarebar
182
asked 5 hours ago
ebarebar
182
asked 5 hours ago
ebarebar
182
182
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
The syntax in your code throws a QueryException if you try it, and there are no records to return. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 5 hours ago
sfdcfoxsfdcfox
260k12206451
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
5 hours ago
@JayantDas That's what I meant, of course, but I went ahead and clarified.
– sfdcfox
2 hours ago
add a comment |
One way to do this is to check for the number of records returned:
People persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 5 hours ago
Keith CKeith C
96.1k1094212
add a comment |
Change the code to:
People people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 5 hours ago
Phil WPhil W
471210
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The syntax in your code throws a QueryException if you try it, and there are no records to return. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 5 hours ago
sfdcfoxsfdcfox
260k12206451
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
5 hours ago
@JayantDas That's what I meant, of course, but I went ahead and clarified.
– sfdcfox
2 hours ago
add a comment |
The syntax in your code throws a QueryException if you try it, and there are no records to return. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 5 hours ago
sfdcfoxsfdcfox
260k12206451
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
5 hours ago
@JayantDas That's what I meant, of course, but I went ahead and clarified.
– sfdcfox
2 hours ago
add a comment |
The syntax in your code throws a QueryException if you try it, and there are no records to return. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 5 hours ago
sfdcfoxsfdcfox
260k12206451
The syntax in your code throws a QueryException if you try it, and there are no records to return. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 5 hours ago
sfdcfoxsfdcfox
260k12206451
edited 2 hours ago
answered 5 hours ago
sfdcfoxsfdcfox
260k12206451
answered 5 hours ago
sfdcfoxsfdcfox
260k12206451
answered 5 hours ago
sfdcfoxsfdcfox
260k12206451
260k12206451
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
5 hours ago
@JayantDas That's what I meant, of course, but I went ahead and clarified.
– sfdcfox
2 hours ago
add a comment |
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
5 hours ago
@JayantDas That's what I meant, of course, but I went ahead and clarified.
– sfdcfox
2 hours ago
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
5 hours ago
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
5 hours ago
@JayantDas That's what I meant, of course, but I went ahead and clarified.
– sfdcfox
2 hours ago
@JayantDas That's what I meant, of course, but I went ahead and clarified.
– sfdcfox
2 hours ago
add a comment |
One way to do this is to check for the number of records returned:
People persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 5 hours ago
Keith CKeith C
96.1k1094212
add a comment |
One way to do this is to check for the number of records returned:
People persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 5 hours ago
Keith CKeith C
96.1k1094212
add a comment |
One way to do this is to check for the number of records returned:
People persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 5 hours ago
Keith CKeith C
96.1k1094212
One way to do this is to check for the number of records returned:
People persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 5 hours ago
Keith CKeith C
96.1k1094212
answered 5 hours ago
Keith CKeith C
96.1k1094212
answered 5 hours ago
Keith CKeith C
96.1k1094212
answered 5 hours ago
Keith CKeith C
96.1k1094212
96.1k1094212
add a comment |
add a comment |
Change the code to:
People people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 5 hours ago
Phil WPhil W
471210
add a comment |
Change the code to:
People people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 5 hours ago
Phil WPhil W
471210
add a comment |
Change the code to:
People people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 5 hours ago
Phil WPhil W
471210
Change the code to:
People people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 5 hours ago
Phil WPhil W
471210
answered 5 hours ago
Phil WPhil W
471210
answered 5 hours ago
Phil WPhil W
471210
answered 5 hours ago
Phil WPhil W
471210
471210
add a comment |
add a comment |
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