Pipe each batch of xargs trough wc -l
So my task is to find the file with the most hardlinks in a directory.
So far i have :
find . -name "file*" | xargs -I{} -n 1 find . -samefile {}
which gives me:
/hardlinkFIle245
./hardlinkFIle23
./hardlinkFIle2
./file2.txt
./hardlinkFIle1234
./hardlinkFIle123
./hardlinkFIle12
./hardlinkFIle1
./file1.txt
Now when i pipe it in with |wc -l i get the total number of lines 9:
find . -name "file*" | xargs -I{} -n 1 find . -samefile {} | wc -l
What i want is for each xargs batch -n 1 to give me the count :
so i want: 4
5
linux find pipe xargs
New contributor
add a comment |
So my task is to find the file with the most hardlinks in a directory.
So far i have :
find . -name "file*" | xargs -I{} -n 1 find . -samefile {}
which gives me:
/hardlinkFIle245
./hardlinkFIle23
./hardlinkFIle2
./file2.txt
./hardlinkFIle1234
./hardlinkFIle123
./hardlinkFIle12
./hardlinkFIle1
./file1.txt
Now when i pipe it in with |wc -l i get the total number of lines 9:
find . -name "file*" | xargs -I{} -n 1 find . -samefile {} | wc -l
What i want is for each xargs batch -n 1 to give me the count :
so i want: 4
5
linux find pipe xargs
New contributor
Doesn't yourfind
command's-printf
have a%n
specifier for the number of hardlinks? You could simplysort
andtail
that
– steeldriver
3 hours ago
add a comment |
So my task is to find the file with the most hardlinks in a directory.
So far i have :
find . -name "file*" | xargs -I{} -n 1 find . -samefile {}
which gives me:
/hardlinkFIle245
./hardlinkFIle23
./hardlinkFIle2
./file2.txt
./hardlinkFIle1234
./hardlinkFIle123
./hardlinkFIle12
./hardlinkFIle1
./file1.txt
Now when i pipe it in with |wc -l i get the total number of lines 9:
find . -name "file*" | xargs -I{} -n 1 find . -samefile {} | wc -l
What i want is for each xargs batch -n 1 to give me the count :
so i want: 4
5
linux find pipe xargs
New contributor
So my task is to find the file with the most hardlinks in a directory.
So far i have :
find . -name "file*" | xargs -I{} -n 1 find . -samefile {}
which gives me:
/hardlinkFIle245
./hardlinkFIle23
./hardlinkFIle2
./file2.txt
./hardlinkFIle1234
./hardlinkFIle123
./hardlinkFIle12
./hardlinkFIle1
./file1.txt
Now when i pipe it in with |wc -l i get the total number of lines 9:
find . -name "file*" | xargs -I{} -n 1 find . -samefile {} | wc -l
What i want is for each xargs batch -n 1 to give me the count :
so i want: 4
5
linux find pipe xargs
linux find pipe xargs
New contributor
New contributor
New contributor
asked 4 hours ago
GokingGoking
1
1
New contributor
New contributor
Doesn't yourfind
command's-printf
have a%n
specifier for the number of hardlinks? You could simplysort
andtail
that
– steeldriver
3 hours ago
add a comment |
Doesn't yourfind
command's-printf
have a%n
specifier for the number of hardlinks? You could simplysort
andtail
that
– steeldriver
3 hours ago
Doesn't your
find
command's -printf
have a %n
specifier for the number of hardlinks? You could simply sort
and tail
that– steeldriver
3 hours ago
Doesn't your
find
command's -printf
have a %n
specifier for the number of hardlinks? You could simply sort
and tail
that– steeldriver
3 hours ago
add a comment |
1 Answer
1
active
oldest
votes
You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
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add a comment |
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1 Answer
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You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
New contributor
add a comment |
You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
New contributor
add a comment |
You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
New contributor
You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
New contributor
New contributor
answered 4 hours ago
Entropy0Entropy0
362
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Doesn't your
find
command's-printf
have a%n
specifier for the number of hardlinks? You could simplysort
andtail
that– steeldriver
3 hours ago