Pipe each batch of xargs trough wc -l
Multi tool use
-1
So my task is to find the file with the most hardlinks in a directory.
So far i have :
find . -name "file*" | xargs -I{} -n 1 find . -samefile {}
which gives me:
/hardlinkFIle245
./hardlinkFIle23
./hardlinkFIle2
./file2.txt
./hardlinkFIle1234
./hardlinkFIle123
./hardlinkFIle12
./hardlinkFIle1
./file1.txt
Now when i pipe it in with |wc -l i get the total number of lines 9:
find . -name "file*" | xargs -I{} -n 1 find . -samefile {} | wc -l
What i want is for each xargs batch -n 1 to give me the count :
so i want: 4
5
linux find pipe xargs
asked 4 hours ago
GokingGoking
1
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add a comment |
-1
So my task is to find the file with the most hardlinks in a directory.
So far i have :
find . -name "file*" | xargs -I{} -n 1 find . -samefile {}
which gives me:
/hardlinkFIle245
./hardlinkFIle23
./hardlinkFIle2
./file2.txt
./hardlinkFIle1234
./hardlinkFIle123
./hardlinkFIle12
./hardlinkFIle1
./file1.txt
Now when i pipe it in with |wc -l i get the total number of lines 9:
find . -name "file*" | xargs -I{} -n 1 find . -samefile {} | wc -l
What i want is for each xargs batch -n 1 to give me the count :
so i want: 4
5
linux find pipe xargs
asked 4 hours ago
GokingGoking
1
New contributor
Goking is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Doesn't yourfindcommand's-printfhave a%nspecifier for the number of hardlinks? You could simplysortandtailthat
– steeldriver
3 hours ago
add a comment |
-1
-1
-1
So my task is to find the file with the most hardlinks in a directory.
So far i have :
find . -name "file*" | xargs -I{} -n 1 find . -samefile {}
which gives me:
/hardlinkFIle245
./hardlinkFIle23
./hardlinkFIle2
./file2.txt
./hardlinkFIle1234
./hardlinkFIle123
./hardlinkFIle12
./hardlinkFIle1
./file1.txt
Now when i pipe it in with |wc -l i get the total number of lines 9:
find . -name "file*" | xargs -I{} -n 1 find . -samefile {} | wc -l
What i want is for each xargs batch -n 1 to give me the count :
so i want: 4
5
linux find pipe xargs
asked 4 hours ago
GokingGoking
1
New contributor
Goking is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
So my task is to find the file with the most hardlinks in a directory.
So far i have :
find . -name "file*" | xargs -I{} -n 1 find . -samefile {}
which gives me:
/hardlinkFIle245
./hardlinkFIle23
./hardlinkFIle2
./file2.txt
./hardlinkFIle1234
./hardlinkFIle123
./hardlinkFIle12
./hardlinkFIle1
./file1.txt
Now when i pipe it in with |wc -l i get the total number of lines 9:
find . -name "file*" | xargs -I{} -n 1 find . -samefile {} | wc -l
What i want is for each xargs batch -n 1 to give me the count :
so i want: 4
5
linux find pipe xargs
linux find pipe xargs
asked 4 hours ago
GokingGoking
1
New contributor
Goking is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 4 hours ago
GokingGoking
1
New contributor
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asked 4 hours ago
GokingGoking
1
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asked 4 hours ago
GokingGoking
1
asked 4 hours ago
GokingGoking
1
1
New contributor
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New contributor
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Doesn't yourfindcommand's-printfhave a%nspecifier for the number of hardlinks? You could simplysortandtailthat
– steeldriver
3 hours ago
add a comment |
Doesn't yourfindcommand's-printfhave a%nspecifier for the number of hardlinks? You could simplysortandtailthat
– steeldriver
3 hours ago
Doesn't your
find command's -printf have a %n specifier for the number of hardlinks? You could simply sort and tail that– steeldriver
3 hours ago
Doesn't your
find command's -printf have a %n specifier for the number of hardlinks? You could simply sort and tail that– steeldriver
3 hours ago
add a comment |
1 Answer
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You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
answered 4 hours ago
Entropy0Entropy0
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You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
answered 4 hours ago
Entropy0Entropy0
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1
You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
answered 4 hours ago
Entropy0Entropy0
362
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1
1
1
You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
answered 4 hours ago
Entropy0Entropy0
362
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You can just spawn a new shell on each xargs:
find . -name "file*" | xargs -I{} -n 1 sh -c "echo {}; find . -samefile {} | wc -l"
answered 4 hours ago
Entropy0Entropy0
362
New contributor
Entropy0 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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answered 4 hours ago
Entropy0Entropy0
362
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answered 4 hours ago
Entropy0Entropy0
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answered 4 hours ago
Entropy0Entropy0
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362
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Doesn't your
findcommand's-printfhave a%nspecifier for the number of hardlinks? You could simplysortandtailthat– steeldriver
3 hours ago