Looping without brace expansion
I'm using a blackbox CLI based on Bash and I'm not entirely sure what stuff I can use.
Brace expansion doesn't work, and with it goes my ability to do loops without listing the arguments explicitly, which is something I was trying to avoid by looping to start with.
for x in {1..5}
do
for y in {a..c}
do
echo $HOME$x$y
done
done
How do I run something like this without brace expansion and without listing the arguments explicitly? Environment variables should also work, that's why I appended a random $HOME to the example.
Please feel free to provide different alternatives (AWK, sed) as I'm not entirely sure what will and what won't work.
bash shell-script shell
asked 2 hours ago
CharacterClassCharacterClass
103
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CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
I'm using a blackbox CLI based on Bash and I'm not entirely sure what stuff I can use.
Brace expansion doesn't work, and with it goes my ability to do loops without listing the arguments explicitly, which is something I was trying to avoid by looping to start with.
for x in {1..5}
do
for y in {a..c}
do
echo $HOME$x$y
done
done
How do I run something like this without brace expansion and without listing the arguments explicitly? Environment variables should also work, that's why I appended a random $HOME to the example.
Please feel free to provide different alternatives (AWK, sed) as I'm not entirely sure what will and what won't work.
bash shell-script shell
asked 2 hours ago
CharacterClassCharacterClass
103
New contributor
CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Do you have access to thejotcommand?
– Fox
2 hours ago
2
So this appears to be not based on Bash based on your description; what makes you think that it is? Is there any further detail available about the system, the shell that's in it, or the tools that are available there?
– Michael Homer
1 hour ago
add a comment |
I'm using a blackbox CLI based on Bash and I'm not entirely sure what stuff I can use.
Brace expansion doesn't work, and with it goes my ability to do loops without listing the arguments explicitly, which is something I was trying to avoid by looping to start with.
for x in {1..5}
do
for y in {a..c}
do
echo $HOME$x$y
done
done
How do I run something like this without brace expansion and without listing the arguments explicitly? Environment variables should also work, that's why I appended a random $HOME to the example.
Please feel free to provide different alternatives (AWK, sed) as I'm not entirely sure what will and what won't work.
bash shell-script shell
asked 2 hours ago
CharacterClassCharacterClass
103
New contributor
CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm using a blackbox CLI based on Bash and I'm not entirely sure what stuff I can use.
Brace expansion doesn't work, and with it goes my ability to do loops without listing the arguments explicitly, which is something I was trying to avoid by looping to start with.
for x in {1..5}
do
for y in {a..c}
do
echo $HOME$x$y
done
done
How do I run something like this without brace expansion and without listing the arguments explicitly? Environment variables should also work, that's why I appended a random $HOME to the example.
Please feel free to provide different alternatives (AWK, sed) as I'm not entirely sure what will and what won't work.
bash shell-script shell
bash shell-script shell
asked 2 hours ago
CharacterClassCharacterClass
103
New contributor
CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
CharacterClassCharacterClass
103
New contributor
CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
CharacterClassCharacterClass
103
New contributor
CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
CharacterClassCharacterClass
103
asked 2 hours ago
CharacterClassCharacterClass
103
103
New contributor
CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
CharacterClass is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Do you have access to thejotcommand?
– Fox
2 hours ago
2
So this appears to be not based on Bash based on your description; what makes you think that it is? Is there any further detail available about the system, the shell that's in it, or the tools that are available there?
– Michael Homer
1 hour ago
add a comment |
1
Do you have access to thejotcommand?
– Fox
2 hours ago
2
So this appears to be not based on Bash based on your description; what makes you think that it is? Is there any further detail available about the system, the shell that's in it, or the tools that are available there?
– Michael Homer
1 hour ago
1
1
Do you have access to the
jot command?– Fox
2 hours ago
Do you have access to the
jot command?– Fox
2 hours ago
2
2
So this appears to be not based on Bash based on your description; what makes you think that it is? Is there any further detail available about the system, the shell that's in it, or the tools that are available there?
– Michael Homer
1 hour ago
So this appears to be not based on Bash based on your description; what makes you think that it is? Is there any further detail available about the system, the shell that's in it, or the tools that are available there?
– Michael Homer
1 hour ago
add a comment |
1 Answer
1
active
oldest
votes
You'd better use jot as commented. Here is a (not so pretty) awk implementation.
#!/usr/bin/awk -f
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "%s%d%c ",ENVIRON["HOME"],i,j;
print;
}
or (you may also use the -v option of awk to assign shell variables to awk variables)
#!/bin/bash
awk -f /dev/fd/3 3<< EOF
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "$HOME%d%c ",i,j;
print;
}
EOF
answered 2 hours ago
Weijun ZhouWeijun Zhou
1,481325
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
votes
You'd better use jot as commented. Here is a (not so pretty) awk implementation.
#!/usr/bin/awk -f
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "%s%d%c ",ENVIRON["HOME"],i,j;
print;
}
or (you may also use the -v option of awk to assign shell variables to awk variables)
#!/bin/bash
awk -f /dev/fd/3 3<< EOF
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "$HOME%d%c ",i,j;
print;
}
EOF
answered 2 hours ago
Weijun ZhouWeijun Zhou
1,481325
add a comment |
You'd better use jot as commented. Here is a (not so pretty) awk implementation.
#!/usr/bin/awk -f
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "%s%d%c ",ENVIRON["HOME"],i,j;
print;
}
or (you may also use the -v option of awk to assign shell variables to awk variables)
#!/bin/bash
awk -f /dev/fd/3 3<< EOF
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "$HOME%d%c ",i,j;
print;
}
EOF
answered 2 hours ago
Weijun ZhouWeijun Zhou
1,481325
add a comment |
You'd better use jot as commented. Here is a (not so pretty) awk implementation.
#!/usr/bin/awk -f
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "%s%d%c ",ENVIRON["HOME"],i,j;
print;
}
or (you may also use the -v option of awk to assign shell variables to awk variables)
#!/bin/bash
awk -f /dev/fd/3 3<< EOF
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "$HOME%d%c ",i,j;
print;
}
EOF
answered 2 hours ago
Weijun ZhouWeijun Zhou
1,481325
You'd better use jot as commented. Here is a (not so pretty) awk implementation.
#!/usr/bin/awk -f
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "%s%d%c ",ENVIRON["HOME"],i,j;
print;
}
or (you may also use the -v option of awk to assign shell variables to awk variables)
#!/bin/bash
awk -f /dev/fd/3 3<< EOF
BEGIN{
for(i=1;i<5;i++)
for(j=97;j<100;j++)
printf "$HOME%d%c ",i,j;
print;
}
EOF
answered 2 hours ago
Weijun ZhouWeijun Zhou
1,481325
edited 1 hour ago
answered 2 hours ago
Weijun ZhouWeijun Zhou
1,481325
answered 2 hours ago
Weijun ZhouWeijun Zhou
1,481325
answered 2 hours ago
Weijun ZhouWeijun Zhou
1,481325
1,481325
add a comment |
add a comment |
CharacterClass is a new contributor. Be nice, and check out our Code of Conduct.
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1
Do you have access to the
jotcommand?– Fox
2 hours ago
2
So this appears to be not based on Bash based on your description; what makes you think that it is? Is there any further detail available about the system, the shell that's in it, or the tools that are available there?
– Michael Homer
1 hour ago