Welcoming 2019 Pi day: How to draw the letter π?












5
















How to draw the letter π not in the standard way (i.e. pi)?




I mean "draw", not "type"! Today there will be no pi, but there will be something like this



documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,2)--(3,2);
draw (1,0)--(1,2);
draw (2,0)--(2,2);
end{tikzpicture}
end{document}


enter image description here



(inspired by David Carlisle – I draw this in TikZ just because I don't know how to use picture ;))



Or this



documentclass[tikz]{standalone}
usepackage{tikzducks}
begin{document}
begin{tikzpicture}
duck
duck[xshift=1cm,yshift=2cm]
duck[xshift=1cm,yshift=4cm]
duck[xshift=1cm,yshift=6cm]
duck[xshift=0cm,yshift=8cm]
duck[xshift=-2cm,yshift=7.5cm]
duck[xshift=2cm,yshift=8cm]
duck[xshift=4cm,yshift=8cm]
duck[xshift=6cm,yshift=8cm]
duck[xshift=8cm,yshift=8cm]
duck[xshift=5cm,yshift=6cm]
duck[xshift=5cm,yshift=4cm]
duck[xshift=5.5cm,yshift=2cm]
duck[xshift=6.5cm,yshift=0cm]
duck[xshift=8cm,yshift=1cm]
node[font=huge] at (4,11) {Happy $pi$ day with verb|tikzducks|!};
end{tikzpicture}
end{document}


enter image description here



They are my proudest π drawings, and as today is Pi day, I'd like to see yours!










share|improve this question

























  • Beat this one: ioccc.org/1989/roemer.c

    – user49915
    2 hours ago













  • @user49915 I don't think we can have the output and the code being exactly the same :))

    – JouleV
    1 hour ago











  • Though, I guess, a really useful one would be a sans-serif normalfont upright math capital Pi with xelatex and OTF fonts. You may ask "why", and the answer would be "since it's not a part of Unicode". As for for useless ones, I still see documentclass, begin, draw, tikz, linespread, ...; the output is all nice anyway, and I like all the solutions here.

    – user49915
    1 hour ago













  • You can probably have the code and the output close enough; you only have to pepper the Makefile compiling the code by suitable awk or sed scripts. In theory, you can have them exactly the same, since tex is Turing-complete (en.wikipedia.org/wiki/Quine_(computing)), but it's unlikely to print Pi in any sense of the word.

    – user49915
    1 hour ago


















5
















How to draw the letter π not in the standard way (i.e. pi)?




I mean "draw", not "type"! Today there will be no pi, but there will be something like this



documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,2)--(3,2);
draw (1,0)--(1,2);
draw (2,0)--(2,2);
end{tikzpicture}
end{document}


enter image description here



(inspired by David Carlisle – I draw this in TikZ just because I don't know how to use picture ;))



Or this



documentclass[tikz]{standalone}
usepackage{tikzducks}
begin{document}
begin{tikzpicture}
duck
duck[xshift=1cm,yshift=2cm]
duck[xshift=1cm,yshift=4cm]
duck[xshift=1cm,yshift=6cm]
duck[xshift=0cm,yshift=8cm]
duck[xshift=-2cm,yshift=7.5cm]
duck[xshift=2cm,yshift=8cm]
duck[xshift=4cm,yshift=8cm]
duck[xshift=6cm,yshift=8cm]
duck[xshift=8cm,yshift=8cm]
duck[xshift=5cm,yshift=6cm]
duck[xshift=5cm,yshift=4cm]
duck[xshift=5.5cm,yshift=2cm]
duck[xshift=6.5cm,yshift=0cm]
duck[xshift=8cm,yshift=1cm]
node[font=huge] at (4,11) {Happy $pi$ day with verb|tikzducks|!};
end{tikzpicture}
end{document}


enter image description here



They are my proudest π drawings, and as today is Pi day, I'd like to see yours!










share|improve this question

























  • Beat this one: ioccc.org/1989/roemer.c

    – user49915
    2 hours ago













  • @user49915 I don't think we can have the output and the code being exactly the same :))

    – JouleV
    1 hour ago











  • Though, I guess, a really useful one would be a sans-serif normalfont upright math capital Pi with xelatex and OTF fonts. You may ask "why", and the answer would be "since it's not a part of Unicode". As for for useless ones, I still see documentclass, begin, draw, tikz, linespread, ...; the output is all nice anyway, and I like all the solutions here.

    – user49915
    1 hour ago













  • You can probably have the code and the output close enough; you only have to pepper the Makefile compiling the code by suitable awk or sed scripts. In theory, you can have them exactly the same, since tex is Turing-complete (en.wikipedia.org/wiki/Quine_(computing)), but it's unlikely to print Pi in any sense of the word.

    – user49915
    1 hour ago
















5












5








5









How to draw the letter π not in the standard way (i.e. pi)?




I mean "draw", not "type"! Today there will be no pi, but there will be something like this



documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,2)--(3,2);
draw (1,0)--(1,2);
draw (2,0)--(2,2);
end{tikzpicture}
end{document}


enter image description here



(inspired by David Carlisle – I draw this in TikZ just because I don't know how to use picture ;))



Or this



documentclass[tikz]{standalone}
usepackage{tikzducks}
begin{document}
begin{tikzpicture}
duck
duck[xshift=1cm,yshift=2cm]
duck[xshift=1cm,yshift=4cm]
duck[xshift=1cm,yshift=6cm]
duck[xshift=0cm,yshift=8cm]
duck[xshift=-2cm,yshift=7.5cm]
duck[xshift=2cm,yshift=8cm]
duck[xshift=4cm,yshift=8cm]
duck[xshift=6cm,yshift=8cm]
duck[xshift=8cm,yshift=8cm]
duck[xshift=5cm,yshift=6cm]
duck[xshift=5cm,yshift=4cm]
duck[xshift=5.5cm,yshift=2cm]
duck[xshift=6.5cm,yshift=0cm]
duck[xshift=8cm,yshift=1cm]
node[font=huge] at (4,11) {Happy $pi$ day with verb|tikzducks|!};
end{tikzpicture}
end{document}


enter image description here



They are my proudest π drawings, and as today is Pi day, I'd like to see yours!










share|improve this question

















How to draw the letter π not in the standard way (i.e. pi)?




I mean "draw", not "type"! Today there will be no pi, but there will be something like this



documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,2)--(3,2);
draw (1,0)--(1,2);
draw (2,0)--(2,2);
end{tikzpicture}
end{document}


enter image description here



(inspired by David Carlisle – I draw this in TikZ just because I don't know how to use picture ;))



Or this



documentclass[tikz]{standalone}
usepackage{tikzducks}
begin{document}
begin{tikzpicture}
duck
duck[xshift=1cm,yshift=2cm]
duck[xshift=1cm,yshift=4cm]
duck[xshift=1cm,yshift=6cm]
duck[xshift=0cm,yshift=8cm]
duck[xshift=-2cm,yshift=7.5cm]
duck[xshift=2cm,yshift=8cm]
duck[xshift=4cm,yshift=8cm]
duck[xshift=6cm,yshift=8cm]
duck[xshift=8cm,yshift=8cm]
duck[xshift=5cm,yshift=6cm]
duck[xshift=5cm,yshift=4cm]
duck[xshift=5.5cm,yshift=2cm]
duck[xshift=6.5cm,yshift=0cm]
duck[xshift=8cm,yshift=1cm]
node[font=huge] at (4,11) {Happy $pi$ day with verb|tikzducks|!};
end{tikzpicture}
end{document}


enter image description here



They are my proudest π drawings, and as today is Pi day, I'd like to see yours!







tikz-pgf fun tikzducks picture-mode tikzlings






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 34 mins ago









Henri Menke

76.5k8167282




76.5k8167282










asked 3 hours ago









JouleVJouleV

5,34621242




5,34621242













  • Beat this one: ioccc.org/1989/roemer.c

    – user49915
    2 hours ago













  • @user49915 I don't think we can have the output and the code being exactly the same :))

    – JouleV
    1 hour ago











  • Though, I guess, a really useful one would be a sans-serif normalfont upright math capital Pi with xelatex and OTF fonts. You may ask "why", and the answer would be "since it's not a part of Unicode". As for for useless ones, I still see documentclass, begin, draw, tikz, linespread, ...; the output is all nice anyway, and I like all the solutions here.

    – user49915
    1 hour ago













  • You can probably have the code and the output close enough; you only have to pepper the Makefile compiling the code by suitable awk or sed scripts. In theory, you can have them exactly the same, since tex is Turing-complete (en.wikipedia.org/wiki/Quine_(computing)), but it's unlikely to print Pi in any sense of the word.

    – user49915
    1 hour ago





















  • Beat this one: ioccc.org/1989/roemer.c

    – user49915
    2 hours ago













  • @user49915 I don't think we can have the output and the code being exactly the same :))

    – JouleV
    1 hour ago











  • Though, I guess, a really useful one would be a sans-serif normalfont upright math capital Pi with xelatex and OTF fonts. You may ask "why", and the answer would be "since it's not a part of Unicode". As for for useless ones, I still see documentclass, begin, draw, tikz, linespread, ...; the output is all nice anyway, and I like all the solutions here.

    – user49915
    1 hour ago













  • You can probably have the code and the output close enough; you only have to pepper the Makefile compiling the code by suitable awk or sed scripts. In theory, you can have them exactly the same, since tex is Turing-complete (en.wikipedia.org/wiki/Quine_(computing)), but it's unlikely to print Pi in any sense of the word.

    – user49915
    1 hour ago



















Beat this one: ioccc.org/1989/roemer.c

– user49915
2 hours ago







Beat this one: ioccc.org/1989/roemer.c

– user49915
2 hours ago















@user49915 I don't think we can have the output and the code being exactly the same :))

– JouleV
1 hour ago





@user49915 I don't think we can have the output and the code being exactly the same :))

– JouleV
1 hour ago













Though, I guess, a really useful one would be a sans-serif normalfont upright math capital Pi with xelatex and OTF fonts. You may ask "why", and the answer would be "since it's not a part of Unicode". As for for useless ones, I still see documentclass, begin, draw, tikz, linespread, ...; the output is all nice anyway, and I like all the solutions here.

– user49915
1 hour ago







Though, I guess, a really useful one would be a sans-serif normalfont upright math capital Pi with xelatex and OTF fonts. You may ask "why", and the answer would be "since it's not a part of Unicode". As for for useless ones, I still see documentclass, begin, draw, tikz, linespread, ...; the output is all nice anyway, and I like all the solutions here.

– user49915
1 hour ago















You can probably have the code and the output close enough; you only have to pepper the Makefile compiling the code by suitable awk or sed scripts. In theory, you can have them exactly the same, since tex is Turing-complete (en.wikipedia.org/wiki/Quine_(computing)), but it's unlikely to print Pi in any sense of the word.

– user49915
1 hour ago







You can probably have the code and the output close enough; you only have to pepper the Makefile compiling the code by suitable awk or sed scripts. In theory, you can have them exactly the same, since tex is Turing-complete (en.wikipedia.org/wiki/Quine_(computing)), but it's unlikely to print Pi in any sense of the word.

– user49915
1 hour ago












5 Answers
5






active

oldest

votes


















4














We could extract the MetaPost paths for the glyph pi from the font and draw it using LuaTeX.



documentclass{article}

usepackage{fontspec}
setmainfont{latinmodern-math.otf}

usepackage{luacode}
begin{luacode*}


-- We need some utilities from ConTeXt
callbacks = callbacks or {}
callbacks.supported = callbacks.supported or {}
CONTEXTLMTXMODE = CONTEXTLMTXMODE or (status.obj_ptr == nil and 2 or 1)
dofile(kpse.find_file("util-fmt.lua"))
dofile(kpse.find_file("node-ini.lua"))
dofile(kpse.find_file("font-mps.lua"))
dofile(kpse.find_file("font-shp.lua"))

-- That's a simple reimplemetation of ConTeXt's showshape macro
function outlinepaths(character)
local fontid = font.current()
local shapedata = fonts.hashes.shapes[fontid] -- by index
local chardata = fonts.hashes.characters[fontid] -- by unicode
local shapeglyphs = shapedata.glyphs or { }

character = utf.byte(character)
local c = chardata[character]
if c then
if not c.index then
return {}
end
local glyph = shapeglyphs[c.index]
if glyph and (glyph.segments or glyph.sequence) then
local units = shapedata.units or 1000
local factor = 100/units
local paths = fonts.metapost.paths(glyph,factor)
return paths
end
end
end




end{luacode*}

usepackage{luamplib}
everymplib{beginfig(0);}
everyendmplib{endfig;}

defmpdefineoutlines#1{directlua{


    local char = "luaescapestring{#1}"
local outlines = outlinepaths("#1")
for i, path in ipairs(outlines) do
tex.print("fill " .. path .. ";")
end




  }}

begin{document}

begin{mplibcode}

mpdefineoutlines{𝜋}

end{mplibcode}

end{document}


Instead of using luamplib, we could also simply print the path to the log file and copy it to a MetaPost file. With some additonal formatting we get:



prologues := 3;
outputformat := "pdf";

beginfig(1)
fill (56.70,40.70)
.. controls (56.70,43.10) and (54.60,43.10)
.. (52.70,43.10)
-- (19.20,43.10)
.. controls (17,43.10) and (13.20,43.10)
.. (8.80,38.40)
.. controls (5.30,34.50) and (2.70,29.90)
.. (2.70,29.40)
.. controls (2.70,29.40) and (2.70,28.40)
.. (3.90,28.40)
.. controls (4.70,28.40) and (4.90,28.80)
.. (5.50,29.60)
.. controls (10.40,37.30) and (16.20,37.30)
.. (18.20,37.30)
-- (23.90,37.30)
.. controls (20.70,25.20) and (15.30,13.10)
.. (11.10,4)
.. controls (10.30,2.50) and (10.30,2.30)
.. (10.30,1.60)
.. controls (10.30,-0.30) and (11.90,-1.10)
.. (13.20,-1.10)
.. controls (16.20,-1.10) and (17,1.70)
.. (18.20,5.40)
.. controls (19.60,10) and (19.60,10.20)
.. (20.90,15.20)
-- (26.50,37.30)
-- (37.80,37.30)
.. controls (34.50,22.50) and (33.60,18.20)
.. (33.60,11.50)
.. controls (33.60,10) and (33.60,7.30)
.. (34.40,3.90)
.. controls (35.40,-0.50) and (36.50,-1.10)
.. (38,-1.10)
.. controls (40,-1.10) and (42.10,0.70)
.. (42.10,2.70)
.. controls (42.10,3.30) and (42.10,3.50)
.. (41.50,4.90)
.. controls (38.60,12.10) and (38.60,18.60)
.. (38.60,21.40)
.. controls (38.60,26.70) and (39.30,32.10)
.. (40.40,37.30)
-- (51.80,37.30)
.. controls (53.10,37.30) and (56.70,37.30)
.. (56.70,40.70)
-- cycle;
endfig;
end


Or you can even use the path with TikZ.



documentclass{article}

usepackage{tikz}

begin{document}

begin{tikzpicture}[x=1pt,y=1pt]

fill (56.70,40.70)
.. controls (56.70,43.10) and (54.60,43.10)
.. (52.70,43.10)
-- (19.20,43.10)
.. controls (17,43.10) and (13.20,43.10)
.. (8.80,38.40)
.. controls (5.30,34.50) and (2.70,29.90)
.. (2.70,29.40)
.. controls (2.70,29.40) and (2.70,28.40)
.. (3.90,28.40)
.. controls (4.70,28.40) and (4.90,28.80)
.. (5.50,29.60)
.. controls (10.40,37.30) and (16.20,37.30)
.. (18.20,37.30)
-- (23.90,37.30)
.. controls (20.70,25.20) and (15.30,13.10)
.. (11.10,4)
.. controls (10.30,2.50) and (10.30,2.30)
.. (10.30,1.60)
.. controls (10.30,-0.30) and (11.90,-1.10)
.. (13.20,-1.10)
.. controls (16.20,-1.10) and (17,1.70)
.. (18.20,5.40)
.. controls (19.60,10) and (19.60,10.20)
.. (20.90,15.20)
-- (26.50,37.30)
-- (37.80,37.30)
.. controls (34.50,22.50) and (33.60,18.20)
.. (33.60,11.50)
.. controls (33.60,10) and (33.60,7.30)
.. (34.40,3.90)
.. controls (35.40,-0.50) and (36.50,-1.10)
.. (38,-1.10)
.. controls (40,-1.10) and (42.10,0.70)
.. (42.10,2.70)
.. controls (42.10,3.30) and (42.10,3.50)
.. (41.50,4.90)
.. controls (38.60,12.10) and (38.60,18.60)
.. (38.60,21.40)
.. controls (38.60,26.70) and (39.30,32.10)
.. (40.40,37.30)
-- (51.80,37.30)
.. controls (53.10,37.30) and (56.70,37.30)
.. (56.70,40.70)
-- cycle;

end{tikzpicture}

end{document}


The output is rather unspectacular.



enter image description here






share|improve this answer

































    3














    Writing π with the digits of π - using the verbatim environment.



    enter image description here



    documentclass{article}
    linespread{0.7}
    begin{document}
    begin{verbatim}
    3.141592653589793238462643383279
    5028841971693993751058209749445923
    07816406286208998628034825342117067
    9821 48086 5132
    823 06647 09384
    46 09550 58223
    17 25359 4081
    2848 1117
    4502 8410
    2701 9385
    21105 55964
    46229 48954
    9303 81964
    4288 10975
    66593 34461
    284756 48233
    78678 31652 71
    2019091 456485 66
    9234603 48610454326648
    2133936 0726024914127
    3724587 00660631558
    817488 152092096
    end{verbatim}
    end{document}


    Based on ascii art drawing by Jorel - https://www.flickr.com/photos/jorel314/3352784321/






    share|improve this answer


























    • How did you format the code? By trial/error?

      – Sigur
      2 hours ago











    • @Sigur I did it by hand, but based off an ascii art drawing I found online. Added a reference to the original drawing.

      – Milo
      1 hour ago













    • Nice. Though, not quite: you simply draw it rather than computing it :-).

      – user49915
      1 hour ago



















    2














    Happy pi(less) day!!



    enter image description here



    documentclass{report}
    begin{document}
    noindent%
    rule{30pt}{1pt}\[-1pt]
    rule{8pt}{0pt}%
    rule{1pt}{30pt}%
    rule{12pt}{0pt}%
    rule{1pt}{30pt}
    end{document}





    share|improve this answer

































      2














      One should also honor Euler a bit.



      documentclass[tikz,border=3.14mm]{standalone}
      usepackage{tikzlings,amsmath}
      makeatletter
      tikzset{/thing/.cd,
      pie/.code=thing@cheesetruedefthing@cheese{#1}, %<-pretend you didn't see that
      pie/.default=pink!70!red}
      makeatother
      begin{document}
      begin{tikzpicture}[font=sffamily]
      marmot[pie,whiskers,teeth,shadow]
      node[anchor=east,scale=5,transform shape] at (-0.6,1) {$picdotmathsf{e}=text{sffamily pie}$};
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer































        1














        The obligatory forest solution:



        documentclass{standalone}

        usepackage[edges]{forest}
        usetikzlibrary{calc}
        forestset{
        forked edge'/.style={
        edge={rotate/.option=!parent.grow},
        edge path'={(!u.parent anchor)++(0pt,-30pt) -- (!u.parent anchor)++(0pt,30pt) |- (.child anchor)},
        }
        }
        begin{document}
        Huge
        begin{forest}forked edges,for tree={edge={line width=4pt}}
        [ [ ] [ ]]
        end{forest}
        end{document}


        pi






        share|improve this answer























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          5 Answers
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          5 Answers
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          4














          We could extract the MetaPost paths for the glyph pi from the font and draw it using LuaTeX.



          documentclass{article}

          usepackage{fontspec}
          setmainfont{latinmodern-math.otf}

          usepackage{luacode}
          begin{luacode*}


          -- We need some utilities from ConTeXt
          callbacks = callbacks or {}
          callbacks.supported = callbacks.supported or {}
          CONTEXTLMTXMODE = CONTEXTLMTXMODE or (status.obj_ptr == nil and 2 or 1)
          dofile(kpse.find_file("util-fmt.lua"))
          dofile(kpse.find_file("node-ini.lua"))
          dofile(kpse.find_file("font-mps.lua"))
          dofile(kpse.find_file("font-shp.lua"))

          -- That's a simple reimplemetation of ConTeXt's showshape macro
          function outlinepaths(character)
          local fontid = font.current()
          local shapedata = fonts.hashes.shapes[fontid] -- by index
          local chardata = fonts.hashes.characters[fontid] -- by unicode
          local shapeglyphs = shapedata.glyphs or { }

          character = utf.byte(character)
          local c = chardata[character]
          if c then
          if not c.index then
          return {}
          end
          local glyph = shapeglyphs[c.index]
          if glyph and (glyph.segments or glyph.sequence) then
          local units = shapedata.units or 1000
          local factor = 100/units
          local paths = fonts.metapost.paths(glyph,factor)
          return paths
          end
          end
          end




          end{luacode*}

          usepackage{luamplib}
          everymplib{beginfig(0);}
          everyendmplib{endfig;}

          defmpdefineoutlines#1{directlua{


              local char = "luaescapestring{#1}"
          local outlines = outlinepaths("#1")
          for i, path in ipairs(outlines) do
          tex.print("fill " .. path .. ";")
          end




            }}

          begin{document}

          begin{mplibcode}

          mpdefineoutlines{𝜋}

          end{mplibcode}

          end{document}


          Instead of using luamplib, we could also simply print the path to the log file and copy it to a MetaPost file. With some additonal formatting we get:



          prologues := 3;
          outputformat := "pdf";

          beginfig(1)
          fill (56.70,40.70)
          .. controls (56.70,43.10) and (54.60,43.10)
          .. (52.70,43.10)
          -- (19.20,43.10)
          .. controls (17,43.10) and (13.20,43.10)
          .. (8.80,38.40)
          .. controls (5.30,34.50) and (2.70,29.90)
          .. (2.70,29.40)
          .. controls (2.70,29.40) and (2.70,28.40)
          .. (3.90,28.40)
          .. controls (4.70,28.40) and (4.90,28.80)
          .. (5.50,29.60)
          .. controls (10.40,37.30) and (16.20,37.30)
          .. (18.20,37.30)
          -- (23.90,37.30)
          .. controls (20.70,25.20) and (15.30,13.10)
          .. (11.10,4)
          .. controls (10.30,2.50) and (10.30,2.30)
          .. (10.30,1.60)
          .. controls (10.30,-0.30) and (11.90,-1.10)
          .. (13.20,-1.10)
          .. controls (16.20,-1.10) and (17,1.70)
          .. (18.20,5.40)
          .. controls (19.60,10) and (19.60,10.20)
          .. (20.90,15.20)
          -- (26.50,37.30)
          -- (37.80,37.30)
          .. controls (34.50,22.50) and (33.60,18.20)
          .. (33.60,11.50)
          .. controls (33.60,10) and (33.60,7.30)
          .. (34.40,3.90)
          .. controls (35.40,-0.50) and (36.50,-1.10)
          .. (38,-1.10)
          .. controls (40,-1.10) and (42.10,0.70)
          .. (42.10,2.70)
          .. controls (42.10,3.30) and (42.10,3.50)
          .. (41.50,4.90)
          .. controls (38.60,12.10) and (38.60,18.60)
          .. (38.60,21.40)
          .. controls (38.60,26.70) and (39.30,32.10)
          .. (40.40,37.30)
          -- (51.80,37.30)
          .. controls (53.10,37.30) and (56.70,37.30)
          .. (56.70,40.70)
          -- cycle;
          endfig;
          end


          Or you can even use the path with TikZ.



          documentclass{article}

          usepackage{tikz}

          begin{document}

          begin{tikzpicture}[x=1pt,y=1pt]

          fill (56.70,40.70)
          .. controls (56.70,43.10) and (54.60,43.10)
          .. (52.70,43.10)
          -- (19.20,43.10)
          .. controls (17,43.10) and (13.20,43.10)
          .. (8.80,38.40)
          .. controls (5.30,34.50) and (2.70,29.90)
          .. (2.70,29.40)
          .. controls (2.70,29.40) and (2.70,28.40)
          .. (3.90,28.40)
          .. controls (4.70,28.40) and (4.90,28.80)
          .. (5.50,29.60)
          .. controls (10.40,37.30) and (16.20,37.30)
          .. (18.20,37.30)
          -- (23.90,37.30)
          .. controls (20.70,25.20) and (15.30,13.10)
          .. (11.10,4)
          .. controls (10.30,2.50) and (10.30,2.30)
          .. (10.30,1.60)
          .. controls (10.30,-0.30) and (11.90,-1.10)
          .. (13.20,-1.10)
          .. controls (16.20,-1.10) and (17,1.70)
          .. (18.20,5.40)
          .. controls (19.60,10) and (19.60,10.20)
          .. (20.90,15.20)
          -- (26.50,37.30)
          -- (37.80,37.30)
          .. controls (34.50,22.50) and (33.60,18.20)
          .. (33.60,11.50)
          .. controls (33.60,10) and (33.60,7.30)
          .. (34.40,3.90)
          .. controls (35.40,-0.50) and (36.50,-1.10)
          .. (38,-1.10)
          .. controls (40,-1.10) and (42.10,0.70)
          .. (42.10,2.70)
          .. controls (42.10,3.30) and (42.10,3.50)
          .. (41.50,4.90)
          .. controls (38.60,12.10) and (38.60,18.60)
          .. (38.60,21.40)
          .. controls (38.60,26.70) and (39.30,32.10)
          .. (40.40,37.30)
          -- (51.80,37.30)
          .. controls (53.10,37.30) and (56.70,37.30)
          .. (56.70,40.70)
          -- cycle;

          end{tikzpicture}

          end{document}


          The output is rather unspectacular.



          enter image description here






          share|improve this answer






























            4














            We could extract the MetaPost paths for the glyph pi from the font and draw it using LuaTeX.



            documentclass{article}

            usepackage{fontspec}
            setmainfont{latinmodern-math.otf}

            usepackage{luacode}
            begin{luacode*}


            -- We need some utilities from ConTeXt
            callbacks = callbacks or {}
            callbacks.supported = callbacks.supported or {}
            CONTEXTLMTXMODE = CONTEXTLMTXMODE or (status.obj_ptr == nil and 2 or 1)
            dofile(kpse.find_file("util-fmt.lua"))
            dofile(kpse.find_file("node-ini.lua"))
            dofile(kpse.find_file("font-mps.lua"))
            dofile(kpse.find_file("font-shp.lua"))

            -- That's a simple reimplemetation of ConTeXt's showshape macro
            function outlinepaths(character)
            local fontid = font.current()
            local shapedata = fonts.hashes.shapes[fontid] -- by index
            local chardata = fonts.hashes.characters[fontid] -- by unicode
            local shapeglyphs = shapedata.glyphs or { }

            character = utf.byte(character)
            local c = chardata[character]
            if c then
            if not c.index then
            return {}
            end
            local glyph = shapeglyphs[c.index]
            if glyph and (glyph.segments or glyph.sequence) then
            local units = shapedata.units or 1000
            local factor = 100/units
            local paths = fonts.metapost.paths(glyph,factor)
            return paths
            end
            end
            end




            end{luacode*}

            usepackage{luamplib}
            everymplib{beginfig(0);}
            everyendmplib{endfig;}

            defmpdefineoutlines#1{directlua{


                local char = "luaescapestring{#1}"
            local outlines = outlinepaths("#1")
            for i, path in ipairs(outlines) do
            tex.print("fill " .. path .. ";")
            end




              }}

            begin{document}

            begin{mplibcode}

            mpdefineoutlines{𝜋}

            end{mplibcode}

            end{document}


            Instead of using luamplib, we could also simply print the path to the log file and copy it to a MetaPost file. With some additonal formatting we get:



            prologues := 3;
            outputformat := "pdf";

            beginfig(1)
            fill (56.70,40.70)
            .. controls (56.70,43.10) and (54.60,43.10)
            .. (52.70,43.10)
            -- (19.20,43.10)
            .. controls (17,43.10) and (13.20,43.10)
            .. (8.80,38.40)
            .. controls (5.30,34.50) and (2.70,29.90)
            .. (2.70,29.40)
            .. controls (2.70,29.40) and (2.70,28.40)
            .. (3.90,28.40)
            .. controls (4.70,28.40) and (4.90,28.80)
            .. (5.50,29.60)
            .. controls (10.40,37.30) and (16.20,37.30)
            .. (18.20,37.30)
            -- (23.90,37.30)
            .. controls (20.70,25.20) and (15.30,13.10)
            .. (11.10,4)
            .. controls (10.30,2.50) and (10.30,2.30)
            .. (10.30,1.60)
            .. controls (10.30,-0.30) and (11.90,-1.10)
            .. (13.20,-1.10)
            .. controls (16.20,-1.10) and (17,1.70)
            .. (18.20,5.40)
            .. controls (19.60,10) and (19.60,10.20)
            .. (20.90,15.20)
            -- (26.50,37.30)
            -- (37.80,37.30)
            .. controls (34.50,22.50) and (33.60,18.20)
            .. (33.60,11.50)
            .. controls (33.60,10) and (33.60,7.30)
            .. (34.40,3.90)
            .. controls (35.40,-0.50) and (36.50,-1.10)
            .. (38,-1.10)
            .. controls (40,-1.10) and (42.10,0.70)
            .. (42.10,2.70)
            .. controls (42.10,3.30) and (42.10,3.50)
            .. (41.50,4.90)
            .. controls (38.60,12.10) and (38.60,18.60)
            .. (38.60,21.40)
            .. controls (38.60,26.70) and (39.30,32.10)
            .. (40.40,37.30)
            -- (51.80,37.30)
            .. controls (53.10,37.30) and (56.70,37.30)
            .. (56.70,40.70)
            -- cycle;
            endfig;
            end


            Or you can even use the path with TikZ.



            documentclass{article}

            usepackage{tikz}

            begin{document}

            begin{tikzpicture}[x=1pt,y=1pt]

            fill (56.70,40.70)
            .. controls (56.70,43.10) and (54.60,43.10)
            .. (52.70,43.10)
            -- (19.20,43.10)
            .. controls (17,43.10) and (13.20,43.10)
            .. (8.80,38.40)
            .. controls (5.30,34.50) and (2.70,29.90)
            .. (2.70,29.40)
            .. controls (2.70,29.40) and (2.70,28.40)
            .. (3.90,28.40)
            .. controls (4.70,28.40) and (4.90,28.80)
            .. (5.50,29.60)
            .. controls (10.40,37.30) and (16.20,37.30)
            .. (18.20,37.30)
            -- (23.90,37.30)
            .. controls (20.70,25.20) and (15.30,13.10)
            .. (11.10,4)
            .. controls (10.30,2.50) and (10.30,2.30)
            .. (10.30,1.60)
            .. controls (10.30,-0.30) and (11.90,-1.10)
            .. (13.20,-1.10)
            .. controls (16.20,-1.10) and (17,1.70)
            .. (18.20,5.40)
            .. controls (19.60,10) and (19.60,10.20)
            .. (20.90,15.20)
            -- (26.50,37.30)
            -- (37.80,37.30)
            .. controls (34.50,22.50) and (33.60,18.20)
            .. (33.60,11.50)
            .. controls (33.60,10) and (33.60,7.30)
            .. (34.40,3.90)
            .. controls (35.40,-0.50) and (36.50,-1.10)
            .. (38,-1.10)
            .. controls (40,-1.10) and (42.10,0.70)
            .. (42.10,2.70)
            .. controls (42.10,3.30) and (42.10,3.50)
            .. (41.50,4.90)
            .. controls (38.60,12.10) and (38.60,18.60)
            .. (38.60,21.40)
            .. controls (38.60,26.70) and (39.30,32.10)
            .. (40.40,37.30)
            -- (51.80,37.30)
            .. controls (53.10,37.30) and (56.70,37.30)
            .. (56.70,40.70)
            -- cycle;

            end{tikzpicture}

            end{document}


            The output is rather unspectacular.



            enter image description here






            share|improve this answer




























              4












              4








              4







              We could extract the MetaPost paths for the glyph pi from the font and draw it using LuaTeX.



              documentclass{article}

              usepackage{fontspec}
              setmainfont{latinmodern-math.otf}

              usepackage{luacode}
              begin{luacode*}


              -- We need some utilities from ConTeXt
              callbacks = callbacks or {}
              callbacks.supported = callbacks.supported or {}
              CONTEXTLMTXMODE = CONTEXTLMTXMODE or (status.obj_ptr == nil and 2 or 1)
              dofile(kpse.find_file("util-fmt.lua"))
              dofile(kpse.find_file("node-ini.lua"))
              dofile(kpse.find_file("font-mps.lua"))
              dofile(kpse.find_file("font-shp.lua"))

              -- That's a simple reimplemetation of ConTeXt's showshape macro
              function outlinepaths(character)
              local fontid = font.current()
              local shapedata = fonts.hashes.shapes[fontid] -- by index
              local chardata = fonts.hashes.characters[fontid] -- by unicode
              local shapeglyphs = shapedata.glyphs or { }

              character = utf.byte(character)
              local c = chardata[character]
              if c then
              if not c.index then
              return {}
              end
              local glyph = shapeglyphs[c.index]
              if glyph and (glyph.segments or glyph.sequence) then
              local units = shapedata.units or 1000
              local factor = 100/units
              local paths = fonts.metapost.paths(glyph,factor)
              return paths
              end
              end
              end




              end{luacode*}

              usepackage{luamplib}
              everymplib{beginfig(0);}
              everyendmplib{endfig;}

              defmpdefineoutlines#1{directlua{


                  local char = "luaescapestring{#1}"
              local outlines = outlinepaths("#1")
              for i, path in ipairs(outlines) do
              tex.print("fill " .. path .. ";")
              end




                }}

              begin{document}

              begin{mplibcode}

              mpdefineoutlines{𝜋}

              end{mplibcode}

              end{document}


              Instead of using luamplib, we could also simply print the path to the log file and copy it to a MetaPost file. With some additonal formatting we get:



              prologues := 3;
              outputformat := "pdf";

              beginfig(1)
              fill (56.70,40.70)
              .. controls (56.70,43.10) and (54.60,43.10)
              .. (52.70,43.10)
              -- (19.20,43.10)
              .. controls (17,43.10) and (13.20,43.10)
              .. (8.80,38.40)
              .. controls (5.30,34.50) and (2.70,29.90)
              .. (2.70,29.40)
              .. controls (2.70,29.40) and (2.70,28.40)
              .. (3.90,28.40)
              .. controls (4.70,28.40) and (4.90,28.80)
              .. (5.50,29.60)
              .. controls (10.40,37.30) and (16.20,37.30)
              .. (18.20,37.30)
              -- (23.90,37.30)
              .. controls (20.70,25.20) and (15.30,13.10)
              .. (11.10,4)
              .. controls (10.30,2.50) and (10.30,2.30)
              .. (10.30,1.60)
              .. controls (10.30,-0.30) and (11.90,-1.10)
              .. (13.20,-1.10)
              .. controls (16.20,-1.10) and (17,1.70)
              .. (18.20,5.40)
              .. controls (19.60,10) and (19.60,10.20)
              .. (20.90,15.20)
              -- (26.50,37.30)
              -- (37.80,37.30)
              .. controls (34.50,22.50) and (33.60,18.20)
              .. (33.60,11.50)
              .. controls (33.60,10) and (33.60,7.30)
              .. (34.40,3.90)
              .. controls (35.40,-0.50) and (36.50,-1.10)
              .. (38,-1.10)
              .. controls (40,-1.10) and (42.10,0.70)
              .. (42.10,2.70)
              .. controls (42.10,3.30) and (42.10,3.50)
              .. (41.50,4.90)
              .. controls (38.60,12.10) and (38.60,18.60)
              .. (38.60,21.40)
              .. controls (38.60,26.70) and (39.30,32.10)
              .. (40.40,37.30)
              -- (51.80,37.30)
              .. controls (53.10,37.30) and (56.70,37.30)
              .. (56.70,40.70)
              -- cycle;
              endfig;
              end


              Or you can even use the path with TikZ.



              documentclass{article}

              usepackage{tikz}

              begin{document}

              begin{tikzpicture}[x=1pt,y=1pt]

              fill (56.70,40.70)
              .. controls (56.70,43.10) and (54.60,43.10)
              .. (52.70,43.10)
              -- (19.20,43.10)
              .. controls (17,43.10) and (13.20,43.10)
              .. (8.80,38.40)
              .. controls (5.30,34.50) and (2.70,29.90)
              .. (2.70,29.40)
              .. controls (2.70,29.40) and (2.70,28.40)
              .. (3.90,28.40)
              .. controls (4.70,28.40) and (4.90,28.80)
              .. (5.50,29.60)
              .. controls (10.40,37.30) and (16.20,37.30)
              .. (18.20,37.30)
              -- (23.90,37.30)
              .. controls (20.70,25.20) and (15.30,13.10)
              .. (11.10,4)
              .. controls (10.30,2.50) and (10.30,2.30)
              .. (10.30,1.60)
              .. controls (10.30,-0.30) and (11.90,-1.10)
              .. (13.20,-1.10)
              .. controls (16.20,-1.10) and (17,1.70)
              .. (18.20,5.40)
              .. controls (19.60,10) and (19.60,10.20)
              .. (20.90,15.20)
              -- (26.50,37.30)
              -- (37.80,37.30)
              .. controls (34.50,22.50) and (33.60,18.20)
              .. (33.60,11.50)
              .. controls (33.60,10) and (33.60,7.30)
              .. (34.40,3.90)
              .. controls (35.40,-0.50) and (36.50,-1.10)
              .. (38,-1.10)
              .. controls (40,-1.10) and (42.10,0.70)
              .. (42.10,2.70)
              .. controls (42.10,3.30) and (42.10,3.50)
              .. (41.50,4.90)
              .. controls (38.60,12.10) and (38.60,18.60)
              .. (38.60,21.40)
              .. controls (38.60,26.70) and (39.30,32.10)
              .. (40.40,37.30)
              -- (51.80,37.30)
              .. controls (53.10,37.30) and (56.70,37.30)
              .. (56.70,40.70)
              -- cycle;

              end{tikzpicture}

              end{document}


              The output is rather unspectacular.



              enter image description here






              share|improve this answer















              We could extract the MetaPost paths for the glyph pi from the font and draw it using LuaTeX.



              documentclass{article}

              usepackage{fontspec}
              setmainfont{latinmodern-math.otf}

              usepackage{luacode}
              begin{luacode*}


              -- We need some utilities from ConTeXt
              callbacks = callbacks or {}
              callbacks.supported = callbacks.supported or {}
              CONTEXTLMTXMODE = CONTEXTLMTXMODE or (status.obj_ptr == nil and 2 or 1)
              dofile(kpse.find_file("util-fmt.lua"))
              dofile(kpse.find_file("node-ini.lua"))
              dofile(kpse.find_file("font-mps.lua"))
              dofile(kpse.find_file("font-shp.lua"))

              -- That's a simple reimplemetation of ConTeXt's showshape macro
              function outlinepaths(character)
              local fontid = font.current()
              local shapedata = fonts.hashes.shapes[fontid] -- by index
              local chardata = fonts.hashes.characters[fontid] -- by unicode
              local shapeglyphs = shapedata.glyphs or { }

              character = utf.byte(character)
              local c = chardata[character]
              if c then
              if not c.index then
              return {}
              end
              local glyph = shapeglyphs[c.index]
              if glyph and (glyph.segments or glyph.sequence) then
              local units = shapedata.units or 1000
              local factor = 100/units
              local paths = fonts.metapost.paths(glyph,factor)
              return paths
              end
              end
              end




              end{luacode*}

              usepackage{luamplib}
              everymplib{beginfig(0);}
              everyendmplib{endfig;}

              defmpdefineoutlines#1{directlua{


                  local char = "luaescapestring{#1}"
              local outlines = outlinepaths("#1")
              for i, path in ipairs(outlines) do
              tex.print("fill " .. path .. ";")
              end




                }}

              begin{document}

              begin{mplibcode}

              mpdefineoutlines{𝜋}

              end{mplibcode}

              end{document}


              Instead of using luamplib, we could also simply print the path to the log file and copy it to a MetaPost file. With some additonal formatting we get:



              prologues := 3;
              outputformat := "pdf";

              beginfig(1)
              fill (56.70,40.70)
              .. controls (56.70,43.10) and (54.60,43.10)
              .. (52.70,43.10)
              -- (19.20,43.10)
              .. controls (17,43.10) and (13.20,43.10)
              .. (8.80,38.40)
              .. controls (5.30,34.50) and (2.70,29.90)
              .. (2.70,29.40)
              .. controls (2.70,29.40) and (2.70,28.40)
              .. (3.90,28.40)
              .. controls (4.70,28.40) and (4.90,28.80)
              .. (5.50,29.60)
              .. controls (10.40,37.30) and (16.20,37.30)
              .. (18.20,37.30)
              -- (23.90,37.30)
              .. controls (20.70,25.20) and (15.30,13.10)
              .. (11.10,4)
              .. controls (10.30,2.50) and (10.30,2.30)
              .. (10.30,1.60)
              .. controls (10.30,-0.30) and (11.90,-1.10)
              .. (13.20,-1.10)
              .. controls (16.20,-1.10) and (17,1.70)
              .. (18.20,5.40)
              .. controls (19.60,10) and (19.60,10.20)
              .. (20.90,15.20)
              -- (26.50,37.30)
              -- (37.80,37.30)
              .. controls (34.50,22.50) and (33.60,18.20)
              .. (33.60,11.50)
              .. controls (33.60,10) and (33.60,7.30)
              .. (34.40,3.90)
              .. controls (35.40,-0.50) and (36.50,-1.10)
              .. (38,-1.10)
              .. controls (40,-1.10) and (42.10,0.70)
              .. (42.10,2.70)
              .. controls (42.10,3.30) and (42.10,3.50)
              .. (41.50,4.90)
              .. controls (38.60,12.10) and (38.60,18.60)
              .. (38.60,21.40)
              .. controls (38.60,26.70) and (39.30,32.10)
              .. (40.40,37.30)
              -- (51.80,37.30)
              .. controls (53.10,37.30) and (56.70,37.30)
              .. (56.70,40.70)
              -- cycle;
              endfig;
              end


              Or you can even use the path with TikZ.



              documentclass{article}

              usepackage{tikz}

              begin{document}

              begin{tikzpicture}[x=1pt,y=1pt]

              fill (56.70,40.70)
              .. controls (56.70,43.10) and (54.60,43.10)
              .. (52.70,43.10)
              -- (19.20,43.10)
              .. controls (17,43.10) and (13.20,43.10)
              .. (8.80,38.40)
              .. controls (5.30,34.50) and (2.70,29.90)
              .. (2.70,29.40)
              .. controls (2.70,29.40) and (2.70,28.40)
              .. (3.90,28.40)
              .. controls (4.70,28.40) and (4.90,28.80)
              .. (5.50,29.60)
              .. controls (10.40,37.30) and (16.20,37.30)
              .. (18.20,37.30)
              -- (23.90,37.30)
              .. controls (20.70,25.20) and (15.30,13.10)
              .. (11.10,4)
              .. controls (10.30,2.50) and (10.30,2.30)
              .. (10.30,1.60)
              .. controls (10.30,-0.30) and (11.90,-1.10)
              .. (13.20,-1.10)
              .. controls (16.20,-1.10) and (17,1.70)
              .. (18.20,5.40)
              .. controls (19.60,10) and (19.60,10.20)
              .. (20.90,15.20)
              -- (26.50,37.30)
              -- (37.80,37.30)
              .. controls (34.50,22.50) and (33.60,18.20)
              .. (33.60,11.50)
              .. controls (33.60,10) and (33.60,7.30)
              .. (34.40,3.90)
              .. controls (35.40,-0.50) and (36.50,-1.10)
              .. (38,-1.10)
              .. controls (40,-1.10) and (42.10,0.70)
              .. (42.10,2.70)
              .. controls (42.10,3.30) and (42.10,3.50)
              .. (41.50,4.90)
              .. controls (38.60,12.10) and (38.60,18.60)
              .. (38.60,21.40)
              .. controls (38.60,26.70) and (39.30,32.10)
              .. (40.40,37.30)
              -- (51.80,37.30)
              .. controls (53.10,37.30) and (56.70,37.30)
              .. (56.70,40.70)
              -- cycle;

              end{tikzpicture}

              end{document}


              The output is rather unspectacular.



              enter image description here







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 23 secs ago

























              answered 1 hour ago









              Henri MenkeHenri Menke

              76.5k8167282




              76.5k8167282























                  3














                  Writing π with the digits of π - using the verbatim environment.



                  enter image description here



                  documentclass{article}
                  linespread{0.7}
                  begin{document}
                  begin{verbatim}
                  3.141592653589793238462643383279
                  5028841971693993751058209749445923
                  07816406286208998628034825342117067
                  9821 48086 5132
                  823 06647 09384
                  46 09550 58223
                  17 25359 4081
                  2848 1117
                  4502 8410
                  2701 9385
                  21105 55964
                  46229 48954
                  9303 81964
                  4288 10975
                  66593 34461
                  284756 48233
                  78678 31652 71
                  2019091 456485 66
                  9234603 48610454326648
                  2133936 0726024914127
                  3724587 00660631558
                  817488 152092096
                  end{verbatim}
                  end{document}


                  Based on ascii art drawing by Jorel - https://www.flickr.com/photos/jorel314/3352784321/






                  share|improve this answer


























                  • How did you format the code? By trial/error?

                    – Sigur
                    2 hours ago











                  • @Sigur I did it by hand, but based off an ascii art drawing I found online. Added a reference to the original drawing.

                    – Milo
                    1 hour ago













                  • Nice. Though, not quite: you simply draw it rather than computing it :-).

                    – user49915
                    1 hour ago
















                  3














                  Writing π with the digits of π - using the verbatim environment.



                  enter image description here



                  documentclass{article}
                  linespread{0.7}
                  begin{document}
                  begin{verbatim}
                  3.141592653589793238462643383279
                  5028841971693993751058209749445923
                  07816406286208998628034825342117067
                  9821 48086 5132
                  823 06647 09384
                  46 09550 58223
                  17 25359 4081
                  2848 1117
                  4502 8410
                  2701 9385
                  21105 55964
                  46229 48954
                  9303 81964
                  4288 10975
                  66593 34461
                  284756 48233
                  78678 31652 71
                  2019091 456485 66
                  9234603 48610454326648
                  2133936 0726024914127
                  3724587 00660631558
                  817488 152092096
                  end{verbatim}
                  end{document}


                  Based on ascii art drawing by Jorel - https://www.flickr.com/photos/jorel314/3352784321/






                  share|improve this answer


























                  • How did you format the code? By trial/error?

                    – Sigur
                    2 hours ago











                  • @Sigur I did it by hand, but based off an ascii art drawing I found online. Added a reference to the original drawing.

                    – Milo
                    1 hour ago













                  • Nice. Though, not quite: you simply draw it rather than computing it :-).

                    – user49915
                    1 hour ago














                  3












                  3








                  3







                  Writing π with the digits of π - using the verbatim environment.



                  enter image description here



                  documentclass{article}
                  linespread{0.7}
                  begin{document}
                  begin{verbatim}
                  3.141592653589793238462643383279
                  5028841971693993751058209749445923
                  07816406286208998628034825342117067
                  9821 48086 5132
                  823 06647 09384
                  46 09550 58223
                  17 25359 4081
                  2848 1117
                  4502 8410
                  2701 9385
                  21105 55964
                  46229 48954
                  9303 81964
                  4288 10975
                  66593 34461
                  284756 48233
                  78678 31652 71
                  2019091 456485 66
                  9234603 48610454326648
                  2133936 0726024914127
                  3724587 00660631558
                  817488 152092096
                  end{verbatim}
                  end{document}


                  Based on ascii art drawing by Jorel - https://www.flickr.com/photos/jorel314/3352784321/






                  share|improve this answer















                  Writing π with the digits of π - using the verbatim environment.



                  enter image description here



                  documentclass{article}
                  linespread{0.7}
                  begin{document}
                  begin{verbatim}
                  3.141592653589793238462643383279
                  5028841971693993751058209749445923
                  07816406286208998628034825342117067
                  9821 48086 5132
                  823 06647 09384
                  46 09550 58223
                  17 25359 4081
                  2848 1117
                  4502 8410
                  2701 9385
                  21105 55964
                  46229 48954
                  9303 81964
                  4288 10975
                  66593 34461
                  284756 48233
                  78678 31652 71
                  2019091 456485 66
                  9234603 48610454326648
                  2133936 0726024914127
                  3724587 00660631558
                  817488 152092096
                  end{verbatim}
                  end{document}


                  Based on ascii art drawing by Jorel - https://www.flickr.com/photos/jorel314/3352784321/







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 1 hour ago

























                  answered 2 hours ago









                  MiloMilo

                  6,42221650




                  6,42221650













                  • How did you format the code? By trial/error?

                    – Sigur
                    2 hours ago











                  • @Sigur I did it by hand, but based off an ascii art drawing I found online. Added a reference to the original drawing.

                    – Milo
                    1 hour ago













                  • Nice. Though, not quite: you simply draw it rather than computing it :-).

                    – user49915
                    1 hour ago



















                  • How did you format the code? By trial/error?

                    – Sigur
                    2 hours ago











                  • @Sigur I did it by hand, but based off an ascii art drawing I found online. Added a reference to the original drawing.

                    – Milo
                    1 hour ago













                  • Nice. Though, not quite: you simply draw it rather than computing it :-).

                    – user49915
                    1 hour ago

















                  How did you format the code? By trial/error?

                  – Sigur
                  2 hours ago





                  How did you format the code? By trial/error?

                  – Sigur
                  2 hours ago













                  @Sigur I did it by hand, but based off an ascii art drawing I found online. Added a reference to the original drawing.

                  – Milo
                  1 hour ago







                  @Sigur I did it by hand, but based off an ascii art drawing I found online. Added a reference to the original drawing.

                  – Milo
                  1 hour ago















                  Nice. Though, not quite: you simply draw it rather than computing it :-).

                  – user49915
                  1 hour ago





                  Nice. Though, not quite: you simply draw it rather than computing it :-).

                  – user49915
                  1 hour ago











                  2














                  Happy pi(less) day!!



                  enter image description here



                  documentclass{report}
                  begin{document}
                  noindent%
                  rule{30pt}{1pt}\[-1pt]
                  rule{8pt}{0pt}%
                  rule{1pt}{30pt}%
                  rule{12pt}{0pt}%
                  rule{1pt}{30pt}
                  end{document}





                  share|improve this answer






























                    2














                    Happy pi(less) day!!



                    enter image description here



                    documentclass{report}
                    begin{document}
                    noindent%
                    rule{30pt}{1pt}\[-1pt]
                    rule{8pt}{0pt}%
                    rule{1pt}{30pt}%
                    rule{12pt}{0pt}%
                    rule{1pt}{30pt}
                    end{document}





                    share|improve this answer




























                      2












                      2








                      2







                      Happy pi(less) day!!



                      enter image description here



                      documentclass{report}
                      begin{document}
                      noindent%
                      rule{30pt}{1pt}\[-1pt]
                      rule{8pt}{0pt}%
                      rule{1pt}{30pt}%
                      rule{12pt}{0pt}%
                      rule{1pt}{30pt}
                      end{document}





                      share|improve this answer















                      Happy pi(less) day!!



                      enter image description here



                      documentclass{report}
                      begin{document}
                      noindent%
                      rule{30pt}{1pt}\[-1pt]
                      rule{8pt}{0pt}%
                      rule{1pt}{30pt}%
                      rule{12pt}{0pt}%
                      rule{1pt}{30pt}
                      end{document}






                      share|improve this answer














                      share|improve this answer



                      share|improve this answer








                      edited 2 hours ago

























                      answered 2 hours ago









                      SigurSigur

                      25.9k457140




                      25.9k457140























                          2














                          One should also honor Euler a bit.



                          documentclass[tikz,border=3.14mm]{standalone}
                          usepackage{tikzlings,amsmath}
                          makeatletter
                          tikzset{/thing/.cd,
                          pie/.code=thing@cheesetruedefthing@cheese{#1}, %<-pretend you didn't see that
                          pie/.default=pink!70!red}
                          makeatother
                          begin{document}
                          begin{tikzpicture}[font=sffamily]
                          marmot[pie,whiskers,teeth,shadow]
                          node[anchor=east,scale=5,transform shape] at (-0.6,1) {$picdotmathsf{e}=text{sffamily pie}$};
                          end{tikzpicture}
                          end{document}


                          enter image description here






                          share|improve this answer




























                            2














                            One should also honor Euler a bit.



                            documentclass[tikz,border=3.14mm]{standalone}
                            usepackage{tikzlings,amsmath}
                            makeatletter
                            tikzset{/thing/.cd,
                            pie/.code=thing@cheesetruedefthing@cheese{#1}, %<-pretend you didn't see that
                            pie/.default=pink!70!red}
                            makeatother
                            begin{document}
                            begin{tikzpicture}[font=sffamily]
                            marmot[pie,whiskers,teeth,shadow]
                            node[anchor=east,scale=5,transform shape] at (-0.6,1) {$picdotmathsf{e}=text{sffamily pie}$};
                            end{tikzpicture}
                            end{document}


                            enter image description here






                            share|improve this answer


























                              2












                              2








                              2







                              One should also honor Euler a bit.



                              documentclass[tikz,border=3.14mm]{standalone}
                              usepackage{tikzlings,amsmath}
                              makeatletter
                              tikzset{/thing/.cd,
                              pie/.code=thing@cheesetruedefthing@cheese{#1}, %<-pretend you didn't see that
                              pie/.default=pink!70!red}
                              makeatother
                              begin{document}
                              begin{tikzpicture}[font=sffamily]
                              marmot[pie,whiskers,teeth,shadow]
                              node[anchor=east,scale=5,transform shape] at (-0.6,1) {$picdotmathsf{e}=text{sffamily pie}$};
                              end{tikzpicture}
                              end{document}


                              enter image description here






                              share|improve this answer













                              One should also honor Euler a bit.



                              documentclass[tikz,border=3.14mm]{standalone}
                              usepackage{tikzlings,amsmath}
                              makeatletter
                              tikzset{/thing/.cd,
                              pie/.code=thing@cheesetruedefthing@cheese{#1}, %<-pretend you didn't see that
                              pie/.default=pink!70!red}
                              makeatother
                              begin{document}
                              begin{tikzpicture}[font=sffamily]
                              marmot[pie,whiskers,teeth,shadow]
                              node[anchor=east,scale=5,transform shape] at (-0.6,1) {$picdotmathsf{e}=text{sffamily pie}$};
                              end{tikzpicture}
                              end{document}


                              enter image description here







                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered 1 hour ago









                              marmotmarmot

                              108k5132249




                              108k5132249























                                  1














                                  The obligatory forest solution:



                                  documentclass{standalone}

                                  usepackage[edges]{forest}
                                  usetikzlibrary{calc}
                                  forestset{
                                  forked edge'/.style={
                                  edge={rotate/.option=!parent.grow},
                                  edge path'={(!u.parent anchor)++(0pt,-30pt) -- (!u.parent anchor)++(0pt,30pt) |- (.child anchor)},
                                  }
                                  }
                                  begin{document}
                                  Huge
                                  begin{forest}forked edges,for tree={edge={line width=4pt}}
                                  [ [ ] [ ]]
                                  end{forest}
                                  end{document}


                                  pi






                                  share|improve this answer




























                                    1














                                    The obligatory forest solution:



                                    documentclass{standalone}

                                    usepackage[edges]{forest}
                                    usetikzlibrary{calc}
                                    forestset{
                                    forked edge'/.style={
                                    edge={rotate/.option=!parent.grow},
                                    edge path'={(!u.parent anchor)++(0pt,-30pt) -- (!u.parent anchor)++(0pt,30pt) |- (.child anchor)},
                                    }
                                    }
                                    begin{document}
                                    Huge
                                    begin{forest}forked edges,for tree={edge={line width=4pt}}
                                    [ [ ] [ ]]
                                    end{forest}
                                    end{document}


                                    pi






                                    share|improve this answer


























                                      1












                                      1








                                      1







                                      The obligatory forest solution:



                                      documentclass{standalone}

                                      usepackage[edges]{forest}
                                      usetikzlibrary{calc}
                                      forestset{
                                      forked edge'/.style={
                                      edge={rotate/.option=!parent.grow},
                                      edge path'={(!u.parent anchor)++(0pt,-30pt) -- (!u.parent anchor)++(0pt,30pt) |- (.child anchor)},
                                      }
                                      }
                                      begin{document}
                                      Huge
                                      begin{forest}forked edges,for tree={edge={line width=4pt}}
                                      [ [ ] [ ]]
                                      end{forest}
                                      end{document}


                                      pi






                                      share|improve this answer













                                      The obligatory forest solution:



                                      documentclass{standalone}

                                      usepackage[edges]{forest}
                                      usetikzlibrary{calc}
                                      forestset{
                                      forked edge'/.style={
                                      edge={rotate/.option=!parent.grow},
                                      edge path'={(!u.parent anchor)++(0pt,-30pt) -- (!u.parent anchor)++(0pt,30pt) |- (.child anchor)},
                                      }
                                      }
                                      begin{document}
                                      Huge
                                      begin{forest}forked edges,for tree={edge={line width=4pt}}
                                      [ [ ] [ ]]
                                      end{forest}
                                      end{document}


                                      pi







                                      share|improve this answer












                                      share|improve this answer



                                      share|improve this answer










                                      answered 26 mins ago









                                      Alan MunnAlan Munn

                                      162k28432709




                                      162k28432709






























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