Use scp to copy files of specific extension from directory
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I'm writing a bash script that needs to fetch all *_out.csv from a directory, on a remote server. All these files are several directories deep inside of another directory. So for instance, say the directory is called ox_20190404/. I can find all my files by going:
find ox_20190404/assessment/LWR/validation -type f -name "*_out.csv"
This question answers part of my question, but since I don't want to copy the directory in it's entirety I need to figure out how to implement the above code. Suppose I start with this:
$ dir="/projects/ox/git"
$ server="myusername@server"
$ scp $server:$dir/$(ssh $server 'ls -t $dir | head -1') .
How would I grab the files I need from there?
The last part of my question wonders if there is a way to then take all the copied files and place them in the same file path and directory they were in on the remote server.
bash shell-script rsync scp
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dylanjm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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|
show 5 more comments
I'm writing a bash script that needs to fetch all *_out.csv from a directory, on a remote server. All these files are several directories deep inside of another directory. So for instance, say the directory is called ox_20190404/. I can find all my files by going:
find ox_20190404/assessment/LWR/validation -type f -name "*_out.csv"
This question answers part of my question, but since I don't want to copy the directory in it's entirety I need to figure out how to implement the above code. Suppose I start with this:
$ dir="/projects/ox/git"
$ server="myusername@server"
$ scp $server:$dir/$(ssh $server 'ls -t $dir | head -1') .
How would I grab the files I need from there?
The last part of my question wonders if there is a way to then take all the copied files and place them in the same file path and directory they were in on the remote server.
bash shell-script rsync scp
New contributor
dylanjm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
To clarify, you want the directory under $dir that has the most recent ... name? timestamp? You hard-codedox_20190404in the lead-up, so it's not clear how you selected it.
– Jeff Schaller♦
23 hours ago
@JeffSchaller Suppose I'm ssh'd into the server. If I typels -t /projects/ox/git | head -1thenox_20190404is the directory that is returned. I then want to go inside that folder and get the files from there.
– dylanjm
23 hours ago
iszshavailable on $server?
– Jeff Schaller♦
23 hours ago
@JeffSchaller It appears so, but it's not really setup (no .zshrc files).
– dylanjm
23 hours ago
and so the finalscpcommand would explicitly list all of the*_out.csvfiles underneath the most recent directory under$dirin order to be copied locally?
– Jeff Schaller♦
23 hours ago
|
show 5 more comments
I'm writing a bash script that needs to fetch all *_out.csv from a directory, on a remote server. All these files are several directories deep inside of another directory. So for instance, say the directory is called ox_20190404/. I can find all my files by going:
find ox_20190404/assessment/LWR/validation -type f -name "*_out.csv"
This question answers part of my question, but since I don't want to copy the directory in it's entirety I need to figure out how to implement the above code. Suppose I start with this:
$ dir="/projects/ox/git"
$ server="myusername@server"
$ scp $server:$dir/$(ssh $server 'ls -t $dir | head -1') .
How would I grab the files I need from there?
The last part of my question wonders if there is a way to then take all the copied files and place them in the same file path and directory they were in on the remote server.
bash shell-script rsync scp
New contributor
dylanjm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm writing a bash script that needs to fetch all *_out.csv from a directory, on a remote server. All these files are several directories deep inside of another directory. So for instance, say the directory is called ox_20190404/. I can find all my files by going:
find ox_20190404/assessment/LWR/validation -type f -name "*_out.csv"
This question answers part of my question, but since I don't want to copy the directory in it's entirety I need to figure out how to implement the above code. Suppose I start with this:
$ dir="/projects/ox/git"
$ server="myusername@server"
$ scp $server:$dir/$(ssh $server 'ls -t $dir | head -1') .
How would I grab the files I need from there?
The last part of my question wonders if there is a way to then take all the copied files and place them in the same file path and directory they were in on the remote server.
bash shell-script rsync scp
bash shell-script rsync scp
New contributor
dylanjm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
dylanjm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 30 mins ago
ctrl-alt-delor
12.4k42661
12.4k42661
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asked yesterday
dylanjmdylanjm
992
992
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dylanjm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
dylanjm is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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Check out our Code of Conduct.
To clarify, you want the directory under $dir that has the most recent ... name? timestamp? You hard-codedox_20190404in the lead-up, so it's not clear how you selected it.
– Jeff Schaller♦
23 hours ago
@JeffSchaller Suppose I'm ssh'd into the server. If I typels -t /projects/ox/git | head -1thenox_20190404is the directory that is returned. I then want to go inside that folder and get the files from there.
– dylanjm
23 hours ago
iszshavailable on $server?
– Jeff Schaller♦
23 hours ago
@JeffSchaller It appears so, but it's not really setup (no .zshrc files).
– dylanjm
23 hours ago
and so the finalscpcommand would explicitly list all of the*_out.csvfiles underneath the most recent directory under$dirin order to be copied locally?
– Jeff Schaller♦
23 hours ago
|
show 5 more comments
To clarify, you want the directory under $dir that has the most recent ... name? timestamp? You hard-codedox_20190404in the lead-up, so it's not clear how you selected it.
– Jeff Schaller♦
23 hours ago
@JeffSchaller Suppose I'm ssh'd into the server. If I typels -t /projects/ox/git | head -1thenox_20190404is the directory that is returned. I then want to go inside that folder and get the files from there.
– dylanjm
23 hours ago
iszshavailable on $server?
– Jeff Schaller♦
23 hours ago
@JeffSchaller It appears so, but it's not really setup (no .zshrc files).
– dylanjm
23 hours ago
and so the finalscpcommand would explicitly list all of the*_out.csvfiles underneath the most recent directory under$dirin order to be copied locally?
– Jeff Schaller♦
23 hours ago
To clarify, you want the directory under $dir that has the most recent ... name? timestamp? You hard-coded
ox_20190404 in the lead-up, so it's not clear how you selected it.– Jeff Schaller♦
23 hours ago
To clarify, you want the directory under $dir that has the most recent ... name? timestamp? You hard-coded
ox_20190404 in the lead-up, so it's not clear how you selected it.– Jeff Schaller♦
23 hours ago
@JeffSchaller Suppose I'm ssh'd into the server. If I type
ls -t /projects/ox/git | head -1 then ox_20190404 is the directory that is returned. I then want to go inside that folder and get the files from there.– dylanjm
23 hours ago
@JeffSchaller Suppose I'm ssh'd into the server. If I type
ls -t /projects/ox/git | head -1 then ox_20190404 is the directory that is returned. I then want to go inside that folder and get the files from there.– dylanjm
23 hours ago
is
zsh available on $server?– Jeff Schaller♦
23 hours ago
is
zsh available on $server?– Jeff Schaller♦
23 hours ago
@JeffSchaller It appears so, but it's not really setup (no .zshrc files).
– dylanjm
23 hours ago
@JeffSchaller It appears so, but it's not really setup (no .zshrc files).
– dylanjm
23 hours ago
and so the final
scp command would explicitly list all of the *_out.csv files underneath the most recent directory under $dir in order to be copied locally?– Jeff Schaller♦
23 hours ago
and so the final
scp command would explicitly list all of the *_out.csv files underneath the most recent directory under $dir in order to be copied locally?– Jeff Schaller♦
23 hours ago
|
show 5 more comments
2 Answers
2
active
oldest
votes
I've adjusted some of your variable names a bit.
Surely there are better ways to do this than something dangerous like parsing the output of ls, but see whether this works for you:
$ pth="/projects/ox/git"
$ server="myusername@server"
$ dir="$(ssh $server "ls -t "$pth" | head -1")"
$ mkdir -p "$pth/$dir"
$ scp -p $server:"$pth/$dir"/'*_out.csv' "$pth/$dir"/
Once dir has been set to the newest remote directory, mkdir -p is used to ensure that the same directory name exists locally. Then scp the files into a local directory with the same path and name as the remote directory. I was looking for an rsync solution, but couldn't think of one.
add a comment |
This will find the most recently modified (created) directory, assuming that the directory name does not contain a newline (n)
newest=$(
ssh -qn REMOTE 'find ./* -mindepth 0 -maxdepth 0 -type d -printf "%T@t%fn"' |
sort -t$'t' -r -nk1,2 |
head -n1 |
cut -f2-
)
If you can guarantee that the target contains only directories of interest you can simplify it considerably (again, bearing in mind the newline issue)
newest=$(ssh -qn REMOTE ls -t | head -n1)
You can copy an entire tree of files using scp, but if you want to filter it you'll probably be better off using rsync
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE:"$newest" "$newest"
If you're keeping the previous set of files locally and you really just wanted to add the latest set without copying the previous ones, rsync can do that too
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE: .
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
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oldest
votes
I've adjusted some of your variable names a bit.
Surely there are better ways to do this than something dangerous like parsing the output of ls, but see whether this works for you:
$ pth="/projects/ox/git"
$ server="myusername@server"
$ dir="$(ssh $server "ls -t "$pth" | head -1")"
$ mkdir -p "$pth/$dir"
$ scp -p $server:"$pth/$dir"/'*_out.csv' "$pth/$dir"/
Once dir has been set to the newest remote directory, mkdir -p is used to ensure that the same directory name exists locally. Then scp the files into a local directory with the same path and name as the remote directory. I was looking for an rsync solution, but couldn't think of one.
add a comment |
I've adjusted some of your variable names a bit.
Surely there are better ways to do this than something dangerous like parsing the output of ls, but see whether this works for you:
$ pth="/projects/ox/git"
$ server="myusername@server"
$ dir="$(ssh $server "ls -t "$pth" | head -1")"
$ mkdir -p "$pth/$dir"
$ scp -p $server:"$pth/$dir"/'*_out.csv' "$pth/$dir"/
Once dir has been set to the newest remote directory, mkdir -p is used to ensure that the same directory name exists locally. Then scp the files into a local directory with the same path and name as the remote directory. I was looking for an rsync solution, but couldn't think of one.
add a comment |
I've adjusted some of your variable names a bit.
Surely there are better ways to do this than something dangerous like parsing the output of ls, but see whether this works for you:
$ pth="/projects/ox/git"
$ server="myusername@server"
$ dir="$(ssh $server "ls -t "$pth" | head -1")"
$ mkdir -p "$pth/$dir"
$ scp -p $server:"$pth/$dir"/'*_out.csv' "$pth/$dir"/
Once dir has been set to the newest remote directory, mkdir -p is used to ensure that the same directory name exists locally. Then scp the files into a local directory with the same path and name as the remote directory. I was looking for an rsync solution, but couldn't think of one.
I've adjusted some of your variable names a bit.
Surely there are better ways to do this than something dangerous like parsing the output of ls, but see whether this works for you:
$ pth="/projects/ox/git"
$ server="myusername@server"
$ dir="$(ssh $server "ls -t "$pth" | head -1")"
$ mkdir -p "$pth/$dir"
$ scp -p $server:"$pth/$dir"/'*_out.csv' "$pth/$dir"/
Once dir has been set to the newest remote directory, mkdir -p is used to ensure that the same directory name exists locally. Then scp the files into a local directory with the same path and name as the remote directory. I was looking for an rsync solution, but couldn't think of one.
answered 22 hours ago
Jim L.Jim L.
1413
1413
add a comment |
add a comment |
This will find the most recently modified (created) directory, assuming that the directory name does not contain a newline (n)
newest=$(
ssh -qn REMOTE 'find ./* -mindepth 0 -maxdepth 0 -type d -printf "%T@t%fn"' |
sort -t$'t' -r -nk1,2 |
head -n1 |
cut -f2-
)
If you can guarantee that the target contains only directories of interest you can simplify it considerably (again, bearing in mind the newline issue)
newest=$(ssh -qn REMOTE ls -t | head -n1)
You can copy an entire tree of files using scp, but if you want to filter it you'll probably be better off using rsync
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE:"$newest" "$newest"
If you're keeping the previous set of files locally and you really just wanted to add the latest set without copying the previous ones, rsync can do that too
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE: .
add a comment |
This will find the most recently modified (created) directory, assuming that the directory name does not contain a newline (n)
newest=$(
ssh -qn REMOTE 'find ./* -mindepth 0 -maxdepth 0 -type d -printf "%T@t%fn"' |
sort -t$'t' -r -nk1,2 |
head -n1 |
cut -f2-
)
If you can guarantee that the target contains only directories of interest you can simplify it considerably (again, bearing in mind the newline issue)
newest=$(ssh -qn REMOTE ls -t | head -n1)
You can copy an entire tree of files using scp, but if you want to filter it you'll probably be better off using rsync
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE:"$newest" "$newest"
If you're keeping the previous set of files locally and you really just wanted to add the latest set without copying the previous ones, rsync can do that too
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE: .
add a comment |
This will find the most recently modified (created) directory, assuming that the directory name does not contain a newline (n)
newest=$(
ssh -qn REMOTE 'find ./* -mindepth 0 -maxdepth 0 -type d -printf "%T@t%fn"' |
sort -t$'t' -r -nk1,2 |
head -n1 |
cut -f2-
)
If you can guarantee that the target contains only directories of interest you can simplify it considerably (again, bearing in mind the newline issue)
newest=$(ssh -qn REMOTE ls -t | head -n1)
You can copy an entire tree of files using scp, but if you want to filter it you'll probably be better off using rsync
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE:"$newest" "$newest"
If you're keeping the previous set of files locally and you really just wanted to add the latest set without copying the previous ones, rsync can do that too
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE: .
This will find the most recently modified (created) directory, assuming that the directory name does not contain a newline (n)
newest=$(
ssh -qn REMOTE 'find ./* -mindepth 0 -maxdepth 0 -type d -printf "%T@t%fn"' |
sort -t$'t' -r -nk1,2 |
head -n1 |
cut -f2-
)
If you can guarantee that the target contains only directories of interest you can simplify it considerably (again, bearing in mind the newline issue)
newest=$(ssh -qn REMOTE ls -t | head -n1)
You can copy an entire tree of files using scp, but if you want to filter it you'll probably be better off using rsync
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE:"$newest" "$newest"
If you're keeping the previous set of files locally and you really just wanted to add the latest set without copying the previous ones, rsync can do that too
rsync -av --include '*/' --include '*_out.csv' --exclude '*' --prune-empty-dirs REMOTE: .
edited 21 hours ago
answered 22 hours ago
roaimaroaima
46k758124
46k758124
add a comment |
add a comment |
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dylanjm is a new contributor. Be nice, and check out our Code of Conduct.
dylanjm is a new contributor. Be nice, and check out our Code of Conduct.
dylanjm is a new contributor. Be nice, and check out our Code of Conduct.
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To clarify, you want the directory under $dir that has the most recent ... name? timestamp? You hard-coded
ox_20190404in the lead-up, so it's not clear how you selected it.– Jeff Schaller♦
23 hours ago
@JeffSchaller Suppose I'm ssh'd into the server. If I type
ls -t /projects/ox/git | head -1thenox_20190404is the directory that is returned. I then want to go inside that folder and get the files from there.– dylanjm
23 hours ago
is
zshavailable on $server?– Jeff Schaller♦
23 hours ago
@JeffSchaller It appears so, but it's not really setup (no .zshrc files).
– dylanjm
23 hours ago
and so the final
scpcommand would explicitly list all of the*_out.csvfiles underneath the most recent directory under$dirin order to be copied locally?– Jeff Schaller♦
23 hours ago