Yrurtj

In a bash script I need various values from /proc/ files. Until now I have dozens of lines grepping the files directly like that:

grep -oP '^MemFree: *K[0-9]+' /proc/meminfo

In an effort to make that more efficient I saved the file content in a variable and grepped that:

a=$(</proc/meminfo)

echo "$a" | grep -oP '^MemFree: *K[0-9]+'

Instead of opening the file multiple times this should just open it once and grep the variable content, which I assumed would be faster – but in fact it is slower:

bash 4.4.19 $ time for i in {1..1000};do grep ^MemFree /proc/meminfo;done >/dev/null

real    0m0.803s

user    0m0.619s

sys     0m0.232s

bash 4.4.19 $ a=$(</proc/meminfo)

bash 4.4.19 $ time for i in {1..1000};do echo "$a"|grep ^MemFree; done >/dev/null

real    0m1.182s

user    0m1.425s

sys     0m0.506s

The same is true for dash and zsh. I suspected the special state of /proc/ files as a reason, but when I copy the content of /proc/meminfo to a regular file and use that the results are the same:

bash 4.4.19 $ cat </proc/meminfo >meminfo

bash 4.4.19 $ time for i in $(seq 1 1000);do grep ^MemFree meminfo; done >/dev/null

real    0m0.790s

user    0m0.608s

sys     0m0.227s

Using a here string to save the pipe makes it slightly faster, but still not as fast as with the files:

bash 4.4.19 $ time for i in $(seq 1 1000);do <<<"$a" grep ^MemFree; done >/dev/null

real    0m0.977s

user    0m0.758s

sys     0m0.268s

Why is opening a file faster than reading the same content from a variable?

grep -oP '^MemFree: *K[0-9]+' /proc/meminfo forks a process that executes grep that opens /proc/meminfo (a virtual file, in memory, no disk I/O involved) reads it and matches the regexp.

The most expensive part in that is forking the process and loading the grep utility and its library dependencies, doing the dynamic linking, open the locale database, dozens of files that are on disk (but likely cached in memory).

The part about reading /proc/meminfo is insignificant in comparison, the kernel needs little time to generate the information in there and grep needs little time to read it.

In:

a=$(</proc/meminfo)

In most shells that support that $(<...) ksh operator, the shell just opens the file and read its content (and strips the trailing newline characters). bash is different and much less efficient in that it forks a process to do that reading and passes the data to the parent via a pipe. But here, it's done once so it doesn't matter.

In:

printf '%sn' "$a" | grep '^MemFree'

The shell needs to spawn two processes, which are running concurrently but interact between each other via a pipe. That pipe creation, tearing down, and writing and reading from it has some little cost. The much greater cost is the spawning of an extra process. The scheduling of the processes has some impact as well.

You may find that using the zsh <<< operator makes it slightly quicker:

grep '^MemFree' <<< "$a"

In zsh and bash, that's done by writing the content of $a in a temporary file, that is less expensive than spawning an extra process, but will probably not give you any gain compared to getting the data straight off /proc/meminfo. That's still less efficient than your approach that copies /proc/meminfo on disk, as the writing of the temp file is done at each iteration.

dash doesn't support here-strings, but its heredocs are implemented with a pipe that doesn't involve spawning an extra process. In:

 grep '^MemFree' << EOF

 $a

 EOF

The shell creates a pipe, forks a process. The child executes grep with its stdin as the reading end of the pipe, and the parent writes the content at the other end of the pipe.

But that pipe handling and process synchronisation is still likely to be more expensive than just getting the data straight off /proc/meminfo.

The content of /proc/meminfo is short and takes not much time to produce. If you want to save some CPU cycles, you want to remove the expensive parts: forking processes and running external commands.

Like:

IFS= read -rd '' meminfo < /proc/meminfo

memfree=${meminfo#*MemFree:}

memfree=${memfree%%$'n'*}

memfree=${memfree#"${memfree%%[! ]*}"}

Avoid bash though whose pattern matching is very ineficient. With zsh -o extendedglob, you can shorten it to:

memfree=${${"$(</proc/meminfo)"##*MemFree: #}%%$'n'*}

Note that ^ is special in many shells (Bourne, fish, rc, es and zsh with the extendedglob option at least), I'd recommend quoting it. Also note that echo can't be used to output arbitrary data (hence my use of printf above).

In your first case you are just using grep utility and finding something from file /proc/meminfo, /proc is a virtual file system so /proc/meminfo file is in the memory, and it requires very little time to fetch its content.

But in the second case, you are creating a pipe, then passing the first command's output to the second command using this pipe, which is costly.

The difference is because of /proc (because it is in memory) and pipe, see the example below:

time for i in {1..1000};do grep ^MemFree /proc/meminfo;done >/dev/null



real    0m0.914s

user    0m0.032s

sys     0m0.148s





cat /proc/meminfo > file

time for i in {1..1000};do grep ^MemFree file;done >/dev/null



real    0m0.938s

user    0m0.032s

sys     0m0.152s





time for i in {1..1000};do echo "$a"|grep ^MemFree; done >/dev/null



real    0m1.016s

user    0m0.040s

sys     0m0.232s