How to read dd/mm/yyyy date string in date -d UNIX command?












0















I am trying to dynamically convert one column in text file containing date in dd/mm/yyyy hh:mm:ss format to yy-mm-dd hh:mm:ss. Following command is working but giving output in yy-dd-mm and NOT yy-mm-dd as I need.



echo $(date -d "8/11/2018 06:20:57 AM" "+%y-%m-%d %H:%M:%S")



Output:



18-08-11 06:20:57



Moreover, this is not working for dates > 12 as it is treating first digit as month not date as below:



echo $(date -d "28/11/2018 06:20:57 AM" "+%y-%m-%d %H:%M:%S")



Output:



date: invalid date ‘28/11/2018 06:20:57 AM’



Is there any way to make it work?










share|improve this question









New contributor




Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • 2





    date is very flexible on the output but the input is very specific. I'd suggest to transform the date before reaching date. May be bring in them from SQL functions or Javascript (depending on the source). If there is no source (like from a file), I'd suggest sed or awk

    – Juan
    1 hour ago











  • ... or use something like Perl's Time::Piece with its strptime/strftime implementations

    – steeldriver
    1 hour ago











  • or php -r "command" ...

    – Juan
    1 hour ago
















0















I am trying to dynamically convert one column in text file containing date in dd/mm/yyyy hh:mm:ss format to yy-mm-dd hh:mm:ss. Following command is working but giving output in yy-dd-mm and NOT yy-mm-dd as I need.



echo $(date -d "8/11/2018 06:20:57 AM" "+%y-%m-%d %H:%M:%S")



Output:



18-08-11 06:20:57



Moreover, this is not working for dates > 12 as it is treating first digit as month not date as below:



echo $(date -d "28/11/2018 06:20:57 AM" "+%y-%m-%d %H:%M:%S")



Output:



date: invalid date ‘28/11/2018 06:20:57 AM’



Is there any way to make it work?










share|improve this question









New contributor




Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 2





    date is very flexible on the output but the input is very specific. I'd suggest to transform the date before reaching date. May be bring in them from SQL functions or Javascript (depending on the source). If there is no source (like from a file), I'd suggest sed or awk

    – Juan
    1 hour ago











  • ... or use something like Perl's Time::Piece with its strptime/strftime implementations

    – steeldriver
    1 hour ago











  • or php -r "command" ...

    – Juan
    1 hour ago














0












0








0








I am trying to dynamically convert one column in text file containing date in dd/mm/yyyy hh:mm:ss format to yy-mm-dd hh:mm:ss. Following command is working but giving output in yy-dd-mm and NOT yy-mm-dd as I need.



echo $(date -d "8/11/2018 06:20:57 AM" "+%y-%m-%d %H:%M:%S")



Output:



18-08-11 06:20:57



Moreover, this is not working for dates > 12 as it is treating first digit as month not date as below:



echo $(date -d "28/11/2018 06:20:57 AM" "+%y-%m-%d %H:%M:%S")



Output:



date: invalid date ‘28/11/2018 06:20:57 AM’



Is there any way to make it work?










share|improve this question









New contributor




Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I am trying to dynamically convert one column in text file containing date in dd/mm/yyyy hh:mm:ss format to yy-mm-dd hh:mm:ss. Following command is working but giving output in yy-dd-mm and NOT yy-mm-dd as I need.



echo $(date -d "8/11/2018 06:20:57 AM" "+%y-%m-%d %H:%M:%S")



Output:



18-08-11 06:20:57



Moreover, this is not working for dates > 12 as it is treating first digit as month not date as below:



echo $(date -d "28/11/2018 06:20:57 AM" "+%y-%m-%d %H:%M:%S")



Output:



date: invalid date ‘28/11/2018 06:20:57 AM’



Is there any way to make it work?







shell-script date






share|improve this question









New contributor




Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 1 hour ago









Jeff Schaller

43.8k1161141




43.8k1161141






New contributor




Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 1 hour ago









Deepak MalhotraDeepak Malhotra

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31




New contributor




Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Deepak Malhotra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 2





    date is very flexible on the output but the input is very specific. I'd suggest to transform the date before reaching date. May be bring in them from SQL functions or Javascript (depending on the source). If there is no source (like from a file), I'd suggest sed or awk

    – Juan
    1 hour ago











  • ... or use something like Perl's Time::Piece with its strptime/strftime implementations

    – steeldriver
    1 hour ago











  • or php -r "command" ...

    – Juan
    1 hour ago














  • 2





    date is very flexible on the output but the input is very specific. I'd suggest to transform the date before reaching date. May be bring in them from SQL functions or Javascript (depending on the source). If there is no source (like from a file), I'd suggest sed or awk

    – Juan
    1 hour ago











  • ... or use something like Perl's Time::Piece with its strptime/strftime implementations

    – steeldriver
    1 hour ago











  • or php -r "command" ...

    – Juan
    1 hour ago








2




2





date is very flexible on the output but the input is very specific. I'd suggest to transform the date before reaching date. May be bring in them from SQL functions or Javascript (depending on the source). If there is no source (like from a file), I'd suggest sed or awk

– Juan
1 hour ago





date is very flexible on the output but the input is very specific. I'd suggest to transform the date before reaching date. May be bring in them from SQL functions or Javascript (depending on the source). If there is no source (like from a file), I'd suggest sed or awk

– Juan
1 hour ago













... or use something like Perl's Time::Piece with its strptime/strftime implementations

– steeldriver
1 hour ago





... or use something like Perl's Time::Piece with its strptime/strftime implementations

– steeldriver
1 hour ago













or php -r "command" ...

– Juan
1 hour ago





or php -r "command" ...

– Juan
1 hour ago










1 Answer
1






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oldest

votes


















0














You might want to pre processes it first. My best shot is with sed



echo "28/11/2018 06:20:57 PM" | sed -E "s/([0-9]+)/([0-9]+)/([0-9]+) ([0-9]+):([0-9]+):([0-9]+) ([APM]{2})/3/2/1 4:5:6 7/g" | xargs -I II date -d II "+%y-%m-%d %H:%M:%S"






share|improve this answer
























  • Great ! It works, Thank you so much . :) I used date because I had multiple column with dates different format in every column , it was working fine for other columns except this column because it has different date format with PM and AM in it.

    – Deepak Malhotra
    23 mins ago











  • You are welcome. Don't forget to vote up ;)

    – Juan
    20 mins ago











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1 Answer
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1 Answer
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active

oldest

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active

oldest

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active

oldest

votes









0














You might want to pre processes it first. My best shot is with sed



echo "28/11/2018 06:20:57 PM" | sed -E "s/([0-9]+)/([0-9]+)/([0-9]+) ([0-9]+):([0-9]+):([0-9]+) ([APM]{2})/3/2/1 4:5:6 7/g" | xargs -I II date -d II "+%y-%m-%d %H:%M:%S"






share|improve this answer
























  • Great ! It works, Thank you so much . :) I used date because I had multiple column with dates different format in every column , it was working fine for other columns except this column because it has different date format with PM and AM in it.

    – Deepak Malhotra
    23 mins ago











  • You are welcome. Don't forget to vote up ;)

    – Juan
    20 mins ago
















0














You might want to pre processes it first. My best shot is with sed



echo "28/11/2018 06:20:57 PM" | sed -E "s/([0-9]+)/([0-9]+)/([0-9]+) ([0-9]+):([0-9]+):([0-9]+) ([APM]{2})/3/2/1 4:5:6 7/g" | xargs -I II date -d II "+%y-%m-%d %H:%M:%S"






share|improve this answer
























  • Great ! It works, Thank you so much . :) I used date because I had multiple column with dates different format in every column , it was working fine for other columns except this column because it has different date format with PM and AM in it.

    – Deepak Malhotra
    23 mins ago











  • You are welcome. Don't forget to vote up ;)

    – Juan
    20 mins ago














0












0








0







You might want to pre processes it first. My best shot is with sed



echo "28/11/2018 06:20:57 PM" | sed -E "s/([0-9]+)/([0-9]+)/([0-9]+) ([0-9]+):([0-9]+):([0-9]+) ([APM]{2})/3/2/1 4:5:6 7/g" | xargs -I II date -d II "+%y-%m-%d %H:%M:%S"






share|improve this answer













You might want to pre processes it first. My best shot is with sed



echo "28/11/2018 06:20:57 PM" | sed -E "s/([0-9]+)/([0-9]+)/([0-9]+) ([0-9]+):([0-9]+):([0-9]+) ([APM]{2})/3/2/1 4:5:6 7/g" | xargs -I II date -d II "+%y-%m-%d %H:%M:%S"







share|improve this answer












share|improve this answer



share|improve this answer










answered 56 mins ago









JuanJuan

201110




201110













  • Great ! It works, Thank you so much . :) I used date because I had multiple column with dates different format in every column , it was working fine for other columns except this column because it has different date format with PM and AM in it.

    – Deepak Malhotra
    23 mins ago











  • You are welcome. Don't forget to vote up ;)

    – Juan
    20 mins ago



















  • Great ! It works, Thank you so much . :) I used date because I had multiple column with dates different format in every column , it was working fine for other columns except this column because it has different date format with PM and AM in it.

    – Deepak Malhotra
    23 mins ago











  • You are welcome. Don't forget to vote up ;)

    – Juan
    20 mins ago

















Great ! It works, Thank you so much . :) I used date because I had multiple column with dates different format in every column , it was working fine for other columns except this column because it has different date format with PM and AM in it.

– Deepak Malhotra
23 mins ago





Great ! It works, Thank you so much . :) I used date because I had multiple column with dates different format in every column , it was working fine for other columns except this column because it has different date format with PM and AM in it.

– Deepak Malhotra
23 mins ago













You are welcome. Don't forget to vote up ;)

– Juan
20 mins ago





You are welcome. Don't forget to vote up ;)

– Juan
20 mins ago










Deepak Malhotra is a new contributor. Be nice, and check out our Code of Conduct.










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