Using sed to replace a character before another character in a line
I try to use sed or whatever to replace a number of a line /opt/tin/toss to become a *
For example
37 7 * * * /opt/tin/toss
43 7 * * * /opt/tin/te1
58 7 * * * /opt/tin/test2
Output:
37 * * * * /opt/tin/toss
43 7 * * * /opt/tin/te1
58 7 * * * /opt/tin/test2
Normally, 7 generates randomly, It can be 2, 4 or 8, running from 0-24.
Could anyone please help me? Thank you.
shell-script
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I try to use sed or whatever to replace a number of a line /opt/tin/toss to become a *
For example
37 7 * * * /opt/tin/toss
43 7 * * * /opt/tin/te1
58 7 * * * /opt/tin/test2
Output:
37 * * * * /opt/tin/toss
43 7 * * * /opt/tin/te1
58 7 * * * /opt/tin/test2
Normally, 7 generates randomly, It can be 2, 4 or 8, running from 0-24.
Could anyone please help me? Thank you.
shell-script
New contributor
add a comment |
I try to use sed or whatever to replace a number of a line /opt/tin/toss to become a *
For example
37 7 * * * /opt/tin/toss
43 7 * * * /opt/tin/te1
58 7 * * * /opt/tin/test2
Output:
37 * * * * /opt/tin/toss
43 7 * * * /opt/tin/te1
58 7 * * * /opt/tin/test2
Normally, 7 generates randomly, It can be 2, 4 or 8, running from 0-24.
Could anyone please help me? Thank you.
shell-script
New contributor
I try to use sed or whatever to replace a number of a line /opt/tin/toss to become a *
For example
37 7 * * * /opt/tin/toss
43 7 * * * /opt/tin/te1
58 7 * * * /opt/tin/test2
Output:
37 * * * * /opt/tin/toss
43 7 * * * /opt/tin/te1
58 7 * * * /opt/tin/test2
Normally, 7 generates randomly, It can be 2, 4 or 8, running from 0-24.
Could anyone please help me? Thank you.
shell-script
shell-script
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asked 3 mins ago
Quang NgôQuang Ngô
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Quang Ngô is a new contributor. Be nice, and check out our Code of Conduct.
Quang Ngô is a new contributor. Be nice, and check out our Code of Conduct.
Quang Ngô is a new contributor. Be nice, and check out our Code of Conduct.
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