Recursively find directories but do not print subdirectories of matches
Considering the following directory structure:
dir1
[domain.com] foo dir1
subdir1
subdir2
FooFile
dir2
[domain.com] foo dir2
subdir3
[domain.com] foo dir3
subdir4
subdir5
subdir6
subdir7
[domain.com] foo dir4
subdir8
I'd like to list all dirs with names that contain [domain.com]
.
Desired output:
[domain.com] foo dir1
[domain.com] foo dir2
[domain.com] foo dir3
[domain.com] foo dir4
I'm having a hard time putting this together. The closest I have come:
find . -type d -regextype posix-egrep -regex ".*/([domain.com]).+" -exec basename {} ;
But this outputs subdirectories as well:
[domain.com] foo dir3
subdir5
subdir4
[domain.com] foo dir2
[domain.com] foo dir4
subdir8
[domain.com] foo dir1
subdir1
shell find
New contributor
add a comment |
Considering the following directory structure:
dir1
[domain.com] foo dir1
subdir1
subdir2
FooFile
dir2
[domain.com] foo dir2
subdir3
[domain.com] foo dir3
subdir4
subdir5
subdir6
subdir7
[domain.com] foo dir4
subdir8
I'd like to list all dirs with names that contain [domain.com]
.
Desired output:
[domain.com] foo dir1
[domain.com] foo dir2
[domain.com] foo dir3
[domain.com] foo dir4
I'm having a hard time putting this together. The closest I have come:
find . -type d -regextype posix-egrep -regex ".*/([domain.com]).+" -exec basename {} ;
But this outputs subdirectories as well:
[domain.com] foo dir3
subdir5
subdir4
[domain.com] foo dir2
[domain.com] foo dir4
subdir8
[domain.com] foo dir1
subdir1
shell find
New contributor
add a comment |
Considering the following directory structure:
dir1
[domain.com] foo dir1
subdir1
subdir2
FooFile
dir2
[domain.com] foo dir2
subdir3
[domain.com] foo dir3
subdir4
subdir5
subdir6
subdir7
[domain.com] foo dir4
subdir8
I'd like to list all dirs with names that contain [domain.com]
.
Desired output:
[domain.com] foo dir1
[domain.com] foo dir2
[domain.com] foo dir3
[domain.com] foo dir4
I'm having a hard time putting this together. The closest I have come:
find . -type d -regextype posix-egrep -regex ".*/([domain.com]).+" -exec basename {} ;
But this outputs subdirectories as well:
[domain.com] foo dir3
subdir5
subdir4
[domain.com] foo dir2
[domain.com] foo dir4
subdir8
[domain.com] foo dir1
subdir1
shell find
New contributor
Considering the following directory structure:
dir1
[domain.com] foo dir1
subdir1
subdir2
FooFile
dir2
[domain.com] foo dir2
subdir3
[domain.com] foo dir3
subdir4
subdir5
subdir6
subdir7
[domain.com] foo dir4
subdir8
I'd like to list all dirs with names that contain [domain.com]
.
Desired output:
[domain.com] foo dir1
[domain.com] foo dir2
[domain.com] foo dir3
[domain.com] foo dir4
I'm having a hard time putting this together. The closest I have come:
find . -type d -regextype posix-egrep -regex ".*/([domain.com]).+" -exec basename {} ;
But this outputs subdirectories as well:
[domain.com] foo dir3
subdir5
subdir4
[domain.com] foo dir2
[domain.com] foo dir4
subdir8
[domain.com] foo dir1
subdir1
shell find
shell find
New contributor
New contributor
edited 6 mins ago
Daktari
New contributor
asked 8 mins ago
DaktariDaktari
1
1
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New contributor
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add a comment |
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Daktari is a new contributor. Be nice, and check out our Code of Conduct.
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Daktari is a new contributor. Be nice, and check out our Code of Conduct.
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