Cleanest way to take a[b[c]] to a[b][c]
2
$begingroup$
As indicated in the title I'm looking for the fastest way to transform a[b[c]] into a[b][c], and the natural generalization to an arbitrary chaining of arguments. I'm sure there's got to be a convenient way that I've overlooked.
In my cases a, b, and c can be any expression with any complicated internal structure they like.
function-construction
edited 38 mins ago
David G. Stork
24.1k22153
asked 1 hour ago
b3m2a1b3m2a1
27.2k257156
$endgroup$
add a comment |
2
$begingroup$
As indicated in the title I'm looking for the fastest way to transform a[b[c]] into a[b][c], and the natural generalization to an arbitrary chaining of arguments. I'm sure there's got to be a convenient way that I've overlooked.
In my cases a, b, and c can be any expression with any complicated internal structure they like.
function-construction
edited 38 mins ago
David G. Stork
24.1k22153
asked 1 hour ago
b3m2a1b3m2a1
27.2k257156
$endgroup$
1
$begingroup$
The solution likely would useOperate.
$endgroup$
– QuantumDot
1 hour ago
$begingroup$
f = Curry[Replace][a_[b_[c_]] :> a[b][c]]also works, so thata[b[c]] // fgives the desired result.
$endgroup$
– Shredderroy
1 hour ago
$begingroup$
How about generalizing the question to takinga[b[c[d[...]]]]toa[b][c][d]...?
$endgroup$
– David G. Stork
52 mins ago
$begingroup$
@DavidG.Stork sorry I thought that was implicit
$endgroup$
– b3m2a1
46 mins ago
$begingroup$
@b3m2a1: Oh.... well I recommend you alter the question... and seem my new solution.
$endgroup$
– David G. Stork
43 mins ago
add a comment |
2
2
2
$begingroup$
As indicated in the title I'm looking for the fastest way to transform a[b[c]] into a[b][c], and the natural generalization to an arbitrary chaining of arguments. I'm sure there's got to be a convenient way that I've overlooked.
In my cases a, b, and c can be any expression with any complicated internal structure they like.
function-construction
edited 38 mins ago
David G. Stork
24.1k22153
asked 1 hour ago
b3m2a1b3m2a1
27.2k257156
$endgroup$
As indicated in the title I'm looking for the fastest way to transform a[b[c]] into a[b][c], and the natural generalization to an arbitrary chaining of arguments. I'm sure there's got to be a convenient way that I've overlooked.
In my cases a, b, and c can be any expression with any complicated internal structure they like.
function-construction
function-construction
edited 38 mins ago
David G. Stork
24.1k22153
asked 1 hour ago
b3m2a1b3m2a1
27.2k257156
edited 38 mins ago
David G. Stork
24.1k22153
asked 1 hour ago
b3m2a1b3m2a1
27.2k257156
edited 38 mins ago
David G. Stork
24.1k22153
edited 38 mins ago
David G. Stork
24.1k22153
edited 38 mins ago
David G. Stork
24.1k22153
24.1k22153
asked 1 hour ago
b3m2a1b3m2a1
27.2k257156
asked 1 hour ago
b3m2a1b3m2a1
27.2k257156
asked 1 hour ago
b3m2a1b3m2a1
27.2k257156
27.2k257156
1
$begingroup$
The solution likely would useOperate.
$endgroup$
– QuantumDot
1 hour ago
$begingroup$
f = Curry[Replace][a_[b_[c_]] :> a[b][c]]also works, so thata[b[c]] // fgives the desired result.
$endgroup$
– Shredderroy
1 hour ago
$begingroup$
How about generalizing the question to takinga[b[c[d[...]]]]toa[b][c][d]...?
$endgroup$
– David G. Stork
52 mins ago
$begingroup$
@DavidG.Stork sorry I thought that was implicit
$endgroup$
– b3m2a1
46 mins ago
$begingroup$
@b3m2a1: Oh.... well I recommend you alter the question... and seem my new solution.
$endgroup$
– David G. Stork
43 mins ago
add a comment |
1
$begingroup$
The solution likely would useOperate.
$endgroup$
– QuantumDot
1 hour ago
$begingroup$
f = Curry[Replace][a_[b_[c_]] :> a[b][c]]also works, so thata[b[c]] // fgives the desired result.
$endgroup$
– Shredderroy
1 hour ago
$begingroup$
How about generalizing the question to takinga[b[c[d[...]]]]toa[b][c][d]...?
$endgroup$
– David G. Stork
52 mins ago
$begingroup$
@DavidG.Stork sorry I thought that was implicit
$endgroup$
– b3m2a1
46 mins ago
$begingroup$
@b3m2a1: Oh.... well I recommend you alter the question... and seem my new solution.
$endgroup$
– David G. Stork
43 mins ago
1
1
$begingroup$
The solution likely would use
Operate.$endgroup$
– QuantumDot
1 hour ago
$begingroup$
The solution likely would use
Operate.$endgroup$
– QuantumDot
1 hour ago
$begingroup$
f = Curry[Replace][a_[b_[c_]] :> a[b][c]] also works, so that a[b[c]] // f gives the desired result.$endgroup$
– Shredderroy
1 hour ago
$begingroup$
f = Curry[Replace][a_[b_[c_]] :> a[b][c]] also works, so that a[b[c]] // f gives the desired result.$endgroup$
– Shredderroy
1 hour ago
$begingroup$
How about generalizing the question to taking
a[b[c[d[...]]]] to a[b][c][d]...?$endgroup$
– David G. Stork
52 mins ago
$begingroup$
How about generalizing the question to taking
a[b[c[d[...]]]] to a[b][c][d]...?$endgroup$
– David G. Stork
52 mins ago
$begingroup$
@DavidG.Stork sorry I thought that was implicit
$endgroup$
– b3m2a1
46 mins ago
$begingroup$
@DavidG.Stork sorry I thought that was implicit
$endgroup$
– b3m2a1
46 mins ago
$begingroup$
@b3m2a1: Oh.... well I recommend you alter the question... and seem my new solution.
$endgroup$
– David G. Stork
43 mins ago
$begingroup$
@b3m2a1: Oh.... well I recommend you alter the question... and seem my new solution.
$endgroup$
– David G. Stork
43 mins ago
add a comment |
2 Answers
2
active
oldest
votes
2
$begingroup$
Operate[#[[0]], First@#] &[a[b[c]]]
a[b][c]
ClearAll[deCompose]
deCompose = Nest[Operate[#[[0]], First@#] &, #, Depth[#] - 2] &;
deCompose@a[b[c]]
a[b][c]
exp = Compose[a, b, c, d, e, f, g]
a[b[c[d[e[f[g]]]]]]
deCompose @ exp
a[b][c][d][e][f][g]
answered 47 mins ago
kglrkglr
180k9200413
$endgroup$
add a comment |
2
$begingroup$
Not particularly "clean," but it works:
Operate[Head[#], Level[#, 2][[2]]] & @ a[b[c]]
For the full generalization:
Nest[Operate[Head[#], Level[#, 2][[2]]] & , #, Depth[#] -2] & @
a[b[c[d[e]]]]
answered 1 hour ago
David G. StorkDavid G. Stork
24.1k22153
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
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votes
2
$begingroup$
Operate[#[[0]], First@#] &[a[b[c]]]
a[b][c]
ClearAll[deCompose]
deCompose = Nest[Operate[#[[0]], First@#] &, #, Depth[#] - 2] &;
deCompose@a[b[c]]
a[b][c]
exp = Compose[a, b, c, d, e, f, g]
a[b[c[d[e[f[g]]]]]]
deCompose @ exp
a[b][c][d][e][f][g]
answered 47 mins ago
kglrkglr
180k9200413
$endgroup$
add a comment |
2
$begingroup$
Operate[#[[0]], First@#] &[a[b[c]]]
a[b][c]
ClearAll[deCompose]
deCompose = Nest[Operate[#[[0]], First@#] &, #, Depth[#] - 2] &;
deCompose@a[b[c]]
a[b][c]
exp = Compose[a, b, c, d, e, f, g]
a[b[c[d[e[f[g]]]]]]
deCompose @ exp
a[b][c][d][e][f][g]
answered 47 mins ago
kglrkglr
180k9200413
$endgroup$
add a comment |
2
2
2
$begingroup$
Operate[#[[0]], First@#] &[a[b[c]]]
a[b][c]
ClearAll[deCompose]
deCompose = Nest[Operate[#[[0]], First@#] &, #, Depth[#] - 2] &;
deCompose@a[b[c]]
a[b][c]
exp = Compose[a, b, c, d, e, f, g]
a[b[c[d[e[f[g]]]]]]
deCompose @ exp
a[b][c][d][e][f][g]
answered 47 mins ago
kglrkglr
180k9200413
$endgroup$
Operate[#[[0]], First@#] &[a[b[c]]]
a[b][c]
ClearAll[deCompose]
deCompose = Nest[Operate[#[[0]], First@#] &, #, Depth[#] - 2] &;
deCompose@a[b[c]]
a[b][c]
exp = Compose[a, b, c, d, e, f, g]
a[b[c[d[e[f[g]]]]]]
deCompose @ exp
a[b][c][d][e][f][g]
answered 47 mins ago
kglrkglr
180k9200413
edited 40 mins ago
answered 47 mins ago
kglrkglr
180k9200413
answered 47 mins ago
kglrkglr
180k9200413
answered 47 mins ago
kglrkglr
180k9200413
180k9200413
add a comment |
add a comment |
2
$begingroup$
Not particularly "clean," but it works:
Operate[Head[#], Level[#, 2][[2]]] & @ a[b[c]]
For the full generalization:
Nest[Operate[Head[#], Level[#, 2][[2]]] & , #, Depth[#] -2] & @
a[b[c[d[e]]]]
answered 1 hour ago
David G. StorkDavid G. Stork
24.1k22153
$endgroup$
add a comment |
2
$begingroup$
Not particularly "clean," but it works:
Operate[Head[#], Level[#, 2][[2]]] & @ a[b[c]]
For the full generalization:
Nest[Operate[Head[#], Level[#, 2][[2]]] & , #, Depth[#] -2] & @
a[b[c[d[e]]]]
answered 1 hour ago
David G. StorkDavid G. Stork
24.1k22153
$endgroup$
add a comment |
2
2
2
$begingroup$
Not particularly "clean," but it works:
Operate[Head[#], Level[#, 2][[2]]] & @ a[b[c]]
For the full generalization:
Nest[Operate[Head[#], Level[#, 2][[2]]] & , #, Depth[#] -2] & @
a[b[c[d[e]]]]
answered 1 hour ago
David G. StorkDavid G. Stork
24.1k22153
$endgroup$
Not particularly "clean," but it works:
Operate[Head[#], Level[#, 2][[2]]] & @ a[b[c]]
For the full generalization:
Nest[Operate[Head[#], Level[#, 2][[2]]] & , #, Depth[#] -2] & @
a[b[c[d[e]]]]
answered 1 hour ago
David G. StorkDavid G. Stork
24.1k22153
edited 39 mins ago
answered 1 hour ago
David G. StorkDavid G. Stork
24.1k22153
answered 1 hour ago
David G. StorkDavid G. Stork
24.1k22153
answered 1 hour ago
David G. StorkDavid G. Stork
24.1k22153
24.1k22153
add a comment |
add a comment |
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1
$begingroup$
The solution likely would use
Operate.$endgroup$
– QuantumDot
1 hour ago
$begingroup$
f = Curry[Replace][a_[b_[c_]] :> a[b][c]]also works, so thata[b[c]] // fgives the desired result.$endgroup$
– Shredderroy
1 hour ago
$begingroup$
How about generalizing the question to taking
a[b[c[d[...]]]]toa[b][c][d]...?$endgroup$
– David G. Stork
52 mins ago
$begingroup$
@DavidG.Stork sorry I thought that was implicit
$endgroup$
– b3m2a1
46 mins ago
$begingroup$
@b3m2a1: Oh.... well I recommend you alter the question... and seem my new solution.
$endgroup$
– David G. Stork
43 mins ago