Could a ~150 mile impact basin form from a small object imact?
Could a ~150 mile (240 kilometers) crater form from a small object impact?
So the object impacting the site of the crater is a human shape and not able to be destroyed. The location of the impact is in an ocean which is on average 1000 feet (304 meters) deep with the ocean floor made of mostly granite. The atmosphere is also similar to earths. The gravity is half that of earth.
science-based asteroids cataclysms
asked 4 hours ago
SlothsAndMe
515
add a comment |
Could a ~150 mile (240 kilometers) crater form from a small object impact?
So the object impacting the site of the crater is a human shape and not able to be destroyed. The location of the impact is in an ocean which is on average 1000 feet (304 meters) deep with the ocean floor made of mostly granite. The atmosphere is also similar to earths. The gravity is half that of earth.
science-based asteroids cataclysms
asked 4 hours ago
SlothsAndMe
515
2
Wait... The impact location is the ocean, but you want a 150 mile impact basin? At the bottom of the ocean? The impact velocity would probably vaporize most of the ocean (after igniting the atmosphere), killing everything on the planet. Did I understand that correctly?
– JBH
2 hours ago
2
I scratch my head for a science based question involving an indestructible bullet...
– L.Dutch♦
2 hours ago
1
Yes you understand correctly. But at this point there wouldn't be life at all. The story is a deity of sorts falls into the planet at an extremely high speed and the impact creates the only land on the planet.
– SlothsAndMe
2 hours ago
add a comment |
Could a ~150 mile (240 kilometers) crater form from a small object impact?
So the object impacting the site of the crater is a human shape and not able to be destroyed. The location of the impact is in an ocean which is on average 1000 feet (304 meters) deep with the ocean floor made of mostly granite. The atmosphere is also similar to earths. The gravity is half that of earth.
science-based asteroids cataclysms
asked 4 hours ago
SlothsAndMe
515
Could a ~150 mile (240 kilometers) crater form from a small object impact?
So the object impacting the site of the crater is a human shape and not able to be destroyed. The location of the impact is in an ocean which is on average 1000 feet (304 meters) deep with the ocean floor made of mostly granite. The atmosphere is also similar to earths. The gravity is half that of earth.
science-based asteroids cataclysms
science-based asteroids cataclysms
asked 4 hours ago
SlothsAndMe
515
asked 4 hours ago
SlothsAndMe
515
asked 4 hours ago
SlothsAndMe
515
asked 4 hours ago
SlothsAndMe
515
asked 4 hours ago
SlothsAndMe
515
515
2
Wait... The impact location is the ocean, but you want a 150 mile impact basin? At the bottom of the ocean? The impact velocity would probably vaporize most of the ocean (after igniting the atmosphere), killing everything on the planet. Did I understand that correctly?
– JBH
2 hours ago
2
I scratch my head for a science based question involving an indestructible bullet...
– L.Dutch♦
2 hours ago
1
Yes you understand correctly. But at this point there wouldn't be life at all. The story is a deity of sorts falls into the planet at an extremely high speed and the impact creates the only land on the planet.
– SlothsAndMe
2 hours ago
add a comment |
2
Wait... The impact location is the ocean, but you want a 150 mile impact basin? At the bottom of the ocean? The impact velocity would probably vaporize most of the ocean (after igniting the atmosphere), killing everything on the planet. Did I understand that correctly?
– JBH
2 hours ago
2
I scratch my head for a science based question involving an indestructible bullet...
– L.Dutch♦
2 hours ago
1
Yes you understand correctly. But at this point there wouldn't be life at all. The story is a deity of sorts falls into the planet at an extremely high speed and the impact creates the only land on the planet.
– SlothsAndMe
2 hours ago
2
2
Wait... The impact location is the ocean, but you want a 150 mile impact basin? At the bottom of the ocean? The impact velocity would probably vaporize most of the ocean (after igniting the atmosphere), killing everything on the planet. Did I understand that correctly?
– JBH
2 hours ago
Wait... The impact location is the ocean, but you want a 150 mile impact basin? At the bottom of the ocean? The impact velocity would probably vaporize most of the ocean (after igniting the atmosphere), killing everything on the planet. Did I understand that correctly?
– JBH
2 hours ago
2
2
I scratch my head for a science based question involving an indestructible bullet...
– L.Dutch♦
2 hours ago
I scratch my head for a science based question involving an indestructible bullet...
– L.Dutch♦
2 hours ago
1
1
Yes you understand correctly. But at this point there wouldn't be life at all. The story is a deity of sorts falls into the planet at an extremely high speed and the impact creates the only land on the planet.
– SlothsAndMe
2 hours ago
Yes you understand correctly. But at this point there wouldn't be life at all. The story is a deity of sorts falls into the planet at an extremely high speed and the impact creates the only land on the planet.
– SlothsAndMe
2 hours ago
add a comment |
2 Answers
2
active
oldest
votes
I used Down2Earth's impact calculator to try and find out what it would take to get what you want.
The only parameter I could get even close to what you want was the target site: the bed of a 300m deep water body, on an Earth-like planet. I used the densest projectile and the smallest available size? a 100m wide piece of iron. The angle with the widest crater is that of a head-on crash.
This is what we get:
If instead of Iron we used uranium, or even osmium (the densest element), we would get approximately thrice the energy on the impact. The crater would still be one or two orders of magnitude smaller than what you want. But that's with the 100m wide impactor.
As you can see, for even an osmium man-sized projectile to give you the juice you need, it will need to impact at a considerable fraction of the speed of light. It will open a hole in whatever tectonic plate it hits, besides melting most of the crust around the impact, triggering a new Hadean era. If the planet has an atmosphere, it will evaporate into space. Gasified rocks will form a new, venusian atmosphere that may last a billion years. The debris from the impact will form a new Moon; the planet will have its mass reduced due to losing that debris to form the Moon, so the planet will have a smaller gravity after the impact. Also, its orbit will probably change excentricity around the sun.
If the solar system is already depleted of icy bodies (i.e.: comets) going around the orbit of that planet, it will never get enough water to develop life again. Otherwise give it a billion years for the crust to cool off and the atmosphere to renew itself, and maybe some microbial life will appear. Billions of years later, any intelligent life will never be able to tell that the impact happened.
answered 2 hours ago
Renan
43.7k1199223
maybe try with something denser like neutronium.
– Jasen
22 mins ago
add a comment |
The Chicxulub impactor is roughly 6.8-50.3 miles in diameter and in this event it released $5.8 cdot 10^{25} J$ of energy.
To figure out how fast a body would have to travel to impart that energy the equation is $E=(1/2)mv^2$.
Assuming average mans body ~80kg (ASSUMING) we get a velocity of $~1.2 cdot 10^{12} m/s$ which is about 4000 times the speed of light.
To scale that out to 150 mile wide crater would be far beyond anything even worth mentioning. Now if this god being were super massively dense, maybe the math would work out.
edited 2 hours ago
L.Dutch♦
77.9k26186380
answered 2 hours ago
Sonvar
813
New contributor
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
It would be better if you used the relativistic formula for kinetic energy
– L.Dutch♦
39 mins ago
1
Gotta agree with @L.Dutch. If using the classical formula gives an answer like that then it’s time to move up a gear.
– Joe Bloggs
34 mins ago
1
For example, a quick estimate using this calculator pegs the required speed at 0.9999999999999 times the speed of light. Don’t get me wrong, that’s still obscene, but at least it’s physically possible!
– Joe Bloggs
26 mins ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "579"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fworldbuilding.stackexchange.com%2fquestions%2f135807%2fcould-a-150-mile-impact-basin-form-from-a-small-object-imact%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I used Down2Earth's impact calculator to try and find out what it would take to get what you want.
The only parameter I could get even close to what you want was the target site: the bed of a 300m deep water body, on an Earth-like planet. I used the densest projectile and the smallest available size? a 100m wide piece of iron. The angle with the widest crater is that of a head-on crash.
This is what we get:
If instead of Iron we used uranium, or even osmium (the densest element), we would get approximately thrice the energy on the impact. The crater would still be one or two orders of magnitude smaller than what you want. But that's with the 100m wide impactor.
As you can see, for even an osmium man-sized projectile to give you the juice you need, it will need to impact at a considerable fraction of the speed of light. It will open a hole in whatever tectonic plate it hits, besides melting most of the crust around the impact, triggering a new Hadean era. If the planet has an atmosphere, it will evaporate into space. Gasified rocks will form a new, venusian atmosphere that may last a billion years. The debris from the impact will form a new Moon; the planet will have its mass reduced due to losing that debris to form the Moon, so the planet will have a smaller gravity after the impact. Also, its orbit will probably change excentricity around the sun.
If the solar system is already depleted of icy bodies (i.e.: comets) going around the orbit of that planet, it will never get enough water to develop life again. Otherwise give it a billion years for the crust to cool off and the atmosphere to renew itself, and maybe some microbial life will appear. Billions of years later, any intelligent life will never be able to tell that the impact happened.
answered 2 hours ago
Renan
43.7k1199223
maybe try with something denser like neutronium.
– Jasen
22 mins ago
add a comment |
I used Down2Earth's impact calculator to try and find out what it would take to get what you want.
The only parameter I could get even close to what you want was the target site: the bed of a 300m deep water body, on an Earth-like planet. I used the densest projectile and the smallest available size? a 100m wide piece of iron. The angle with the widest crater is that of a head-on crash.
This is what we get:
If instead of Iron we used uranium, or even osmium (the densest element), we would get approximately thrice the energy on the impact. The crater would still be one or two orders of magnitude smaller than what you want. But that's with the 100m wide impactor.
As you can see, for even an osmium man-sized projectile to give you the juice you need, it will need to impact at a considerable fraction of the speed of light. It will open a hole in whatever tectonic plate it hits, besides melting most of the crust around the impact, triggering a new Hadean era. If the planet has an atmosphere, it will evaporate into space. Gasified rocks will form a new, venusian atmosphere that may last a billion years. The debris from the impact will form a new Moon; the planet will have its mass reduced due to losing that debris to form the Moon, so the planet will have a smaller gravity after the impact. Also, its orbit will probably change excentricity around the sun.
If the solar system is already depleted of icy bodies (i.e.: comets) going around the orbit of that planet, it will never get enough water to develop life again. Otherwise give it a billion years for the crust to cool off and the atmosphere to renew itself, and maybe some microbial life will appear. Billions of years later, any intelligent life will never be able to tell that the impact happened.
answered 2 hours ago
Renan
43.7k1199223
maybe try with something denser like neutronium.
– Jasen
22 mins ago
add a comment |
I used Down2Earth's impact calculator to try and find out what it would take to get what you want.
The only parameter I could get even close to what you want was the target site: the bed of a 300m deep water body, on an Earth-like planet. I used the densest projectile and the smallest available size? a 100m wide piece of iron. The angle with the widest crater is that of a head-on crash.
This is what we get:
If instead of Iron we used uranium, or even osmium (the densest element), we would get approximately thrice the energy on the impact. The crater would still be one or two orders of magnitude smaller than what you want. But that's with the 100m wide impactor.
As you can see, for even an osmium man-sized projectile to give you the juice you need, it will need to impact at a considerable fraction of the speed of light. It will open a hole in whatever tectonic plate it hits, besides melting most of the crust around the impact, triggering a new Hadean era. If the planet has an atmosphere, it will evaporate into space. Gasified rocks will form a new, venusian atmosphere that may last a billion years. The debris from the impact will form a new Moon; the planet will have its mass reduced due to losing that debris to form the Moon, so the planet will have a smaller gravity after the impact. Also, its orbit will probably change excentricity around the sun.
If the solar system is already depleted of icy bodies (i.e.: comets) going around the orbit of that planet, it will never get enough water to develop life again. Otherwise give it a billion years for the crust to cool off and the atmosphere to renew itself, and maybe some microbial life will appear. Billions of years later, any intelligent life will never be able to tell that the impact happened.
answered 2 hours ago
Renan
43.7k1199223
I used Down2Earth's impact calculator to try and find out what it would take to get what you want.
The only parameter I could get even close to what you want was the target site: the bed of a 300m deep water body, on an Earth-like planet. I used the densest projectile and the smallest available size? a 100m wide piece of iron. The angle with the widest crater is that of a head-on crash.
This is what we get:
If instead of Iron we used uranium, or even osmium (the densest element), we would get approximately thrice the energy on the impact. The crater would still be one or two orders of magnitude smaller than what you want. But that's with the 100m wide impactor.
As you can see, for even an osmium man-sized projectile to give you the juice you need, it will need to impact at a considerable fraction of the speed of light. It will open a hole in whatever tectonic plate it hits, besides melting most of the crust around the impact, triggering a new Hadean era. If the planet has an atmosphere, it will evaporate into space. Gasified rocks will form a new, venusian atmosphere that may last a billion years. The debris from the impact will form a new Moon; the planet will have its mass reduced due to losing that debris to form the Moon, so the planet will have a smaller gravity after the impact. Also, its orbit will probably change excentricity around the sun.
If the solar system is already depleted of icy bodies (i.e.: comets) going around the orbit of that planet, it will never get enough water to develop life again. Otherwise give it a billion years for the crust to cool off and the atmosphere to renew itself, and maybe some microbial life will appear. Billions of years later, any intelligent life will never be able to tell that the impact happened.
answered 2 hours ago
Renan
43.7k1199223
answered 2 hours ago
Renan
43.7k1199223
answered 2 hours ago
Renan
43.7k1199223
answered 2 hours ago
Renan
43.7k1199223
43.7k1199223
maybe try with something denser like neutronium.
– Jasen
22 mins ago
add a comment |
maybe try with something denser like neutronium.
– Jasen
22 mins ago
maybe try with something denser like neutronium.
– Jasen
22 mins ago
maybe try with something denser like neutronium.
– Jasen
22 mins ago
add a comment |
The Chicxulub impactor is roughly 6.8-50.3 miles in diameter and in this event it released $5.8 cdot 10^{25} J$ of energy.
To figure out how fast a body would have to travel to impart that energy the equation is $E=(1/2)mv^2$.
Assuming average mans body ~80kg (ASSUMING) we get a velocity of $~1.2 cdot 10^{12} m/s$ which is about 4000 times the speed of light.
To scale that out to 150 mile wide crater would be far beyond anything even worth mentioning. Now if this god being were super massively dense, maybe the math would work out.
edited 2 hours ago
L.Dutch♦
77.9k26186380
answered 2 hours ago
Sonvar
813
New contributor
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
It would be better if you used the relativistic formula for kinetic energy
– L.Dutch♦
39 mins ago
1
Gotta agree with @L.Dutch. If using the classical formula gives an answer like that then it’s time to move up a gear.
– Joe Bloggs
34 mins ago
1
For example, a quick estimate using this calculator pegs the required speed at 0.9999999999999 times the speed of light. Don’t get me wrong, that’s still obscene, but at least it’s physically possible!
– Joe Bloggs
26 mins ago
add a comment |
The Chicxulub impactor is roughly 6.8-50.3 miles in diameter and in this event it released $5.8 cdot 10^{25} J$ of energy.
To figure out how fast a body would have to travel to impart that energy the equation is $E=(1/2)mv^2$.
Assuming average mans body ~80kg (ASSUMING) we get a velocity of $~1.2 cdot 10^{12} m/s$ which is about 4000 times the speed of light.
To scale that out to 150 mile wide crater would be far beyond anything even worth mentioning. Now if this god being were super massively dense, maybe the math would work out.
edited 2 hours ago
L.Dutch♦
77.9k26186380
answered 2 hours ago
Sonvar
813
New contributor
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
It would be better if you used the relativistic formula for kinetic energy
– L.Dutch♦
39 mins ago
1
Gotta agree with @L.Dutch. If using the classical formula gives an answer like that then it’s time to move up a gear.
– Joe Bloggs
34 mins ago
1
For example, a quick estimate using this calculator pegs the required speed at 0.9999999999999 times the speed of light. Don’t get me wrong, that’s still obscene, but at least it’s physically possible!
– Joe Bloggs
26 mins ago
add a comment |
The Chicxulub impactor is roughly 6.8-50.3 miles in diameter and in this event it released $5.8 cdot 10^{25} J$ of energy.
To figure out how fast a body would have to travel to impart that energy the equation is $E=(1/2)mv^2$.
Assuming average mans body ~80kg (ASSUMING) we get a velocity of $~1.2 cdot 10^{12} m/s$ which is about 4000 times the speed of light.
To scale that out to 150 mile wide crater would be far beyond anything even worth mentioning. Now if this god being were super massively dense, maybe the math would work out.
edited 2 hours ago
L.Dutch♦
77.9k26186380
answered 2 hours ago
Sonvar
813
New contributor
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
The Chicxulub impactor is roughly 6.8-50.3 miles in diameter and in this event it released $5.8 cdot 10^{25} J$ of energy.
To figure out how fast a body would have to travel to impart that energy the equation is $E=(1/2)mv^2$.
Assuming average mans body ~80kg (ASSUMING) we get a velocity of $~1.2 cdot 10^{12} m/s$ which is about 4000 times the speed of light.
To scale that out to 150 mile wide crater would be far beyond anything even worth mentioning. Now if this god being were super massively dense, maybe the math would work out.
edited 2 hours ago
L.Dutch♦
77.9k26186380
answered 2 hours ago
Sonvar
813
New contributor
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 hours ago
L.Dutch♦
77.9k26186380
edited 2 hours ago
L.Dutch♦
77.9k26186380
edited 2 hours ago
L.Dutch♦
77.9k26186380
77.9k26186380
answered 2 hours ago
Sonvar
813
New contributor
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 hours ago
Sonvar
813
answered 2 hours ago
Sonvar
813
813
New contributor
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Sonvar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
It would be better if you used the relativistic formula for kinetic energy
– L.Dutch♦
39 mins ago
1
Gotta agree with @L.Dutch. If using the classical formula gives an answer like that then it’s time to move up a gear.
– Joe Bloggs
34 mins ago
1
For example, a quick estimate using this calculator pegs the required speed at 0.9999999999999 times the speed of light. Don’t get me wrong, that’s still obscene, but at least it’s physically possible!
– Joe Bloggs
26 mins ago
add a comment |
1
It would be better if you used the relativistic formula for kinetic energy
– L.Dutch♦
39 mins ago
1
Gotta agree with @L.Dutch. If using the classical formula gives an answer like that then it’s time to move up a gear.
– Joe Bloggs
34 mins ago
1
For example, a quick estimate using this calculator pegs the required speed at 0.9999999999999 times the speed of light. Don’t get me wrong, that’s still obscene, but at least it’s physically possible!
– Joe Bloggs
26 mins ago
1
1
It would be better if you used the relativistic formula for kinetic energy
– L.Dutch♦
39 mins ago
It would be better if you used the relativistic formula for kinetic energy
– L.Dutch♦
39 mins ago
1
1
Gotta agree with @L.Dutch. If using the classical formula gives an answer like that then it’s time to move up a gear.
– Joe Bloggs
34 mins ago
Gotta agree with @L.Dutch. If using the classical formula gives an answer like that then it’s time to move up a gear.
– Joe Bloggs
34 mins ago
1
1
For example, a quick estimate using this calculator pegs the required speed at 0.9999999999999 times the speed of light. Don’t get me wrong, that’s still obscene, but at least it’s physically possible!
– Joe Bloggs
26 mins ago
For example, a quick estimate using this calculator pegs the required speed at 0.9999999999999 times the speed of light. Don’t get me wrong, that’s still obscene, but at least it’s physically possible!
– Joe Bloggs
26 mins ago
add a comment |
Thanks for contributing an answer to Worldbuilding Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fworldbuilding.stackexchange.com%2fquestions%2f135807%2fcould-a-150-mile-impact-basin-form-from-a-small-object-imact%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
Wait... The impact location is the ocean, but you want a 150 mile impact basin? At the bottom of the ocean? The impact velocity would probably vaporize most of the ocean (after igniting the atmosphere), killing everything on the planet. Did I understand that correctly?
– JBH
2 hours ago
2
I scratch my head for a science based question involving an indestructible bullet...
– L.Dutch♦
2 hours ago
1
Yes you understand correctly. But at this point there wouldn't be life at all. The story is a deity of sorts falls into the planet at an extremely high speed and the impact creates the only land on the planet.
– SlothsAndMe
2 hours ago