sed - How do I match this pattern?












0














I'm using sed and I am having trouble finding out how to remove some of the first line of text from each block. Here is my original data:



  "s220823vaps2512":   {
"hostname": "s220823vaps2512",
"description": data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},
"roles": "data",
"mounts": "data"
},
"s220823vaps2513": {
"hostname": "s220823vaps2513",
"description": "data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},


I want to use sed to successfully remove everything up until the { on the first line of each block leaving me with a data format similar to



{
"hostname": "data",
"etc": "etc",
},
{
"hostname": "data",
"etc": "etc",
},









share|improve this question




















  • 1




    Looks like JSON. Is it? If so, use a JSON parser. It's much much better that way.
    – Sobrique
    Oct 20 '15 at 9:12
















0














I'm using sed and I am having trouble finding out how to remove some of the first line of text from each block. Here is my original data:



  "s220823vaps2512":   {
"hostname": "s220823vaps2512",
"description": data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},
"roles": "data",
"mounts": "data"
},
"s220823vaps2513": {
"hostname": "s220823vaps2513",
"description": "data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},


I want to use sed to successfully remove everything up until the { on the first line of each block leaving me with a data format similar to



{
"hostname": "data",
"etc": "etc",
},
{
"hostname": "data",
"etc": "etc",
},









share|improve this question




















  • 1




    Looks like JSON. Is it? If so, use a JSON parser. It's much much better that way.
    – Sobrique
    Oct 20 '15 at 9:12














0












0








0







I'm using sed and I am having trouble finding out how to remove some of the first line of text from each block. Here is my original data:



  "s220823vaps2512":   {
"hostname": "s220823vaps2512",
"description": data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},
"roles": "data",
"mounts": "data"
},
"s220823vaps2513": {
"hostname": "s220823vaps2513",
"description": "data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},


I want to use sed to successfully remove everything up until the { on the first line of each block leaving me with a data format similar to



{
"hostname": "data",
"etc": "etc",
},
{
"hostname": "data",
"etc": "etc",
},









share|improve this question















I'm using sed and I am having trouble finding out how to remove some of the first line of text from each block. Here is my original data:



  "s220823vaps2512":   {
"hostname": "s220823vaps2512",
"description": data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},
"roles": "data",
"mounts": "data"
},
"s220823vaps2513": {
"hostname": "s220823vaps2513",
"description": "data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},


I want to use sed to successfully remove everything up until the { on the first line of each block leaving me with a data format similar to



{
"hostname": "data",
"etc": "etc",
},
{
"hostname": "data",
"etc": "etc",
},






sed






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago









Rui F Ribeiro

39.2k1479130




39.2k1479130










asked Oct 20 '15 at 7:02









CMS

1




1








  • 1




    Looks like JSON. Is it? If so, use a JSON parser. It's much much better that way.
    – Sobrique
    Oct 20 '15 at 9:12














  • 1




    Looks like JSON. Is it? If so, use a JSON parser. It's much much better that way.
    – Sobrique
    Oct 20 '15 at 9:12








1




1




Looks like JSON. Is it? If so, use a JSON parser. It's much much better that way.
– Sobrique
Oct 20 '15 at 9:12




Looks like JSON. Is it? If so, use a JSON parser. It's much much better that way.
– Sobrique
Oct 20 '15 at 9:12










3 Answers
3






active

oldest

votes


















2














This answer is predicated on the above looking rather a lot like JSON, so I've therefore assumed it probably is JSON. But it's incomplete in your sample, which I have also assumed is a typo. If this isn't the case... well, you already have sed answers.



Please - don't use a regex to parse JSON. It's nasty. regex is bad at recursive tagged data types like JSON/XML. It's at best a dirty hack which creates brittle code in future.



Similarly - JSON is important that it be complete - I've had to guess how your full JSON looks.



Assuming JSON like this (used http://jsonlint.com/ to tidy up the elements)



{
"s220823vaps2512": {
"hostname": "s220823vaps2512",
"description": "data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
},
"roles": "data",
"mounts": "data"
},
"s220823vaps2513": {
"hostname": "s220823vaps2513",
"description": "data",
"type": "Virtual",
"os": "data",
"idc": "data",
"environment": "data",
"deviceclass": "data",
"cores": "data",
"memory": "data",
"frontnet": "data",
"ipset": {
"backnet": "data",
"storagenet": "data",
"metroclusternet": "data"
}
}
}


Then the way to just get the bits you want:



#!/usr/bin/env perl
use strict;
use warnings;

use JSON;

my $input = ### as above, snipped for brevity.

#decode/validated
my $json = decode_json ( $input );
#create new JSON array of elements.
my $new_json = [map { $json -> {$_} } keys %$json];
#print it out.
print to_json ( $new_json, { pretty => 1, canonical => 1 } );


And in this way, you create valid JSON output as well as handling cases where e.g. key ordering is different (which is entirely valid in JSON).






share|improve this answer





























    0














    Simple with sed:



    sed 's/^[^{]*{/{/' file



    • Just searches for lines starting with characters which are not { (^[^{]), zero or more times * followed by a {.

    • This all is replaced by a single {.


    Edit: If you want to exclude some patterns from being replace (for example the "ipset": line) use this:



    sed '/"ipset":/n;s/^[^{]*{/{/' file



    • If the line starts with "ipset":, continue with the next line n.






    share|improve this answer























    • Will this not effect the ipset data?
      – CMS
      Oct 20 '15 at 7:10










    • Yes it does, if you don't want that, you need something to identify the other lines: is there a similarity in that names: s220823vaps2513? s-digit-vaps-digit or so?
      – chaos
      Oct 20 '15 at 7:15










    • Yes the names are similar in each line, probably around 10 variants though
      – CMS
      Oct 20 '15 at 7:17










    • Additionally can we use sed to ignore the ipset line as this is the only line that it would effect?
      – CMS
      Oct 20 '15 at 7:18










    • Yes, see my edited answer.
      – chaos
      Oct 20 '15 at 7:23



















    0














    This seems to work, at least on the sample of data you provided:



    sed -'s/^ .*{/{/' file 


    It transforms the first line of each block "name" { (note the leading space) to just {






    share|improve this answer























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      This answer is predicated on the above looking rather a lot like JSON, so I've therefore assumed it probably is JSON. But it's incomplete in your sample, which I have also assumed is a typo. If this isn't the case... well, you already have sed answers.



      Please - don't use a regex to parse JSON. It's nasty. regex is bad at recursive tagged data types like JSON/XML. It's at best a dirty hack which creates brittle code in future.



      Similarly - JSON is important that it be complete - I've had to guess how your full JSON looks.



      Assuming JSON like this (used http://jsonlint.com/ to tidy up the elements)



      {
      "s220823vaps2512": {
      "hostname": "s220823vaps2512",
      "description": "data",
      "type": "Virtual",
      "os": "data",
      "idc": "data",
      "environment": "data",
      "deviceclass": "data",
      "cores": "data",
      "memory": "data",
      "frontnet": "data",
      "ipset": {
      "backnet": "data",
      "storagenet": "data",
      "metroclusternet": "data"
      },
      "roles": "data",
      "mounts": "data"
      },
      "s220823vaps2513": {
      "hostname": "s220823vaps2513",
      "description": "data",
      "type": "Virtual",
      "os": "data",
      "idc": "data",
      "environment": "data",
      "deviceclass": "data",
      "cores": "data",
      "memory": "data",
      "frontnet": "data",
      "ipset": {
      "backnet": "data",
      "storagenet": "data",
      "metroclusternet": "data"
      }
      }
      }


      Then the way to just get the bits you want:



      #!/usr/bin/env perl
      use strict;
      use warnings;

      use JSON;

      my $input = ### as above, snipped for brevity.

      #decode/validated
      my $json = decode_json ( $input );
      #create new JSON array of elements.
      my $new_json = [map { $json -> {$_} } keys %$json];
      #print it out.
      print to_json ( $new_json, { pretty => 1, canonical => 1 } );


      And in this way, you create valid JSON output as well as handling cases where e.g. key ordering is different (which is entirely valid in JSON).






      share|improve this answer


























        2














        This answer is predicated on the above looking rather a lot like JSON, so I've therefore assumed it probably is JSON. But it's incomplete in your sample, which I have also assumed is a typo. If this isn't the case... well, you already have sed answers.



        Please - don't use a regex to parse JSON. It's nasty. regex is bad at recursive tagged data types like JSON/XML. It's at best a dirty hack which creates brittle code in future.



        Similarly - JSON is important that it be complete - I've had to guess how your full JSON looks.



        Assuming JSON like this (used http://jsonlint.com/ to tidy up the elements)



        {
        "s220823vaps2512": {
        "hostname": "s220823vaps2512",
        "description": "data",
        "type": "Virtual",
        "os": "data",
        "idc": "data",
        "environment": "data",
        "deviceclass": "data",
        "cores": "data",
        "memory": "data",
        "frontnet": "data",
        "ipset": {
        "backnet": "data",
        "storagenet": "data",
        "metroclusternet": "data"
        },
        "roles": "data",
        "mounts": "data"
        },
        "s220823vaps2513": {
        "hostname": "s220823vaps2513",
        "description": "data",
        "type": "Virtual",
        "os": "data",
        "idc": "data",
        "environment": "data",
        "deviceclass": "data",
        "cores": "data",
        "memory": "data",
        "frontnet": "data",
        "ipset": {
        "backnet": "data",
        "storagenet": "data",
        "metroclusternet": "data"
        }
        }
        }


        Then the way to just get the bits you want:



        #!/usr/bin/env perl
        use strict;
        use warnings;

        use JSON;

        my $input = ### as above, snipped for brevity.

        #decode/validated
        my $json = decode_json ( $input );
        #create new JSON array of elements.
        my $new_json = [map { $json -> {$_} } keys %$json];
        #print it out.
        print to_json ( $new_json, { pretty => 1, canonical => 1 } );


        And in this way, you create valid JSON output as well as handling cases where e.g. key ordering is different (which is entirely valid in JSON).






        share|improve this answer
























          2












          2








          2






          This answer is predicated on the above looking rather a lot like JSON, so I've therefore assumed it probably is JSON. But it's incomplete in your sample, which I have also assumed is a typo. If this isn't the case... well, you already have sed answers.



          Please - don't use a regex to parse JSON. It's nasty. regex is bad at recursive tagged data types like JSON/XML. It's at best a dirty hack which creates brittle code in future.



          Similarly - JSON is important that it be complete - I've had to guess how your full JSON looks.



          Assuming JSON like this (used http://jsonlint.com/ to tidy up the elements)



          {
          "s220823vaps2512": {
          "hostname": "s220823vaps2512",
          "description": "data",
          "type": "Virtual",
          "os": "data",
          "idc": "data",
          "environment": "data",
          "deviceclass": "data",
          "cores": "data",
          "memory": "data",
          "frontnet": "data",
          "ipset": {
          "backnet": "data",
          "storagenet": "data",
          "metroclusternet": "data"
          },
          "roles": "data",
          "mounts": "data"
          },
          "s220823vaps2513": {
          "hostname": "s220823vaps2513",
          "description": "data",
          "type": "Virtual",
          "os": "data",
          "idc": "data",
          "environment": "data",
          "deviceclass": "data",
          "cores": "data",
          "memory": "data",
          "frontnet": "data",
          "ipset": {
          "backnet": "data",
          "storagenet": "data",
          "metroclusternet": "data"
          }
          }
          }


          Then the way to just get the bits you want:



          #!/usr/bin/env perl
          use strict;
          use warnings;

          use JSON;

          my $input = ### as above, snipped for brevity.

          #decode/validated
          my $json = decode_json ( $input );
          #create new JSON array of elements.
          my $new_json = [map { $json -> {$_} } keys %$json];
          #print it out.
          print to_json ( $new_json, { pretty => 1, canonical => 1 } );


          And in this way, you create valid JSON output as well as handling cases where e.g. key ordering is different (which is entirely valid in JSON).






          share|improve this answer












          This answer is predicated on the above looking rather a lot like JSON, so I've therefore assumed it probably is JSON. But it's incomplete in your sample, which I have also assumed is a typo. If this isn't the case... well, you already have sed answers.



          Please - don't use a regex to parse JSON. It's nasty. regex is bad at recursive tagged data types like JSON/XML. It's at best a dirty hack which creates brittle code in future.



          Similarly - JSON is important that it be complete - I've had to guess how your full JSON looks.



          Assuming JSON like this (used http://jsonlint.com/ to tidy up the elements)



          {
          "s220823vaps2512": {
          "hostname": "s220823vaps2512",
          "description": "data",
          "type": "Virtual",
          "os": "data",
          "idc": "data",
          "environment": "data",
          "deviceclass": "data",
          "cores": "data",
          "memory": "data",
          "frontnet": "data",
          "ipset": {
          "backnet": "data",
          "storagenet": "data",
          "metroclusternet": "data"
          },
          "roles": "data",
          "mounts": "data"
          },
          "s220823vaps2513": {
          "hostname": "s220823vaps2513",
          "description": "data",
          "type": "Virtual",
          "os": "data",
          "idc": "data",
          "environment": "data",
          "deviceclass": "data",
          "cores": "data",
          "memory": "data",
          "frontnet": "data",
          "ipset": {
          "backnet": "data",
          "storagenet": "data",
          "metroclusternet": "data"
          }
          }
          }


          Then the way to just get the bits you want:



          #!/usr/bin/env perl
          use strict;
          use warnings;

          use JSON;

          my $input = ### as above, snipped for brevity.

          #decode/validated
          my $json = decode_json ( $input );
          #create new JSON array of elements.
          my $new_json = [map { $json -> {$_} } keys %$json];
          #print it out.
          print to_json ( $new_json, { pretty => 1, canonical => 1 } );


          And in this way, you create valid JSON output as well as handling cases where e.g. key ordering is different (which is entirely valid in JSON).







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Oct 20 '15 at 9:40









          Sobrique

          3,789518




          3,789518

























              0














              Simple with sed:



              sed 's/^[^{]*{/{/' file



              • Just searches for lines starting with characters which are not { (^[^{]), zero or more times * followed by a {.

              • This all is replaced by a single {.


              Edit: If you want to exclude some patterns from being replace (for example the "ipset": line) use this:



              sed '/"ipset":/n;s/^[^{]*{/{/' file



              • If the line starts with "ipset":, continue with the next line n.






              share|improve this answer























              • Will this not effect the ipset data?
                – CMS
                Oct 20 '15 at 7:10










              • Yes it does, if you don't want that, you need something to identify the other lines: is there a similarity in that names: s220823vaps2513? s-digit-vaps-digit or so?
                – chaos
                Oct 20 '15 at 7:15










              • Yes the names are similar in each line, probably around 10 variants though
                – CMS
                Oct 20 '15 at 7:17










              • Additionally can we use sed to ignore the ipset line as this is the only line that it would effect?
                – CMS
                Oct 20 '15 at 7:18










              • Yes, see my edited answer.
                – chaos
                Oct 20 '15 at 7:23
















              0














              Simple with sed:



              sed 's/^[^{]*{/{/' file



              • Just searches for lines starting with characters which are not { (^[^{]), zero or more times * followed by a {.

              • This all is replaced by a single {.


              Edit: If you want to exclude some patterns from being replace (for example the "ipset": line) use this:



              sed '/"ipset":/n;s/^[^{]*{/{/' file



              • If the line starts with "ipset":, continue with the next line n.






              share|improve this answer























              • Will this not effect the ipset data?
                – CMS
                Oct 20 '15 at 7:10










              • Yes it does, if you don't want that, you need something to identify the other lines: is there a similarity in that names: s220823vaps2513? s-digit-vaps-digit or so?
                – chaos
                Oct 20 '15 at 7:15










              • Yes the names are similar in each line, probably around 10 variants though
                – CMS
                Oct 20 '15 at 7:17










              • Additionally can we use sed to ignore the ipset line as this is the only line that it would effect?
                – CMS
                Oct 20 '15 at 7:18










              • Yes, see my edited answer.
                – chaos
                Oct 20 '15 at 7:23














              0












              0








              0






              Simple with sed:



              sed 's/^[^{]*{/{/' file



              • Just searches for lines starting with characters which are not { (^[^{]), zero or more times * followed by a {.

              • This all is replaced by a single {.


              Edit: If you want to exclude some patterns from being replace (for example the "ipset": line) use this:



              sed '/"ipset":/n;s/^[^{]*{/{/' file



              • If the line starts with "ipset":, continue with the next line n.






              share|improve this answer














              Simple with sed:



              sed 's/^[^{]*{/{/' file



              • Just searches for lines starting with characters which are not { (^[^{]), zero or more times * followed by a {.

              • This all is replaced by a single {.


              Edit: If you want to exclude some patterns from being replace (for example the "ipset": line) use this:



              sed '/"ipset":/n;s/^[^{]*{/{/' file



              • If the line starts with "ipset":, continue with the next line n.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Oct 20 '15 at 7:39

























              answered Oct 20 '15 at 7:07









              chaos

              35.1k773116




              35.1k773116












              • Will this not effect the ipset data?
                – CMS
                Oct 20 '15 at 7:10










              • Yes it does, if you don't want that, you need something to identify the other lines: is there a similarity in that names: s220823vaps2513? s-digit-vaps-digit or so?
                – chaos
                Oct 20 '15 at 7:15










              • Yes the names are similar in each line, probably around 10 variants though
                – CMS
                Oct 20 '15 at 7:17










              • Additionally can we use sed to ignore the ipset line as this is the only line that it would effect?
                – CMS
                Oct 20 '15 at 7:18










              • Yes, see my edited answer.
                – chaos
                Oct 20 '15 at 7:23


















              • Will this not effect the ipset data?
                – CMS
                Oct 20 '15 at 7:10










              • Yes it does, if you don't want that, you need something to identify the other lines: is there a similarity in that names: s220823vaps2513? s-digit-vaps-digit or so?
                – chaos
                Oct 20 '15 at 7:15










              • Yes the names are similar in each line, probably around 10 variants though
                – CMS
                Oct 20 '15 at 7:17










              • Additionally can we use sed to ignore the ipset line as this is the only line that it would effect?
                – CMS
                Oct 20 '15 at 7:18










              • Yes, see my edited answer.
                – chaos
                Oct 20 '15 at 7:23
















              Will this not effect the ipset data?
              – CMS
              Oct 20 '15 at 7:10




              Will this not effect the ipset data?
              – CMS
              Oct 20 '15 at 7:10












              Yes it does, if you don't want that, you need something to identify the other lines: is there a similarity in that names: s220823vaps2513? s-digit-vaps-digit or so?
              – chaos
              Oct 20 '15 at 7:15




              Yes it does, if you don't want that, you need something to identify the other lines: is there a similarity in that names: s220823vaps2513? s-digit-vaps-digit or so?
              – chaos
              Oct 20 '15 at 7:15












              Yes the names are similar in each line, probably around 10 variants though
              – CMS
              Oct 20 '15 at 7:17




              Yes the names are similar in each line, probably around 10 variants though
              – CMS
              Oct 20 '15 at 7:17












              Additionally can we use sed to ignore the ipset line as this is the only line that it would effect?
              – CMS
              Oct 20 '15 at 7:18




              Additionally can we use sed to ignore the ipset line as this is the only line that it would effect?
              – CMS
              Oct 20 '15 at 7:18












              Yes, see my edited answer.
              – chaos
              Oct 20 '15 at 7:23




              Yes, see my edited answer.
              – chaos
              Oct 20 '15 at 7:23











              0














              This seems to work, at least on the sample of data you provided:



              sed -'s/^ .*{/{/' file 


              It transforms the first line of each block "name" { (note the leading space) to just {






              share|improve this answer




























                0














                This seems to work, at least on the sample of data you provided:



                sed -'s/^ .*{/{/' file 


                It transforms the first line of each block "name" { (note the leading space) to just {






                share|improve this answer


























                  0












                  0








                  0






                  This seems to work, at least on the sample of data you provided:



                  sed -'s/^ .*{/{/' file 


                  It transforms the first line of each block "name" { (note the leading space) to just {






                  share|improve this answer














                  This seems to work, at least on the sample of data you provided:



                  sed -'s/^ .*{/{/' file 


                  It transforms the first line of each block "name" { (note the leading space) to just {







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Oct 20 '15 at 7:43

























                  answered Oct 20 '15 at 7:24









                  cas

                  38.7k452100




                  38.7k452100






























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