Start range from 1 onward
I am counting multiple log files with the range starting from 1 onward however it's starting from 0.
path=(/home/folder/text/*)
for 1 int ${!path}; do
printf "$s: $sn" $i "${list[i]##*/}";
done
shell-script array for
edited 2 hours ago
Kusalananda
122k16229374
asked 7 hours ago
User101
254
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I am counting multiple log files with the range starting from 1 onward however it's starting from 0.
path=(/home/folder/text/*)
for 1 int ${!path}; do
printf "$s: $sn" $i "${list[i]##*/}";
done
shell-script array for
edited 2 hours ago
Kusalananda
122k16229374
asked 7 hours ago
User101
254
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am counting multiple log files with the range starting from 1 onward however it's starting from 0.
path=(/home/folder/text/*)
for 1 int ${!path}; do
printf "$s: $sn" $i "${list[i]##*/}";
done
shell-script array for
edited 2 hours ago
Kusalananda
122k16229374
asked 7 hours ago
User101
254
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am counting multiple log files with the range starting from 1 onward however it's starting from 0.
path=(/home/folder/text/*)
for 1 int ${!path}; do
printf "$s: $sn" $i "${list[i]##*/}";
done
shell-script array for
shell-script array for
edited 2 hours ago
Kusalananda
122k16229374
asked 7 hours ago
User101
254
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 hours ago
Kusalananda
122k16229374
asked 7 hours ago
User101
254
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 hours ago
Kusalananda
122k16229374
edited 2 hours ago
Kusalananda
122k16229374
edited 2 hours ago
Kusalananda
122k16229374
122k16229374
asked 7 hours ago
User101
254
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 hours ago
User101
254
asked 7 hours ago
User101
254
254
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
User101 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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add a comment |
add a comment |
1 Answer
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votes
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered 6 hours ago
Kusalananda
122k16229374
add a comment |
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1 Answer
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered 6 hours ago
Kusalananda
122k16229374
add a comment |
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered 6 hours ago
Kusalananda
122k16229374
add a comment |
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered 6 hours ago
Kusalananda
122k16229374
Your shell code makes little sense as it uses the wrong syntax for the for loop and in the substitution to get the indexes, and also does not use printf format strings correctly.
I'm guessing that you'd want to do something like this:
i=0
for pathname in /home/folder/text/*; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
This would enumerate the names found under /home/folder/text (excluding hidden names).
You can replace "$( basename "$pathname" )" in the above with "${pathname##*/}" if you wish.
Using an array as you show in your own code:
pathnames=( /home/folder/text/* )
i=0
for pathname in "${pathnames[@]}"; do
i=$(( i + 1 ))
printf '%s: %sn' "$i" "$( basename "$pathname" )"
done
Would you want to iterate over the indexes of the array:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$index" "$( basename "${pathnames[$index]}" )"
done
Note that bash arrays start on index zero. Adding 1 to each index:
pathnames=( /home/folder/text/* )
for index in "${!pathnames[@]}"; do
printf '%s: %sn' "$(( index + 1 ))" "$( basename "${pathnames[$index]}" )"
done
answered 6 hours ago
Kusalananda
122k16229374
edited 4 hours ago
answered 6 hours ago
Kusalananda
122k16229374
answered 6 hours ago
Kusalananda
122k16229374
answered 6 hours ago
Kusalananda
122k16229374
122k16229374
add a comment |
add a comment |
User101 is a new contributor. Be nice, and check out our Code of Conduct.
User101 is a new contributor. Be nice, and check out our Code of Conduct.
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