Looping 'find…-type f': Getting filenames by dir/subdir, ouputing a txt with name dir_subdir_fname.txt
My data structure is something like:
dir1/subdir1_level1/subdir1_level2.../subdir1_leveln
dir1/subdir2_level1/subdir2_level2.../subdir2_leveln
...
Which means that the levels I'm working with are not structured properly, nevertheless.
I managed to accomplish my objective of getting the filename according to the first 2 levels of the path, and output them to a text file named dirn_subdirn_fname.txt with:
find dir1/subdir1 -type f -printf "%fn">dir1_subdir1_fname.txt
But I was wondering if there was a way to Iterate this process across a list of several dir/subdir's
edit: I found a way to do the first part:
#!/bin/bash
shopt -s dotglob nullglob
topdir= './Dir1'
for subdir in "$topdir"; do
find "$subdir" -type f -printf "%fn"
done
bash shell-script awk perl
asked 2 hours ago
Faustino DelgadoFaustino Delgado
263
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My data structure is something like:
dir1/subdir1_level1/subdir1_level2.../subdir1_leveln
dir1/subdir2_level1/subdir2_level2.../subdir2_leveln
...
Which means that the levels I'm working with are not structured properly, nevertheless.
I managed to accomplish my objective of getting the filename according to the first 2 levels of the path, and output them to a text file named dirn_subdirn_fname.txt with:
find dir1/subdir1 -type f -printf "%fn">dir1_subdir1_fname.txt
But I was wondering if there was a way to Iterate this process across a list of several dir/subdir's
edit: I found a way to do the first part:
#!/bin/bash
shopt -s dotglob nullglob
topdir= './Dir1'
for subdir in "$topdir"; do
find "$subdir" -type f -printf "%fn"
done
bash shell-script awk perl
asked 2 hours ago
Faustino DelgadoFaustino Delgado
263
New contributor
Faustino Delgado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Probably something likefor pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done? Orfind dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;?
– Sergiy Kolodyazhnyy
2 hours ago
add a comment |
My data structure is something like:
dir1/subdir1_level1/subdir1_level2.../subdir1_leveln
dir1/subdir2_level1/subdir2_level2.../subdir2_leveln
...
Which means that the levels I'm working with are not structured properly, nevertheless.
I managed to accomplish my objective of getting the filename according to the first 2 levels of the path, and output them to a text file named dirn_subdirn_fname.txt with:
find dir1/subdir1 -type f -printf "%fn">dir1_subdir1_fname.txt
But I was wondering if there was a way to Iterate this process across a list of several dir/subdir's
edit: I found a way to do the first part:
#!/bin/bash
shopt -s dotglob nullglob
topdir= './Dir1'
for subdir in "$topdir"; do
find "$subdir" -type f -printf "%fn"
done
bash shell-script awk perl
asked 2 hours ago
Faustino DelgadoFaustino Delgado
263
New contributor
Faustino Delgado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
My data structure is something like:
dir1/subdir1_level1/subdir1_level2.../subdir1_leveln
dir1/subdir2_level1/subdir2_level2.../subdir2_leveln
...
Which means that the levels I'm working with are not structured properly, nevertheless.
I managed to accomplish my objective of getting the filename according to the first 2 levels of the path, and output them to a text file named dirn_subdirn_fname.txt with:
find dir1/subdir1 -type f -printf "%fn">dir1_subdir1_fname.txt
But I was wondering if there was a way to Iterate this process across a list of several dir/subdir's
edit: I found a way to do the first part:
#!/bin/bash
shopt -s dotglob nullglob
topdir= './Dir1'
for subdir in "$topdir"; do
find "$subdir" -type f -printf "%fn"
done
bash shell-script awk perl
bash shell-script awk perl
asked 2 hours ago
Faustino DelgadoFaustino Delgado
263
New contributor
Faustino Delgado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Faustino DelgadoFaustino Delgado
263
New contributor
Faustino Delgado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 hours ago
Faustino Delgado
asked 2 hours ago
Faustino DelgadoFaustino Delgado
263
New contributor
Faustino Delgado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Faustino DelgadoFaustino Delgado
263
asked 2 hours ago
Faustino DelgadoFaustino Delgado
263
263
New contributor
Faustino Delgado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Faustino Delgado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Faustino Delgado is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Probably something likefor pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done? Orfind dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;?
– Sergiy Kolodyazhnyy
2 hours ago
add a comment |
Probably something likefor pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done? Orfind dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;?
– Sergiy Kolodyazhnyy
2 hours ago
Probably something like
for pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done ? Or find dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ; ?– Sergiy Kolodyazhnyy
2 hours ago
Probably something like
for pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done ? Or find dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ; ?– Sergiy Kolodyazhnyy
2 hours ago
add a comment |
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Probably something like
for pathname in dir1/*/ ; do find "$pathname" -type f > "$pathname"_fname.txt; done? Orfind dir1/ -type f -exec sh -c 'echo "$1" > "$(basename "$1" )"_fname.txt' sh {} ;?– Sergiy Kolodyazhnyy
2 hours ago