How to count many lines have the same number in two columns?
I need to compare the numbers in two columns and count how many lines have the same value in both columns. For example:
17 19
17 17
17 18
19 19
25 22
34 34
Expected output:
3
I can't sort them because each line is a specific gene and I can't use awk
because technically we haven't seen it in class yet. Is there any way to do this with grep
?
grep
New contributor
add a comment |
I need to compare the numbers in two columns and count how many lines have the same value in both columns. For example:
17 19
17 17
17 18
19 19
25 22
34 34
Expected output:
3
I can't sort them because each line is a specific gene and I can't use awk
because technically we haven't seen it in class yet. Is there any way to do this with grep
?
grep
New contributor
add a comment |
I need to compare the numbers in two columns and count how many lines have the same value in both columns. For example:
17 19
17 17
17 18
19 19
25 22
34 34
Expected output:
3
I can't sort them because each line is a specific gene and I can't use awk
because technically we haven't seen it in class yet. Is there any way to do this with grep
?
grep
New contributor
I need to compare the numbers in two columns and count how many lines have the same value in both columns. For example:
17 19
17 17
17 18
19 19
25 22
34 34
Expected output:
3
I can't sort them because each line is a specific gene and I can't use awk
because technically we haven't seen it in class yet. Is there any way to do this with grep
?
grep
grep
New contributor
New contributor
edited 7 mins ago
Inian
5,3201531
5,3201531
New contributor
asked 8 mins ago
ErandiErandi
1
1
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New contributor
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1 Answer
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One way would be to use grep
with its Extended Regular Expressions mode, to match the value in column 1 and print all those lines whose second column is also the same. The first part ([^ ]+)
captures the value in first column, and 1
means those lines whose value captured in the first column is also the same as second. The -c
is for printing those lines returned.
grep -cE '([^ ]+) 1' file
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1 Answer
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1 Answer
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active
oldest
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oldest
votes
One way would be to use grep
with its Extended Regular Expressions mode, to match the value in column 1 and print all those lines whose second column is also the same. The first part ([^ ]+)
captures the value in first column, and 1
means those lines whose value captured in the first column is also the same as second. The -c
is for printing those lines returned.
grep -cE '([^ ]+) 1' file
add a comment |
One way would be to use grep
with its Extended Regular Expressions mode, to match the value in column 1 and print all those lines whose second column is also the same. The first part ([^ ]+)
captures the value in first column, and 1
means those lines whose value captured in the first column is also the same as second. The -c
is for printing those lines returned.
grep -cE '([^ ]+) 1' file
add a comment |
One way would be to use grep
with its Extended Regular Expressions mode, to match the value in column 1 and print all those lines whose second column is also the same. The first part ([^ ]+)
captures the value in first column, and 1
means those lines whose value captured in the first column is also the same as second. The -c
is for printing those lines returned.
grep -cE '([^ ]+) 1' file
One way would be to use grep
with its Extended Regular Expressions mode, to match the value in column 1 and print all those lines whose second column is also the same. The first part ([^ ]+)
captures the value in first column, and 1
means those lines whose value captured in the first column is also the same as second. The -c
is for printing those lines returned.
grep -cE '([^ ]+) 1' file
answered 1 min ago
InianInian
5,3201531
5,3201531
add a comment |
add a comment |
Erandi is a new contributor. Be nice, and check out our Code of Conduct.
Erandi is a new contributor. Be nice, and check out our Code of Conduct.
Erandi is a new contributor. Be nice, and check out our Code of Conduct.
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