Creating a diagonal matrix from from a vector












1












$begingroup$


I try to create a function that create a diagonal matrix in which the diagonal are:



$qquad 1,a,a^2, cdots,a^n,1,a,a^2, cdots,a^n$



Here is my attempt:



nth[n_] := DiagonalMatrix[Table[a^{Mod[k, n]}, {k, 0, 2 n - 1}]];


For some reason and I do not know wh,y the diagonal matrix is just one vector. So it seems DiagonalMatrix does not work as I expect.



Any idea as to where the mistake is in the function I created?






functions matrix table







share|improve this question











$endgroup$

















    1












    $begingroup$


    I try to create a function that create a diagonal matrix in which the diagonal are:



    $qquad 1,a,a^2, cdots,a^n,1,a,a^2, cdots,a^n$



    Here is my attempt:



    nth[n_] := DiagonalMatrix[Table[a^{Mod[k, n]}, {k, 0, 2 n - 1}]];


    For some reason and I do not know wh,y the diagonal matrix is just one vector. So it seems DiagonalMatrix does not work as I expect.



    Any idea as to where the mistake is in the function I created?






    functions matrix table







    share|improve this question











    $endgroup$















      1












      1








      1





      $begingroup$


      I try to create a function that create a diagonal matrix in which the diagonal are:



      $qquad 1,a,a^2, cdots,a^n,1,a,a^2, cdots,a^n$



      Here is my attempt:



      nth[n_] := DiagonalMatrix[Table[a^{Mod[k, n]}, {k, 0, 2 n - 1}]];


      For some reason and I do not know wh,y the diagonal matrix is just one vector. So it seems DiagonalMatrix does not work as I expect.



      Any idea as to where the mistake is in the function I created?






      functions matrix table







      share|improve this question











      $endgroup$




      I try to create a function that create a diagonal matrix in which the diagonal are:



      $qquad 1,a,a^2, cdots,a^n,1,a,a^2, cdots,a^n$



      Here is my attempt:



      nth[n_] := DiagonalMatrix[Table[a^{Mod[k, n]}, {k, 0, 2 n - 1}]];


      For some reason and I do not know wh,y the diagonal matrix is just one vector. So it seems DiagonalMatrix does not work as I expect.



      Any idea as to where the mistake is in the function I created?






      functions matrix table




      functions matrix table






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 39 mins ago









      m_goldberg

      85.9k872196




      85.9k872196










      asked 6 hours ago









      henryhenry

      1346




      1346






















          1 Answer
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          3












          $begingroup$

          Remove the braces around Mod:



          ClearAll[nth]
          
nth[n_] := DiagonalMatrix@Table[a^Mod[k, n], {k, 0, 2 n - 1}]
          

          
nth[5] // MatrixForm // TeXForm



          $left(
          begin{array}{cccccccccc}
          1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & a & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & a^2 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & a^3 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & a^4 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & a & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & a^2 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^3 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^4 \
          end{array}
          right)$




          Alternatively, you can use SparseArray:



          ClearAll[nth2]
          
nth2[n_] := SparseArray[{k_, k_} :> a^Mod[k, n], {2 n - 1, 2 n - 1}]
          
nth2[5] // MatrixForm // TeXForm



          same result




          or use Band in combination with SparseArray:



          ClearAll[nth3]
          
nth3[n_] := SparseArray[Band[{1, 1}] -> Table[a^Mod[k, n], {k, 0, 2 n - 1}]]
          

          
nth2[5] // MatrixForm // TeXForm



          same result







          share|improve this answer











          $endgroup$













          • $begingroup$
            thanks.. it work perfectly.
            $endgroup$
            – henry
            6 hours ago










          • $begingroup$
            which one more practical? I mean later i need to compute power of modified verson of this matrix. so it will be much more computation.
            $endgroup$
            – henry
            6 hours ago








          • 1




            $begingroup$
            @henry, SparseArray +Band is likely to be the faster than DiagonalMatrix.
            $endgroup$
            – kglr
            6 hours ago










          • $begingroup$
            final question. If i use MatrixForm as a part of the function. does have any effect of efficiency of the computation?
            $endgroup$
            – henry
            6 hours ago






          • 1




            $begingroup$
            @henry, you should use MatrixForm is only for displaying (MatrixForm acts as a "wrapper", which affects printing, but not evaluation. )
            $endgroup$
            – kglr
            5 hours ago











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          3












          $begingroup$

          Remove the braces around Mod:



          ClearAll[nth]
          
nth[n_] := DiagonalMatrix@Table[a^Mod[k, n], {k, 0, 2 n - 1}]
          

          
nth[5] // MatrixForm // TeXForm



          $left(
          begin{array}{cccccccccc}
          1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & a & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & a^2 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & a^3 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & a^4 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & a & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & a^2 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^3 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^4 \
          end{array}
          right)$




          Alternatively, you can use SparseArray:



          ClearAll[nth2]
          
nth2[n_] := SparseArray[{k_, k_} :> a^Mod[k, n], {2 n - 1, 2 n - 1}]
          
nth2[5] // MatrixForm // TeXForm



          same result




          or use Band in combination with SparseArray:



          ClearAll[nth3]
          
nth3[n_] := SparseArray[Band[{1, 1}] -> Table[a^Mod[k, n], {k, 0, 2 n - 1}]]
          

          
nth2[5] // MatrixForm // TeXForm



          same result







          share|improve this answer











          $endgroup$













          • $begingroup$
            thanks.. it work perfectly.
            $endgroup$
            – henry
            6 hours ago










          • $begingroup$
            which one more practical? I mean later i need to compute power of modified verson of this matrix. so it will be much more computation.
            $endgroup$
            – henry
            6 hours ago








          • 1




            $begingroup$
            @henry, SparseArray +Band is likely to be the faster than DiagonalMatrix.
            $endgroup$
            – kglr
            6 hours ago










          • $begingroup$
            final question. If i use MatrixForm as a part of the function. does have any effect of efficiency of the computation?
            $endgroup$
            – henry
            6 hours ago






          • 1




            $begingroup$
            @henry, you should use MatrixForm is only for displaying (MatrixForm acts as a "wrapper", which affects printing, but not evaluation. )
            $endgroup$
            – kglr
            5 hours ago
















          3












          $begingroup$

          Remove the braces around Mod:



          ClearAll[nth]
          
nth[n_] := DiagonalMatrix@Table[a^Mod[k, n], {k, 0, 2 n - 1}]
          

          
nth[5] // MatrixForm // TeXForm



          $left(
          begin{array}{cccccccccc}
          1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & a & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & a^2 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & a^3 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & a^4 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & a & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & a^2 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^3 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^4 \
          end{array}
          right)$




          Alternatively, you can use SparseArray:



          ClearAll[nth2]
          
nth2[n_] := SparseArray[{k_, k_} :> a^Mod[k, n], {2 n - 1, 2 n - 1}]
          
nth2[5] // MatrixForm // TeXForm



          same result




          or use Band in combination with SparseArray:



          ClearAll[nth3]
          
nth3[n_] := SparseArray[Band[{1, 1}] -> Table[a^Mod[k, n], {k, 0, 2 n - 1}]]
          

          
nth2[5] // MatrixForm // TeXForm



          same result







          share|improve this answer











          $endgroup$













          • $begingroup$
            thanks.. it work perfectly.
            $endgroup$
            – henry
            6 hours ago










          • $begingroup$
            which one more practical? I mean later i need to compute power of modified verson of this matrix. so it will be much more computation.
            $endgroup$
            – henry
            6 hours ago








          • 1




            $begingroup$
            @henry, SparseArray +Band is likely to be the faster than DiagonalMatrix.
            $endgroup$
            – kglr
            6 hours ago










          • $begingroup$
            final question. If i use MatrixForm as a part of the function. does have any effect of efficiency of the computation?
            $endgroup$
            – henry
            6 hours ago






          • 1




            $begingroup$
            @henry, you should use MatrixForm is only for displaying (MatrixForm acts as a "wrapper", which affects printing, but not evaluation. )
            $endgroup$
            – kglr
            5 hours ago














          3












          3








          3





          $begingroup$

          Remove the braces around Mod:



          ClearAll[nth]
          
nth[n_] := DiagonalMatrix@Table[a^Mod[k, n], {k, 0, 2 n - 1}]
          

          
nth[5] // MatrixForm // TeXForm



          $left(
          begin{array}{cccccccccc}
          1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & a & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & a^2 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & a^3 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & a^4 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & a & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & a^2 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^3 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^4 \
          end{array}
          right)$




          Alternatively, you can use SparseArray:



          ClearAll[nth2]
          
nth2[n_] := SparseArray[{k_, k_} :> a^Mod[k, n], {2 n - 1, 2 n - 1}]
          
nth2[5] // MatrixForm // TeXForm



          same result




          or use Band in combination with SparseArray:



          ClearAll[nth3]
          
nth3[n_] := SparseArray[Band[{1, 1}] -> Table[a^Mod[k, n], {k, 0, 2 n - 1}]]
          

          
nth2[5] // MatrixForm // TeXForm



          same result







          share|improve this answer











          $endgroup$



          Remove the braces around Mod:



          ClearAll[nth]
          
nth[n_] := DiagonalMatrix@Table[a^Mod[k, n], {k, 0, 2 n - 1}]
          

          
nth[5] // MatrixForm // TeXForm



          $left(
          begin{array}{cccccccccc}
          1 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & a & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & a^2 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & a^3 & 0 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & a^4 & 0 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 1 & 0 & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & a & 0 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & a^2 & 0 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^3 & 0 \
          0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & a^4 \
          end{array}
          right)$




          Alternatively, you can use SparseArray:



          ClearAll[nth2]
          
nth2[n_] := SparseArray[{k_, k_} :> a^Mod[k, n], {2 n - 1, 2 n - 1}]
          
nth2[5] // MatrixForm // TeXForm



          same result




          or use Band in combination with SparseArray:



          ClearAll[nth3]
          
nth3[n_] := SparseArray[Band[{1, 1}] -> Table[a^Mod[k, n], {k, 0, 2 n - 1}]]
          

          
nth2[5] // MatrixForm // TeXForm



          same result








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 6 hours ago

























          answered 6 hours ago









          kglrkglr

          183k10201416




          183k10201416












          • $begingroup$
            thanks.. it work perfectly.
            $endgroup$
            – henry
            6 hours ago










          • $begingroup$
            which one more practical? I mean later i need to compute power of modified verson of this matrix. so it will be much more computation.
            $endgroup$
            – henry
            6 hours ago








          • 1




            $begingroup$
            @henry, SparseArray +Band is likely to be the faster than DiagonalMatrix.
            $endgroup$
            – kglr
            6 hours ago










          • $begingroup$
            final question. If i use MatrixForm as a part of the function. does have any effect of efficiency of the computation?
            $endgroup$
            – henry
            6 hours ago






          • 1




            $begingroup$
            @henry, you should use MatrixForm is only for displaying (MatrixForm acts as a "wrapper", which affects printing, but not evaluation. )
            $endgroup$
            – kglr
            5 hours ago


















          • $begingroup$
            thanks.. it work perfectly.
            $endgroup$
            – henry
            6 hours ago










          • $begingroup$
            which one more practical? I mean later i need to compute power of modified verson of this matrix. so it will be much more computation.
            $endgroup$
            – henry
            6 hours ago








          • 1




            $begingroup$
            @henry, SparseArray +Band is likely to be the faster than DiagonalMatrix.
            $endgroup$
            – kglr
            6 hours ago










          • $begingroup$
            final question. If i use MatrixForm as a part of the function. does have any effect of efficiency of the computation?
            $endgroup$
            – henry
            6 hours ago






          • 1




            $begingroup$
            @henry, you should use MatrixForm is only for displaying (MatrixForm acts as a "wrapper", which affects printing, but not evaluation. )
            $endgroup$
            – kglr
            5 hours ago
















          $begingroup$
          thanks.. it work perfectly.
          $endgroup$
          – henry
          6 hours ago




          $begingroup$
          thanks.. it work perfectly.
          $endgroup$
          – henry
          6 hours ago












          $begingroup$
          which one more practical? I mean later i need to compute power of modified verson of this matrix. so it will be much more computation.
          $endgroup$
          – henry
          6 hours ago






          $begingroup$
          which one more practical? I mean later i need to compute power of modified verson of this matrix. so it will be much more computation.
          $endgroup$
          – henry
          6 hours ago






          1




          1




          $begingroup$
          @henry, SparseArray +Band is likely to be the faster than DiagonalMatrix.
          $endgroup$
          – kglr
          6 hours ago




          $begingroup$
          @henry, SparseArray +Band is likely to be the faster than DiagonalMatrix.
          $endgroup$
          – kglr
          6 hours ago












          $begingroup$
          final question. If i use MatrixForm as a part of the function. does have any effect of efficiency of the computation?
          $endgroup$
          – henry
          6 hours ago




          $begingroup$
          final question. If i use MatrixForm as a part of the function. does have any effect of efficiency of the computation?
          $endgroup$
          – henry
          6 hours ago




          1




          1




          $begingroup$
          @henry, you should use MatrixForm is only for displaying (MatrixForm acts as a "wrapper", which affects printing, but not evaluation. )
          $endgroup$
          – kglr
          5 hours ago




          $begingroup$
          @henry, you should use MatrixForm is only for displaying (MatrixForm acts as a "wrapper", which affects printing, but not evaluation. )
          $endgroup$
          – kglr
          5 hours ago


















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          濃尾地震

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          濃尾地震 『岐阜市街大地震之図』 歌川国利画 本震 発生日 1891年（明治24年）10月28日 発生時刻 6時38分50秒（JST） 震央 日本 岐阜県本巣郡西根尾村（現・本巣市） 北緯35度35分 東経136度20分（ 地図 ） 規模    マグニチュード（M）8.0 最大震度    震度7： 注1 福井県今立郡鯖江町、愛知県葉栗郡大田島村、東春日井郡勝川村 地震の種類 直下型地震 被害 死傷者数 死者7,273人、負傷者17,175人 注1：当時の震度階級では「激烈」 プロジェクト:地球科学 プロジェクト:災害 テンプレートを表示 濃尾地震 （のうびじしん）は、1891年（明治24年）10月28日に濃尾地方で発生した、日本史上最大の内陸地殻内地震。「 美濃・尾張地震 （みの・おわりじしん）」とも呼ばれている。辛卯の年に発生したことから 辛卯震災 と呼んでいる報告書もある。 目次 1 概要 1.1 震源断層 2 被害 3 各地の震度 4 前兆現象 5 報道 6 学術的な意義 7 地震防災 8 脚注 9 関連項目 10 外部リンク 概要 濃尾地震発生当時の根尾谷断層 濃尾地震を引き起こした根尾谷断層 写真中央を斜めに走る段差が根尾谷断層 濃尾地震は、1891年10月28日6時38分50秒に発生した。震源は、岐阜県本巣郡西根尾村（現・本巣市）、北緯35度35分、東経136度20分付近。河角廣 (1951) は岐阜市付近（北緯35.6度、東経136.6度）に震央を仮定し規模 M K = 7.0 を与え [1] 、マグニチュードは M = 8.4 に換算されているが、明治・大正期の地震については0.5程度大きく見積もられているとされる [2] 。また、震央距離と震度との関係など当時のデータから後にM8.0 [3] とも推定される。アメリカ地質調査所 (USGS) でも8.0としている [4] 。「根尾谷断層帯」が活動した典型的な内陸地殻内地震（いわゆる直下型地震）であり、これは記録が残っている日本の内陸...
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