Can a subshell fetch an argument within the parent shell scope?












1















I want to run different versions of a utility onto the same data like so:



current_dir$ (cd my_utility_version_dir && exec ./my_util my_data_file)


Is there a way for my_util to look for my_data_file in current_dir?






shell arguments







share|improve this question





























    1















    I want to run different versions of a utility onto the same data like so:



    current_dir$ (cd my_utility_version_dir && exec ./my_util my_data_file)


    Is there a way for my_util to look for my_data_file in current_dir?






    shell arguments







    share|improve this question



























      1












      1








      1








      I want to run different versions of a utility onto the same data like so:



      current_dir$ (cd my_utility_version_dir && exec ./my_util my_data_file)


      Is there a way for my_util to look for my_data_file in current_dir?






      shell arguments







      share|improve this question
















      I want to run different versions of a utility onto the same data like so:



      current_dir$ (cd my_utility_version_dir && exec ./my_util my_data_file)


      Is there a way for my_util to look for my_data_file in current_dir?






      shell arguments




      shell arguments






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 6 hours ago









      Michael Homer

      49.5k8133172




      49.5k8133172










      asked 6 hours ago









      OneArbOneArb

      112




      112






















          1 Answer
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          2














          If you run



          (cd my_utility_version_dir && exec ./my_util "$OLDPWD/my_data_file")


          then





          1. my_util's current working directory (.) will be my_utility_version_dir

          2. It will have been given the path to my_data_file in the previous working directory - the one you cded out of.


          Whether that looks for it there or not depends on exactly how my_util works inside, but it would be pretty common that it accepted a path to use.






          share|improve this answer
























          • Works like a charm! (rep<15)

            – OneArb
            6 hours ago











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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          If you run



          (cd my_utility_version_dir && exec ./my_util "$OLDPWD/my_data_file")


          then





          1. my_util's current working directory (.) will be my_utility_version_dir

          2. It will have been given the path to my_data_file in the previous working directory - the one you cded out of.


          Whether that looks for it there or not depends on exactly how my_util works inside, but it would be pretty common that it accepted a path to use.






          share|improve this answer
























          • Works like a charm! (rep<15)

            – OneArb
            6 hours ago
















          2














          If you run



          (cd my_utility_version_dir && exec ./my_util "$OLDPWD/my_data_file")


          then





          1. my_util's current working directory (.) will be my_utility_version_dir

          2. It will have been given the path to my_data_file in the previous working directory - the one you cded out of.


          Whether that looks for it there or not depends on exactly how my_util works inside, but it would be pretty common that it accepted a path to use.






          share|improve this answer
























          • Works like a charm! (rep<15)

            – OneArb
            6 hours ago














          2












          2








          2







          If you run



          (cd my_utility_version_dir && exec ./my_util "$OLDPWD/my_data_file")


          then





          1. my_util's current working directory (.) will be my_utility_version_dir

          2. It will have been given the path to my_data_file in the previous working directory - the one you cded out of.


          Whether that looks for it there or not depends on exactly how my_util works inside, but it would be pretty common that it accepted a path to use.






          share|improve this answer













          If you run



          (cd my_utility_version_dir && exec ./my_util "$OLDPWD/my_data_file")


          then





          1. my_util's current working directory (.) will be my_utility_version_dir

          2. It will have been given the path to my_data_file in the previous working directory - the one you cded out of.


          Whether that looks for it there or not depends on exactly how my_util works inside, but it would be pretty common that it accepted a path to use.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 6 hours ago









          Michael HomerMichael Homer

          49.5k8133172




          49.5k8133172













          • Works like a charm! (rep<15)

            – OneArb
            6 hours ago



















          • Works like a charm! (rep<15)

            – OneArb
            6 hours ago

















          Works like a charm! (rep<15)

          – OneArb
          6 hours ago





          Works like a charm! (rep<15)

          – OneArb
          6 hours ago


















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