substract and replace values in string using shell












0















I am newbie to shell scripting and learning.



I have files in folder.
which look like
1232_2019_02_09_12_29_29.txt
1232_2019_02_09_12_29_55.txt



I want to extract 2019_02_09_12_29_29 & 2019_02_09_12_29_55 from file name and convert into
2019-02-09-122929 & 2019-02-09-122955.



#!/bin/sh

path=$1

if [[ -z $1 ]];then
echo "USAGE:: Argument missing, supply full path to list all files"
exit 1
fi

if [ -f $path/all_files.txt ] ; then
rm -f $path/all_files.txt
fi

ls -l $path | grep -v "^d" | awk '{print $9}' > $path/all_files.txt

while read -r line
do
line=${line##*/}
# echo "${line%"/}"
ex1=`awk -F'|' '{print substr($1,length($1)-22, 19)}'`
# ex2=`awk -F'|' '{print substr($1,length($1)-19, 10)}'`
echo $ex1
ex2=$(echo $ex1 | cut -c 1-10)
echo $ex2
ex3=$(echo $ex1 | cut -c 12-20)
echo $ex3
done <$path/all_files.txt


But this code is not giving me desired output.



Can anyone help?









share







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Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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    0















    I am newbie to shell scripting and learning.



    I have files in folder.
    which look like
    1232_2019_02_09_12_29_29.txt
    1232_2019_02_09_12_29_55.txt



    I want to extract 2019_02_09_12_29_29 & 2019_02_09_12_29_55 from file name and convert into
    2019-02-09-122929 & 2019-02-09-122955.



    #!/bin/sh

    path=$1

    if [[ -z $1 ]];then
    echo "USAGE:: Argument missing, supply full path to list all files"
    exit 1
    fi

    if [ -f $path/all_files.txt ] ; then
    rm -f $path/all_files.txt
    fi

    ls -l $path | grep -v "^d" | awk '{print $9}' > $path/all_files.txt

    while read -r line
    do
    line=${line##*/}
    # echo "${line%"/}"
    ex1=`awk -F'|' '{print substr($1,length($1)-22, 19)}'`
    # ex2=`awk -F'|' '{print substr($1,length($1)-19, 10)}'`
    echo $ex1
    ex2=$(echo $ex1 | cut -c 1-10)
    echo $ex2
    ex3=$(echo $ex1 | cut -c 12-20)
    echo $ex3
    done <$path/all_files.txt


    But this code is not giving me desired output.



    Can anyone help?









    share







    New contributor




    Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0








      I am newbie to shell scripting and learning.



      I have files in folder.
      which look like
      1232_2019_02_09_12_29_29.txt
      1232_2019_02_09_12_29_55.txt



      I want to extract 2019_02_09_12_29_29 & 2019_02_09_12_29_55 from file name and convert into
      2019-02-09-122929 & 2019-02-09-122955.



      #!/bin/sh

      path=$1

      if [[ -z $1 ]];then
      echo "USAGE:: Argument missing, supply full path to list all files"
      exit 1
      fi

      if [ -f $path/all_files.txt ] ; then
      rm -f $path/all_files.txt
      fi

      ls -l $path | grep -v "^d" | awk '{print $9}' > $path/all_files.txt

      while read -r line
      do
      line=${line##*/}
      # echo "${line%"/}"
      ex1=`awk -F'|' '{print substr($1,length($1)-22, 19)}'`
      # ex2=`awk -F'|' '{print substr($1,length($1)-19, 10)}'`
      echo $ex1
      ex2=$(echo $ex1 | cut -c 1-10)
      echo $ex2
      ex3=$(echo $ex1 | cut -c 12-20)
      echo $ex3
      done <$path/all_files.txt


      But this code is not giving me desired output.



      Can anyone help?









      share







      New contributor




      Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I am newbie to shell scripting and learning.



      I have files in folder.
      which look like
      1232_2019_02_09_12_29_29.txt
      1232_2019_02_09_12_29_55.txt



      I want to extract 2019_02_09_12_29_29 & 2019_02_09_12_29_55 from file name and convert into
      2019-02-09-122929 & 2019-02-09-122955.



      #!/bin/sh

      path=$1

      if [[ -z $1 ]];then
      echo "USAGE:: Argument missing, supply full path to list all files"
      exit 1
      fi

      if [ -f $path/all_files.txt ] ; then
      rm -f $path/all_files.txt
      fi

      ls -l $path | grep -v "^d" | awk '{print $9}' > $path/all_files.txt

      while read -r line
      do
      line=${line##*/}
      # echo "${line%"/}"
      ex1=`awk -F'|' '{print substr($1,length($1)-22, 19)}'`
      # ex2=`awk -F'|' '{print substr($1,length($1)-19, 10)}'`
      echo $ex1
      ex2=$(echo $ex1 | cut -c 1-10)
      echo $ex2
      ex3=$(echo $ex1 | cut -c 12-20)
      echo $ex3
      done <$path/all_files.txt


      But this code is not giving me desired output.



      Can anyone help?







      shell-script





      share







      New contributor




      Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 2 mins ago









      GeemeGeeme

      1




      1




      New contributor




      Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Geeme is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















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