How to combine similar characters in a list?












7















I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



test = 'hello###_world###test#test123##'

splitter = re.split("(#)", test)

splitter = filter(None, splitter)


Which returns this in the splitter variable:



['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


I'm trying to combine the hashes so the list turns into this:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


Thanks for any help!






python







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    7















    I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



    test = 'hello###_world###test#test123##'
    
splitter = re.split("(#)", test)
    
splitter = filter(None, splitter)


    Which returns this in the splitter variable:



    ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


    I'm trying to combine the hashes so the list turns into this:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


    Thanks for any help!






    python







    share|improve this question









    New contributor




    Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      7












      7








      7








      I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



      test = 'hello###_world###test#test123##'
      
splitter = re.split("(#)", test)
      
splitter = filter(None, splitter)


      Which returns this in the splitter variable:



      ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


      I'm trying to combine the hashes so the list turns into this:



      ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


      Thanks for any help!






      python







      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



      test = 'hello###_world###test#test123##'
      
splitter = re.split("(#)", test)
      
splitter = filter(None, splitter)


      Which returns this in the splitter variable:



      ['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


      I'm trying to combine the hashes so the list turns into this:



      ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


      Thanks for any help!






      python




      python






      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|improve this question




      share|improve this question








      edited 39 mins ago









      Ajax1234

      41.4k42853




      41.4k42853






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      asked 40 mins ago









      GregGreg

      362




      362




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      Greg is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          3 Answers
          3






          active

          oldest

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          5














          Try:



          splitter = re.split("(#+)", test)





          share|improve this answer



















          • 1





            It gives an empty string at the end.

            – AkshayNevrekar
            16 mins ago






          • 2





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            13 mins ago











          • This works for me. Thanks for the help!

            – Greg
            7 mins ago



















          1














          Add + at the end of the regular expression and filtering None values will do the trick



          >>> import re
          
>>> test = 'hello###_world###test#test123##'
          
>>> splitter = re.split("(#+)", test)
          
>>> splitter
          
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
          
>>> splitter = list(filter(None, splitter))
          
>>> splitter
          
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
          
>>>





          share|improve this answer































            1














            You can use itertools.groupby:



            import itertools
            
test = 'hello###_world###test#test123##'
            
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


            You can also use re.findall:



            import re
            
result = re.findall('#+|[^#]+', test)


            Output:



            ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





            share|improve this answer


























            • This one also does the job. Thanks for the help!

              – Greg
              6 mins ago











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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            5














            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer



















            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              16 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              13 mins ago











            • This works for me. Thanks for the help!

              – Greg
              7 mins ago
















            5














            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer



















            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              16 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              13 mins ago











            • This works for me. Thanks for the help!

              – Greg
              7 mins ago














            5












            5








            5







            Try:



            splitter = re.split("(#+)", test)





            share|improve this answer













            Try:



            splitter = re.split("(#+)", test)






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 22 mins ago









            mingganzmingganz

            1986




            1986








            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              16 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              13 mins ago











            • This works for me. Thanks for the help!

              – Greg
              7 mins ago














            • 1





              It gives an empty string at the end.

              – AkshayNevrekar
              16 mins ago






            • 2





              @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

              – DYZ
              13 mins ago











            • This works for me. Thanks for the help!

              – Greg
              7 mins ago








            1




            1





            It gives an empty string at the end.

            – AkshayNevrekar
            16 mins ago





            It gives an empty string at the end.

            – AkshayNevrekar
            16 mins ago




            2




            2





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            13 mins ago





            @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

            – DYZ
            13 mins ago













            This works for me. Thanks for the help!

            – Greg
            7 mins ago





            This works for me. Thanks for the help!

            – Greg
            7 mins ago













            1














            Add + at the end of the regular expression and filtering None values will do the trick



            >>> import re
            
>>> test = 'hello###_world###test#test123##'
            
>>> splitter = re.split("(#+)", test)
            
>>> splitter
            
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
            
>>> splitter = list(filter(None, splitter))
            
>>> splitter
            
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
            
>>>





            share|improve this answer




























              1














              Add + at the end of the regular expression and filtering None values will do the trick



              >>> import re
              
>>> test = 'hello###_world###test#test123##'
              
>>> splitter = re.split("(#+)", test)
              
>>> splitter
              
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
              
>>> splitter = list(filter(None, splitter))
              
>>> splitter
              
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
              
>>>





              share|improve this answer


























                1












                1








                1







                Add + at the end of the regular expression and filtering None values will do the trick



                >>> import re
                
>>> test = 'hello###_world###test#test123##'
                
>>> splitter = re.split("(#+)", test)
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
                
>>> splitter = list(filter(None, splitter))
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
                
>>>





                share|improve this answer













                Add + at the end of the regular expression and filtering None values will do the trick



                >>> import re
                
>>> test = 'hello###_world###test#test123##'
                
>>> splitter = re.split("(#+)", test)
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
                
>>> splitter = list(filter(None, splitter))
                
>>> splitter
                
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
                
>>>






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 11 mins ago









                Bodhi94Bodhi94

                901520




                901520























                    1














                    You can use itertools.groupby:



                    import itertools
                    
test = 'hello###_world###test#test123##'
                    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


                    You can also use re.findall:



                    import re
                    
result = re.findall('#+|[^#]+', test)


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





                    share|improve this answer


























                    • This one also does the job. Thanks for the help!

                      – Greg
                      6 mins ago
















                    1














                    You can use itertools.groupby:



                    import itertools
                    
test = 'hello###_world###test#test123##'
                    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


                    You can also use re.findall:



                    import re
                    
result = re.findall('#+|[^#]+', test)


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





                    share|improve this answer


























                    • This one also does the job. Thanks for the help!

                      – Greg
                      6 mins ago














                    1












                    1








                    1







                    You can use itertools.groupby:



                    import itertools
                    
test = 'hello###_world###test#test123##'
                    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


                    You can also use re.findall:



                    import re
                    
result = re.findall('#+|[^#]+', test)


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





                    share|improve this answer















                    You can use itertools.groupby:



                    import itertools
                    
test = 'hello###_world###test#test123##'
                    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


                    You can also use re.findall:



                    import re
                    
result = re.findall('#+|[^#]+', test)


                    Output:



                    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 3 mins ago

























                    answered 38 mins ago









                    Ajax1234Ajax1234

                    41.4k42853




                    41.4k42853













                    • This one also does the job. Thanks for the help!

                      – Greg
                      6 mins ago



















                    • This one also does the job. Thanks for the help!

                      – Greg
                      6 mins ago

















                    This one also does the job. Thanks for the help!

                    – Greg
                    6 mins ago





                    This one also does the job. Thanks for the help!

                    – Greg
                    6 mins ago










                    Greg is a new contributor. Be nice, and check out our Code of Conduct.










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                    Greg is a new contributor. Be nice, and check out our Code of Conduct.













                    Greg is a new contributor. Be nice, and check out our Code of Conduct.












                    Greg is a new contributor. Be nice, and check out our Code of Conduct.
















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