Writing over fractions












5















I am trying to achieve this look:
enter image description here



documentclass{article}
usepackage{amsmath}
begin{document}
$dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
end{document}
documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{arc@char}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here



I don't need any color or font different from the defaults.



EDIT:
Well I and modified something which is scaling with the fractions which is great but I can't rotate the arc. How to rotate it? Picture above.










share|improve this question




















  • 1





    Here is a way to do that, I think. The perhaps most beautiful option might be this one, but this is opinion-based.

    – marmot
    2 hours ago













  • Why not overbrace?

    – Werner
    1 hour ago
















5















I am trying to achieve this look:
enter image description here



documentclass{article}
usepackage{amsmath}
begin{document}
$dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
end{document}
documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{arc@char}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here



I don't need any color or font different from the defaults.



EDIT:
Well I and modified something which is scaling with the fractions which is great but I can't rotate the arc. How to rotate it? Picture above.










share|improve this question




















  • 1





    Here is a way to do that, I think. The perhaps most beautiful option might be this one, but this is opinion-based.

    – marmot
    2 hours ago













  • Why not overbrace?

    – Werner
    1 hour ago














5












5








5


1






I am trying to achieve this look:
enter image description here



documentclass{article}
usepackage{amsmath}
begin{document}
$dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
end{document}
documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{arc@char}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here



I don't need any color or font different from the defaults.



EDIT:
Well I and modified something which is scaling with the fractions which is great but I can't rotate the arc. How to rotate it? Picture above.










share|improve this question
















I am trying to achieve this look:
enter image description here



documentclass{article}
usepackage{amsmath}
begin{document}
$dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
end{document}
documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{arc@char}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here



I don't need any color or font different from the defaults.



EDIT:
Well I and modified something which is scaling with the fractions which is great but I can't rotate the arc. How to rotate it? Picture above.







math-mode






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago







Simeon Simeonov

















asked 2 hours ago









Simeon SimeonovSimeon Simeonov

3626




3626








  • 1





    Here is a way to do that, I think. The perhaps most beautiful option might be this one, but this is opinion-based.

    – marmot
    2 hours ago













  • Why not overbrace?

    – Werner
    1 hour ago














  • 1





    Here is a way to do that, I think. The perhaps most beautiful option might be this one, but this is opinion-based.

    – marmot
    2 hours ago













  • Why not overbrace?

    – Werner
    1 hour ago








1




1





Here is a way to do that, I think. The perhaps most beautiful option might be this one, but this is opinion-based.

– marmot
2 hours ago







Here is a way to do that, I think. The perhaps most beautiful option might be this one, but this is opinion-based.

– marmot
2 hours ago















Why not overbrace?

– Werner
1 hour ago





Why not overbrace?

– Werner
1 hour ago










1 Answer
1






active

oldest

votes


















3














Here is a proposal that marries your command with this answer by egreg.



documentclass{article}
usepackage{amsmath}
makeatletter% based on https://tex.stackexchange.com/a/260580/121799
newcommandunderparenonly[1]{%
mathop{%
vtop{
m@th
ialign{%
##crcr
$hfildisplaystyle{#1}hfil$crcr
noalign{kern3p@nointerlineskip}%
upparenfillcrcr
}%
}%
}
}
newcommandupparenfill{%
$m@thsetboxz@hbox{$braceld$}%
braceluleadersvrule @heighthtz@ @depthz@hfillbraceru$%
}
makeatother
newcommand{stackAboveChar}[2]{begin{array}[b]{@{}c@{}}underparenonly{#1}\[1ex]{#2}end{array}}
begin{document}
$stackAboveChar{x-2}{dfrac{2x+7}{x-4}}-stackAboveChar{x-4}{dfrac{x+4}{x-2}}$
end{document}


enter image description here



As for the code in your question: as you are already using graphicx, you could just add a rotatebox to flip the parenthesis.



documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{rotatebox[origin=bottom]{180}{arc@char}}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here






share|improve this answer





















  • 1





    It's working, but I need thin layer. I found something and updated my code, can you see it?

    – Simeon Simeonov
    1 hour ago











  • @SimeonSimeonov I rotated the parenthesis of your code. (Yet I must admit that I do not understand all details, not do I know whether or not there is a character code that avoids the rotation, yet since you are loading graphicx anyway that may be not so important.)

    – marmot
    1 hour ago











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














Here is a proposal that marries your command with this answer by egreg.



documentclass{article}
usepackage{amsmath}
makeatletter% based on https://tex.stackexchange.com/a/260580/121799
newcommandunderparenonly[1]{%
mathop{%
vtop{
m@th
ialign{%
##crcr
$hfildisplaystyle{#1}hfil$crcr
noalign{kern3p@nointerlineskip}%
upparenfillcrcr
}%
}%
}
}
newcommandupparenfill{%
$m@thsetboxz@hbox{$braceld$}%
braceluleadersvrule @heighthtz@ @depthz@hfillbraceru$%
}
makeatother
newcommand{stackAboveChar}[2]{begin{array}[b]{@{}c@{}}underparenonly{#1}\[1ex]{#2}end{array}}
begin{document}
$stackAboveChar{x-2}{dfrac{2x+7}{x-4}}-stackAboveChar{x-4}{dfrac{x+4}{x-2}}$
end{document}


enter image description here



As for the code in your question: as you are already using graphicx, you could just add a rotatebox to flip the parenthesis.



documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{rotatebox[origin=bottom]{180}{arc@char}}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here






share|improve this answer





















  • 1





    It's working, but I need thin layer. I found something and updated my code, can you see it?

    – Simeon Simeonov
    1 hour ago











  • @SimeonSimeonov I rotated the parenthesis of your code. (Yet I must admit that I do not understand all details, not do I know whether or not there is a character code that avoids the rotation, yet since you are loading graphicx anyway that may be not so important.)

    – marmot
    1 hour ago
















3














Here is a proposal that marries your command with this answer by egreg.



documentclass{article}
usepackage{amsmath}
makeatletter% based on https://tex.stackexchange.com/a/260580/121799
newcommandunderparenonly[1]{%
mathop{%
vtop{
m@th
ialign{%
##crcr
$hfildisplaystyle{#1}hfil$crcr
noalign{kern3p@nointerlineskip}%
upparenfillcrcr
}%
}%
}
}
newcommandupparenfill{%
$m@thsetboxz@hbox{$braceld$}%
braceluleadersvrule @heighthtz@ @depthz@hfillbraceru$%
}
makeatother
newcommand{stackAboveChar}[2]{begin{array}[b]{@{}c@{}}underparenonly{#1}\[1ex]{#2}end{array}}
begin{document}
$stackAboveChar{x-2}{dfrac{2x+7}{x-4}}-stackAboveChar{x-4}{dfrac{x+4}{x-2}}$
end{document}


enter image description here



As for the code in your question: as you are already using graphicx, you could just add a rotatebox to flip the parenthesis.



documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{rotatebox[origin=bottom]{180}{arc@char}}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here






share|improve this answer





















  • 1





    It's working, but I need thin layer. I found something and updated my code, can you see it?

    – Simeon Simeonov
    1 hour ago











  • @SimeonSimeonov I rotated the parenthesis of your code. (Yet I must admit that I do not understand all details, not do I know whether or not there is a character code that avoids the rotation, yet since you are loading graphicx anyway that may be not so important.)

    – marmot
    1 hour ago














3












3








3







Here is a proposal that marries your command with this answer by egreg.



documentclass{article}
usepackage{amsmath}
makeatletter% based on https://tex.stackexchange.com/a/260580/121799
newcommandunderparenonly[1]{%
mathop{%
vtop{
m@th
ialign{%
##crcr
$hfildisplaystyle{#1}hfil$crcr
noalign{kern3p@nointerlineskip}%
upparenfillcrcr
}%
}%
}
}
newcommandupparenfill{%
$m@thsetboxz@hbox{$braceld$}%
braceluleadersvrule @heighthtz@ @depthz@hfillbraceru$%
}
makeatother
newcommand{stackAboveChar}[2]{begin{array}[b]{@{}c@{}}underparenonly{#1}\[1ex]{#2}end{array}}
begin{document}
$stackAboveChar{x-2}{dfrac{2x+7}{x-4}}-stackAboveChar{x-4}{dfrac{x+4}{x-2}}$
end{document}


enter image description here



As for the code in your question: as you are already using graphicx, you could just add a rotatebox to flip the parenthesis.



documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{rotatebox[origin=bottom]{180}{arc@char}}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here






share|improve this answer















Here is a proposal that marries your command with this answer by egreg.



documentclass{article}
usepackage{amsmath}
makeatletter% based on https://tex.stackexchange.com/a/260580/121799
newcommandunderparenonly[1]{%
mathop{%
vtop{
m@th
ialign{%
##crcr
$hfildisplaystyle{#1}hfil$crcr
noalign{kern3p@nointerlineskip}%
upparenfillcrcr
}%
}%
}
}
newcommandupparenfill{%
$m@thsetboxz@hbox{$braceld$}%
braceluleadersvrule @heighthtz@ @depthz@hfillbraceru$%
}
makeatother
newcommand{stackAboveChar}[2]{begin{array}[b]{@{}c@{}}underparenonly{#1}\[1ex]{#2}end{array}}
begin{document}
$stackAboveChar{x-2}{dfrac{2x+7}{x-4}}-stackAboveChar{x-4}{dfrac{x+4}{x-2}}$
end{document}


enter image description here



As for the code in your question: as you are already using graphicx, you could just add a rotatebox to flip the parenthesis.



documentclass{article}
usepackage{amsmath}
usepackage{graphicx}

makeatletter
DeclareFontFamily{U}{tipa}{}
DeclareFontShape{U}{tipa}{m}{n}{<->tipa10}{}
newcommand{arc@char}{{usefont{U}{tipa}{m}{n}symbol{62}}}%

newcommand{arc}[1]{mathpalettearc@arc{#1}}

newcommand{arc@arc}[2]{%
sbox0{$m@th#1#2$}%
vbox{
hbox{resizebox{wd0}{height}{rotatebox[origin=bottom]{180}{arc@char}}}
nointerlineskip
box0
}%
}
makeatother

newcommand{stackAboveArc}[2]{begin{array}[b]{@{}c@{}}#1\ arc{#2}end{array}}

begin{document}
% $dfrac{2x+7}{x-4}-dfrac{x+4}{x-2}$
$dfrac{stackAboveArc{x-2}{2x+7}}{x-4}-dfrac{stackAboveArc{x-4}{x+4}}{x-2}$
end{document}


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 1 hour ago

























answered 2 hours ago









marmotmarmot

97k4112213




97k4112213








  • 1





    It's working, but I need thin layer. I found something and updated my code, can you see it?

    – Simeon Simeonov
    1 hour ago











  • @SimeonSimeonov I rotated the parenthesis of your code. (Yet I must admit that I do not understand all details, not do I know whether or not there is a character code that avoids the rotation, yet since you are loading graphicx anyway that may be not so important.)

    – marmot
    1 hour ago














  • 1





    It's working, but I need thin layer. I found something and updated my code, can you see it?

    – Simeon Simeonov
    1 hour ago











  • @SimeonSimeonov I rotated the parenthesis of your code. (Yet I must admit that I do not understand all details, not do I know whether or not there is a character code that avoids the rotation, yet since you are loading graphicx anyway that may be not so important.)

    – marmot
    1 hour ago








1




1





It's working, but I need thin layer. I found something and updated my code, can you see it?

– Simeon Simeonov
1 hour ago





It's working, but I need thin layer. I found something and updated my code, can you see it?

– Simeon Simeonov
1 hour ago













@SimeonSimeonov I rotated the parenthesis of your code. (Yet I must admit that I do not understand all details, not do I know whether or not there is a character code that avoids the rotation, yet since you are loading graphicx anyway that may be not so important.)

– marmot
1 hour ago





@SimeonSimeonov I rotated the parenthesis of your code. (Yet I must admit that I do not understand all details, not do I know whether or not there is a character code that avoids the rotation, yet since you are loading graphicx anyway that may be not so important.)

– marmot
1 hour ago


















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