Split string by space in ZSH
Give this file.txt:
first line
second line
third line
This works in bash:
while IFS=' ' read -a args; do
echo "${args[0]}"
done < file.txt
To produce
first
second
third
That is to say, we were able to read the file line by line, and on each one we split the line further into an array using space as a delimiter. But in zsh, the result is an error: read: bad option: -a.
How can we achieve in zsh the same as in bash? I’ve tried several solutions, but I was never able to split a string into an array using spaces as the delimiter.
bash zsh array read
asked 1 min ago
user137369user137369
17017
add a comment |
Give this file.txt:
first line
second line
third line
This works in bash:
while IFS=' ' read -a args; do
echo "${args[0]}"
done < file.txt
To produce
first
second
third
That is to say, we were able to read the file line by line, and on each one we split the line further into an array using space as a delimiter. But in zsh, the result is an error: read: bad option: -a.
How can we achieve in zsh the same as in bash? I’ve tried several solutions, but I was never able to split a string into an array using spaces as the delimiter.
bash zsh array read
asked 1 min ago
user137369user137369
17017
add a comment |
Give this file.txt:
first line
second line
third line
This works in bash:
while IFS=' ' read -a args; do
echo "${args[0]}"
done < file.txt
To produce
first
second
third
That is to say, we were able to read the file line by line, and on each one we split the line further into an array using space as a delimiter. But in zsh, the result is an error: read: bad option: -a.
How can we achieve in zsh the same as in bash? I’ve tried several solutions, but I was never able to split a string into an array using spaces as the delimiter.
bash zsh array read
asked 1 min ago
user137369user137369
17017
Give this file.txt:
first line
second line
third line
This works in bash:
while IFS=' ' read -a args; do
echo "${args[0]}"
done < file.txt
To produce
first
second
third
That is to say, we were able to read the file line by line, and on each one we split the line further into an array using space as a delimiter. But in zsh, the result is an error: read: bad option: -a.
How can we achieve in zsh the same as in bash? I’ve tried several solutions, but I was never able to split a string into an array using spaces as the delimiter.
bash zsh array read
bash zsh array read
asked 1 min ago
user137369user137369
17017
asked 1 min ago
user137369user137369
17017
asked 1 min ago
user137369user137369
17017
asked 1 min ago
user137369user137369
17017
asked 1 min ago
user137369user137369
17017
17017
add a comment |
add a comment |
0
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