Use sed replace with line number from variable
This is my sed command:
while ...;
do sed -r "${counter}s/^S+ /$line /g" $in > $out;
..
..
done
Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:
do echo ´sed -r "${counter}s/^S+/$line/g" $in > $out´;
which printed this to the console:
sed -r <line number>/^S+/<replace pattern>/g <infile> > <outfile>
When executing this very command (without the ´) from the console, I get this:
sed: -e expression #1, char 8: unterminated s' command
I guess this is because the ' are missing around the pattern.
So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?
bash sed
edited Oct 28 '15 at 10:16
serenesat
9341519
asked Oct 28 '15 at 9:42
entenbeinentenbein
12
bumped to the homepage by Community♦ 9 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
|
show 3 more comments
This is my sed command:
while ...;
do sed -r "${counter}s/^S+ /$line /g" $in > $out;
..
..
done
Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:
do echo ´sed -r "${counter}s/^S+/$line/g" $in > $out´;
which printed this to the console:
sed -r <line number>/^S+/<replace pattern>/g <infile> > <outfile>
When executing this very command (without the ´) from the console, I get this:
sed: -e expression #1, char 8: unterminated s' command
I guess this is because the ' are missing around the pattern.
So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?
bash sed
edited Oct 28 '15 at 10:16
serenesat
9341519
asked Oct 28 '15 at 9:42
entenbeinentenbein
12
bumped to the homepage by Community♦ 9 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
how could it possibly work? i dont see any input at all, and it looks like youre callingsedto work a single line at a time. if thats the case then$counterwont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do:while gen ouput; do :; done | sed 's/edit/the_whole_stream/'you'll be a lot better off.
– mikeserv
Oct 28 '15 at 9:46
$counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.
– entenbein
Oct 28 '15 at 9:57
awk or perl are better tools for doing that.
– cas
Oct 28 '15 at 10:02
1
Is there/ornin$linevariable? Any way try to executesed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile>for testing purpose. Is it doing what you wants?
– Costas
Oct 28 '15 at 10:16
Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.
– entenbein
Oct 28 '15 at 10:25
|
show 3 more comments
This is my sed command:
while ...;
do sed -r "${counter}s/^S+ /$line /g" $in > $out;
..
..
done
Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:
do echo ´sed -r "${counter}s/^S+/$line/g" $in > $out´;
which printed this to the console:
sed -r <line number>/^S+/<replace pattern>/g <infile> > <outfile>
When executing this very command (without the ´) from the console, I get this:
sed: -e expression #1, char 8: unterminated s' command
I guess this is because the ' are missing around the pattern.
So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?
bash sed
edited Oct 28 '15 at 10:16
serenesat
9341519
asked Oct 28 '15 at 9:42
entenbeinentenbein
12
This is my sed command:
while ...;
do sed -r "${counter}s/^S+ /$line /g" $in > $out;
..
..
done
Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:
do echo ´sed -r "${counter}s/^S+/$line/g" $in > $out´;
which printed this to the console:
sed -r <line number>/^S+/<replace pattern>/g <infile> > <outfile>
When executing this very command (without the ´) from the console, I get this:
sed: -e expression #1, char 8: unterminated s' command
I guess this is because the ' are missing around the pattern.
So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?
bash sed
bash sed
edited Oct 28 '15 at 10:16
serenesat
9341519
asked Oct 28 '15 at 9:42
entenbeinentenbein
12
edited Oct 28 '15 at 10:16
serenesat
9341519
asked Oct 28 '15 at 9:42
entenbeinentenbein
12
edited Oct 28 '15 at 10:16
serenesat
9341519
edited Oct 28 '15 at 10:16
serenesat
9341519
edited Oct 28 '15 at 10:16
serenesat
9341519
9341519
asked Oct 28 '15 at 9:42
entenbeinentenbein
12
asked Oct 28 '15 at 9:42
entenbeinentenbein
12
asked Oct 28 '15 at 9:42
entenbeinentenbein
12
12
bumped to the homepage by Community♦ 9 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 9 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
how could it possibly work? i dont see any input at all, and it looks like youre callingsedto work a single line at a time. if thats the case then$counterwont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do:while gen ouput; do :; done | sed 's/edit/the_whole_stream/'you'll be a lot better off.
– mikeserv
Oct 28 '15 at 9:46
$counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.
– entenbein
Oct 28 '15 at 9:57
awk or perl are better tools for doing that.
– cas
Oct 28 '15 at 10:02
1
Is there/ornin$linevariable? Any way try to executesed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile>for testing purpose. Is it doing what you wants?
– Costas
Oct 28 '15 at 10:16
Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.
– entenbein
Oct 28 '15 at 10:25
|
show 3 more comments
how could it possibly work? i dont see any input at all, and it looks like youre callingsedto work a single line at a time. if thats the case then$counterwont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do:while gen ouput; do :; done | sed 's/edit/the_whole_stream/'you'll be a lot better off.
– mikeserv
Oct 28 '15 at 9:46
$counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.
– entenbein
Oct 28 '15 at 9:57
awk or perl are better tools for doing that.
– cas
Oct 28 '15 at 10:02
1
Is there/ornin$linevariable? Any way try to executesed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile>for testing purpose. Is it doing what you wants?
– Costas
Oct 28 '15 at 10:16
Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.
– entenbein
Oct 28 '15 at 10:25
how could it possibly work? i dont see any input at all, and it looks like youre calling
sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off.– mikeserv
Oct 28 '15 at 9:46
how could it possibly work? i dont see any input at all, and it looks like youre calling
sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off.– mikeserv
Oct 28 '15 at 9:46
$counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.
– entenbein
Oct 28 '15 at 9:57
$counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.
– entenbein
Oct 28 '15 at 9:57
awk or perl are better tools for doing that.
– cas
Oct 28 '15 at 10:02
awk or perl are better tools for doing that.
– cas
Oct 28 '15 at 10:02
1
1
Is there
/ or n in $line variable? Any way try to execute sed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants?– Costas
Oct 28 '15 at 10:16
Is there
/ or n in $line variable? Any way try to execute sed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants?– Costas
Oct 28 '15 at 10:16
Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.
– entenbein
Oct 28 '15 at 10:25
Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.
– entenbein
Oct 28 '15 at 10:25
|
show 3 more comments
1 Answer
1
active
oldest
votes
Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....
Thanks for your help!
answered Oct 28 '15 at 10:57
entenbeinentenbein
12
add a comment |
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Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....
Thanks for your help!
answered Oct 28 '15 at 10:57
entenbeinentenbein
12
add a comment |
Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....
Thanks for your help!
answered Oct 28 '15 at 10:57
entenbeinentenbein
12
add a comment |
Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....
Thanks for your help!
answered Oct 28 '15 at 10:57
entenbeinentenbein
12
Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....
Thanks for your help!
answered Oct 28 '15 at 10:57
entenbeinentenbein
12
answered Oct 28 '15 at 10:57
entenbeinentenbein
12
answered Oct 28 '15 at 10:57
entenbeinentenbein
12
answered Oct 28 '15 at 10:57
entenbeinentenbein
12
12
add a comment |
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how could it possibly work? i dont see any input at all, and it looks like youre calling
sedto work a single line at a time. if thats the case then$counterwont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do:while gen ouput; do :; done | sed 's/edit/the_whole_stream/'you'll be a lot better off.– mikeserv
Oct 28 '15 at 9:46
$counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line.
– entenbein
Oct 28 '15 at 9:57
awk or perl are better tools for doing that.
– cas
Oct 28 '15 at 10:02
1
Is there
/ornin$linevariable? Any way try to executesed -r "<line number>/^S+/<replace pattern>/g" <infile> > <outfile>for testing purpose. Is it doing what you wants?– Costas
Oct 28 '15 at 10:16
Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far.
– entenbein
Oct 28 '15 at 10:25