How to grep for a particular string?












0















I am trying to get a string that matches the following pattern: starts with foo and finishes with bar.



grep -e "^foo*bar$"









share|improve this question


















  • 1





    o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

    – steeldriver
    33 mins ago











  • Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

    – Bionix1441
    30 mins ago











  • But you missed the point!

    – A.B
    29 mins ago











  • Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

    – Bionix1441
    25 mins ago











  • Well the point is actually a dot. A wild guess? Should I tell it before?

    – A.B
    16 mins ago
















0















I am trying to get a string that matches the following pattern: starts with foo and finishes with bar.



grep -e "^foo*bar$"









share|improve this question


















  • 1





    o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

    – steeldriver
    33 mins ago











  • Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

    – Bionix1441
    30 mins ago











  • But you missed the point!

    – A.B
    29 mins ago











  • Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

    – Bionix1441
    25 mins ago











  • Well the point is actually a dot. A wild guess? Should I tell it before?

    – A.B
    16 mins ago














0












0








0








I am trying to get a string that matches the following pattern: starts with foo and finishes with bar.



grep -e "^foo*bar$"









share|improve this question














I am trying to get a string that matches the following pattern: starts with foo and finishes with bar.



grep -e "^foo*bar$"






grep regular-expression






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 37 mins ago









Bionix1441Bionix1441

17113




17113








  • 1





    o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

    – steeldriver
    33 mins ago











  • Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

    – Bionix1441
    30 mins ago











  • But you missed the point!

    – A.B
    29 mins ago











  • Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

    – Bionix1441
    25 mins ago











  • Well the point is actually a dot. A wild guess? Should I tell it before?

    – A.B
    16 mins ago














  • 1





    o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

    – steeldriver
    33 mins ago











  • Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

    – Bionix1441
    30 mins ago











  • But you missed the point!

    – A.B
    29 mins ago











  • Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

    – Bionix1441
    25 mins ago











  • Well the point is actually a dot. A wild guess? Should I tell it before?

    – A.B
    16 mins ago








1




1





o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

– steeldriver
33 mins ago





o* will only match zero or more o characters - see How do regular expressions differ from wildcards used to filter files

– steeldriver
33 mins ago













Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

– Bionix1441
30 mins ago





Thanks, I did the following: grep -e "^foo" -e "bar$" file. This variant works.

– Bionix1441
30 mins ago













But you missed the point!

– A.B
29 mins ago





But you missed the point!

– A.B
29 mins ago













Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

– Bionix1441
25 mins ago





Maybe, if you want to tell me what is the point that I missed. I actually got the result I expected.

– Bionix1441
25 mins ago













Well the point is actually a dot. A wild guess? Should I tell it before?

– A.B
16 mins ago





Well the point is actually a dot. A wild guess? Should I tell it before?

– A.B
16 mins ago










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