Select lines with two occurences of same pattern
I have several lines of output, some lines contain information on jobs waiting
example
I want to select lines that have more than one occurrence of the pattern
jobs waiting: 0
example:
abcdef rglk,jobs waiting: 2,blah,blah,jobs waiting:0,jobs running: 1,blah,blah
lbf(kjn fk)kkj,jobs waiting: 2,blah,blah,jobs running: 1,blah,blah
gdjhgvdjh,jobs waiting: 0,blah,blah,jobs running: 1,blah,blah,jobs waiting: 0
g gg,jobs waiting: 2,blah,jobs waiting: 0,jobs running: 1,blah,blah
kjn dikfc,jobs waiting: 0,blah,jobs waiting: 0,jobs running: 1,bl ah,blah
d1d,jobs waiting: 2,blah,blah,jobs running: 1,blah,blah
kjfdk nrf(lkj rgf),jobs waiting: 2,blah,blah,jobs waiting: 0,bl ah,blah
would work if the command only returns line 3 and line 5
I would also like to be able to select lines that are opposite to this
Unfortunately I have no idea how to do this, with sed? awk? grep?
awk sed grep
edited 22 mins ago
Sparhawk
9,94464296
asked 34 mins ago
David JenkinsDavid Jenkins
61
New contributor
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
I have several lines of output, some lines contain information on jobs waiting
example
I want to select lines that have more than one occurrence of the pattern
jobs waiting: 0
example:
abcdef rglk,jobs waiting: 2,blah,blah,jobs waiting:0,jobs running: 1,blah,blah
lbf(kjn fk)kkj,jobs waiting: 2,blah,blah,jobs running: 1,blah,blah
gdjhgvdjh,jobs waiting: 0,blah,blah,jobs running: 1,blah,blah,jobs waiting: 0
g gg,jobs waiting: 2,blah,jobs waiting: 0,jobs running: 1,blah,blah
kjn dikfc,jobs waiting: 0,blah,jobs waiting: 0,jobs running: 1,bl ah,blah
d1d,jobs waiting: 2,blah,blah,jobs running: 1,blah,blah
kjfdk nrf(lkj rgf),jobs waiting: 2,blah,blah,jobs waiting: 0,bl ah,blah
would work if the command only returns line 3 and line 5
I would also like to be able to select lines that are opposite to this
Unfortunately I have no idea how to do this, with sed? awk? grep?
awk sed grep
edited 22 mins ago
Sparhawk
9,94464296
asked 34 mins ago
David JenkinsDavid Jenkins
61
New contributor
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have several lines of output, some lines contain information on jobs waiting
example
I want to select lines that have more than one occurrence of the pattern
jobs waiting: 0
example:
abcdef rglk,jobs waiting: 2,blah,blah,jobs waiting:0,jobs running: 1,blah,blah
lbf(kjn fk)kkj,jobs waiting: 2,blah,blah,jobs running: 1,blah,blah
gdjhgvdjh,jobs waiting: 0,blah,blah,jobs running: 1,blah,blah,jobs waiting: 0
g gg,jobs waiting: 2,blah,jobs waiting: 0,jobs running: 1,blah,blah
kjn dikfc,jobs waiting: 0,blah,jobs waiting: 0,jobs running: 1,bl ah,blah
d1d,jobs waiting: 2,blah,blah,jobs running: 1,blah,blah
kjfdk nrf(lkj rgf),jobs waiting: 2,blah,blah,jobs waiting: 0,bl ah,blah
would work if the command only returns line 3 and line 5
I would also like to be able to select lines that are opposite to this
Unfortunately I have no idea how to do this, with sed? awk? grep?
awk sed grep
edited 22 mins ago
Sparhawk
9,94464296
asked 34 mins ago
David JenkinsDavid Jenkins
61
New contributor
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have several lines of output, some lines contain information on jobs waiting
example
I want to select lines that have more than one occurrence of the pattern
jobs waiting: 0
example:
abcdef rglk,jobs waiting: 2,blah,blah,jobs waiting:0,jobs running: 1,blah,blah
lbf(kjn fk)kkj,jobs waiting: 2,blah,blah,jobs running: 1,blah,blah
gdjhgvdjh,jobs waiting: 0,blah,blah,jobs running: 1,blah,blah,jobs waiting: 0
g gg,jobs waiting: 2,blah,jobs waiting: 0,jobs running: 1,blah,blah
kjn dikfc,jobs waiting: 0,blah,jobs waiting: 0,jobs running: 1,bl ah,blah
d1d,jobs waiting: 2,blah,blah,jobs running: 1,blah,blah
kjfdk nrf(lkj rgf),jobs waiting: 2,blah,blah,jobs waiting: 0,bl ah,blah
would work if the command only returns line 3 and line 5
I would also like to be able to select lines that are opposite to this
Unfortunately I have no idea how to do this, with sed? awk? grep?
awk sed grep
awk sed grep
edited 22 mins ago
Sparhawk
9,94464296
asked 34 mins ago
David JenkinsDavid Jenkins
61
New contributor
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 22 mins ago
Sparhawk
9,94464296
asked 34 mins ago
David JenkinsDavid Jenkins
61
New contributor
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 22 mins ago
Sparhawk
9,94464296
edited 22 mins ago
Sparhawk
9,94464296
edited 22 mins ago
Sparhawk
9,94464296
9,94464296
asked 34 mins ago
David JenkinsDavid Jenkins
61
New contributor
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 34 mins ago
David JenkinsDavid Jenkins
61
asked 34 mins ago
David JenkinsDavid Jenkins
61
61
New contributor
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
David Jenkins is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
KISS grep approach:
grep 'jobs waiting: *0.*jobs waiting: *0' file
Invert by adding the -v command line switch.
Alternate with sed - attempt to replace the second instance, and print the line if it succeeds:
sed -n 's/jobs waiting: *0/&/2p' file
Inverse as
sed -n 's/jobs waiting: *0/&/2; t; p' file
Awk approach - use the return value of a gsub:
awk 'gsub(/jobs waiting: *0/,"&",$0) == 2' file
Invert as
awk 'gsub(/jobs waiting: *0/,"&",$0) != 2' file
(In all cases, *0 allows for zero or more space characters before the 0, consistent with your example.)
answered 20 mins ago
steeldriversteeldriver
36.1k35286
May I ask what is "KISS"?
– Tim
11 mins ago
@Tim KISS principle
– steeldriver
9 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
KISS grep approach:
grep 'jobs waiting: *0.*jobs waiting: *0' file
Invert by adding the -v command line switch.
Alternate with sed - attempt to replace the second instance, and print the line if it succeeds:
sed -n 's/jobs waiting: *0/&/2p' file
Inverse as
sed -n 's/jobs waiting: *0/&/2; t; p' file
Awk approach - use the return value of a gsub:
awk 'gsub(/jobs waiting: *0/,"&",$0) == 2' file
Invert as
awk 'gsub(/jobs waiting: *0/,"&",$0) != 2' file
(In all cases, *0 allows for zero or more space characters before the 0, consistent with your example.)
answered 20 mins ago
steeldriversteeldriver
36.1k35286
May I ask what is "KISS"?
– Tim
11 mins ago
@Tim KISS principle
– steeldriver
9 mins ago
add a comment |
KISS grep approach:
grep 'jobs waiting: *0.*jobs waiting: *0' file
Invert by adding the -v command line switch.
Alternate with sed - attempt to replace the second instance, and print the line if it succeeds:
sed -n 's/jobs waiting: *0/&/2p' file
Inverse as
sed -n 's/jobs waiting: *0/&/2; t; p' file
Awk approach - use the return value of a gsub:
awk 'gsub(/jobs waiting: *0/,"&",$0) == 2' file
Invert as
awk 'gsub(/jobs waiting: *0/,"&",$0) != 2' file
(In all cases, *0 allows for zero or more space characters before the 0, consistent with your example.)
answered 20 mins ago
steeldriversteeldriver
36.1k35286
May I ask what is "KISS"?
– Tim
11 mins ago
@Tim KISS principle
– steeldriver
9 mins ago
add a comment |
KISS grep approach:
grep 'jobs waiting: *0.*jobs waiting: *0' file
Invert by adding the -v command line switch.
Alternate with sed - attempt to replace the second instance, and print the line if it succeeds:
sed -n 's/jobs waiting: *0/&/2p' file
Inverse as
sed -n 's/jobs waiting: *0/&/2; t; p' file
Awk approach - use the return value of a gsub:
awk 'gsub(/jobs waiting: *0/,"&",$0) == 2' file
Invert as
awk 'gsub(/jobs waiting: *0/,"&",$0) != 2' file
(In all cases, *0 allows for zero or more space characters before the 0, consistent with your example.)
answered 20 mins ago
steeldriversteeldriver
36.1k35286
KISS grep approach:
grep 'jobs waiting: *0.*jobs waiting: *0' file
Invert by adding the -v command line switch.
Alternate with sed - attempt to replace the second instance, and print the line if it succeeds:
sed -n 's/jobs waiting: *0/&/2p' file
Inverse as
sed -n 's/jobs waiting: *0/&/2; t; p' file
Awk approach - use the return value of a gsub:
awk 'gsub(/jobs waiting: *0/,"&",$0) == 2' file
Invert as
awk 'gsub(/jobs waiting: *0/,"&",$0) != 2' file
(In all cases, *0 allows for zero or more space characters before the 0, consistent with your example.)
answered 20 mins ago
steeldriversteeldriver
36.1k35286
edited 5 mins ago
answered 20 mins ago
steeldriversteeldriver
36.1k35286
answered 20 mins ago
steeldriversteeldriver
36.1k35286
answered 20 mins ago
steeldriversteeldriver
36.1k35286
36.1k35286
May I ask what is "KISS"?
– Tim
11 mins ago
@Tim KISS principle
– steeldriver
9 mins ago
add a comment |
May I ask what is "KISS"?
– Tim
11 mins ago
@Tim KISS principle
– steeldriver
9 mins ago
May I ask what is "KISS"?
– Tim
11 mins ago
May I ask what is "KISS"?
– Tim
11 mins ago
@Tim KISS principle
– steeldriver
9 mins ago
@Tim KISS principle
– steeldriver
9 mins ago
add a comment |
David Jenkins is a new contributor. Be nice, and check out our Code of Conduct.
David Jenkins is a new contributor. Be nice, and check out our Code of Conduct.
David Jenkins is a new contributor. Be nice, and check out our Code of Conduct.
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