Getting exit code from curl in bash script
I want to take the output of simple.sh, a script from the internet and check its exit code.
#!/bin/bash
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ -z "$?" ]; then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
simple.sh:
#!/bin/bash
exit 0
The problem I am getting is:
./test.sh: line 2: #!/bin/bash: No such file or directory
Bad
Any help is much appreciated.
Thank you
bash shell-script curl
edited 59 mins ago
Inian
5,0151429
asked 3 hours ago
RiceRice
17110
add a comment |
I want to take the output of simple.sh, a script from the internet and check its exit code.
#!/bin/bash
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ -z "$?" ]; then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
simple.sh:
#!/bin/bash
exit 0
The problem I am getting is:
./test.sh: line 2: #!/bin/bash: No such file or directory
Bad
Any help is much appreciated.
Thank you
bash shell-script curl
edited 59 mins ago
Inian
5,0151429
asked 3 hours ago
RiceRice
17110
Try adding the full path tocurl, i.e. the output fromtype curl. Probably a path issue.
– datUser
3 hours ago
tryeval "$(curl ...)"
– Jonas
2 hours ago
add a comment |
I want to take the output of simple.sh, a script from the internet and check its exit code.
#!/bin/bash
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ -z "$?" ]; then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
simple.sh:
#!/bin/bash
exit 0
The problem I am getting is:
./test.sh: line 2: #!/bin/bash: No such file or directory
Bad
Any help is much appreciated.
Thank you
bash shell-script curl
edited 59 mins ago
Inian
5,0151429
asked 3 hours ago
RiceRice
17110
I want to take the output of simple.sh, a script from the internet and check its exit code.
#!/bin/bash
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ -z "$?" ]; then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
simple.sh:
#!/bin/bash
exit 0
The problem I am getting is:
./test.sh: line 2: #!/bin/bash: No such file or directory
Bad
Any help is much appreciated.
Thank you
bash shell-script curl
bash shell-script curl
edited 59 mins ago
Inian
5,0151429
asked 3 hours ago
RiceRice
17110
edited 59 mins ago
Inian
5,0151429
asked 3 hours ago
RiceRice
17110
edited 59 mins ago
Inian
5,0151429
edited 59 mins ago
Inian
5,0151429
edited 59 mins ago
Inian
5,0151429
5,0151429
asked 3 hours ago
RiceRice
17110
asked 3 hours ago
RiceRice
17110
asked 3 hours ago
RiceRice
17110
17110
Try adding the full path tocurl, i.e. the output fromtype curl. Probably a path issue.
– datUser
3 hours ago
tryeval "$(curl ...)"
– Jonas
2 hours ago
add a comment |
Try adding the full path tocurl, i.e. the output fromtype curl. Probably a path issue.
– datUser
3 hours ago
tryeval "$(curl ...)"
– Jonas
2 hours ago
Try adding the full path to
curl, i.e. the output from type curl. Probably a path issue.– datUser
3 hours ago
Try adding the full path to
curl, i.e. the output from type curl. Probably a path issue.– datUser
3 hours ago
try
eval "$(curl ...)"– Jonas
2 hours ago
try
eval "$(curl ...)"– Jonas
2 hours ago
add a comment |
2 Answers
2
active
oldest
votes
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 2 hours ago
Scottie HScottie H
326
add a comment |
Your idea is right, but you seem to have defined a wrong conditional for checking the return code with [ -z "$?" ] which checks if the return code string is empty or not. Irrespective of the result of the curl output, your $? will carry a value which means, you'll never assert the if condition of your script. You probably need to check the return code that curl returns directly in your script
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ "$?" -eq 0 ]; then
which is same as saying
if [ "$(curl -s http://127.0.0.1:8000/simple.sh)" -eq 0 ]; then
or even more tersely written without the test operator to allow the return code to be directly used in the if condition
if curl -s http://127.0.0.1:8000/simple.sh; then
answered 1 hour ago
InianInian
5,0151429
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "106"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f505984%2fgetting-exit-code-from-curl-in-bash-script%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 2 hours ago
Scottie HScottie H
326
add a comment |
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 2 hours ago
Scottie HScottie H
326
add a comment |
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 2 hours ago
Scottie HScottie H
326
Can't say it's elegant, but this is the way I would do it:#!/bin/bash
curl -s http://127.0.0.1:8000/simple.sh | /bin/bash -s >/dev/null 2>&1
rc=$?
if [ -z "$rc" ]
then
echo "Good"
exit 0
else
echo "Bad"
exit 1
fi
Seems to me, the way you are doing it is similar to executing a here-file inside the $( ... ) construct. Never tried that, not sure bash works that way.
Letting curl echo the contents of the file and piping it to bash accounts for the text output of the curl command and allows bash to execute it.
I'll bet that, if you try this, you will get the same results:$( cat /[path]/simple.sh ); echo $?
answered 2 hours ago
Scottie HScottie H
326
answered 2 hours ago
Scottie HScottie H
326
answered 2 hours ago
Scottie HScottie H
326
answered 2 hours ago
Scottie HScottie H
326
326
add a comment |
add a comment |
Your idea is right, but you seem to have defined a wrong conditional for checking the return code with [ -z "$?" ] which checks if the return code string is empty or not. Irrespective of the result of the curl output, your $? will carry a value which means, you'll never assert the if condition of your script. You probably need to check the return code that curl returns directly in your script
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ "$?" -eq 0 ]; then
which is same as saying
if [ "$(curl -s http://127.0.0.1:8000/simple.sh)" -eq 0 ]; then
or even more tersely written without the test operator to allow the return code to be directly used in the if condition
if curl -s http://127.0.0.1:8000/simple.sh; then
answered 1 hour ago
InianInian
5,0151429
add a comment |
Your idea is right, but you seem to have defined a wrong conditional for checking the return code with [ -z "$?" ] which checks if the return code string is empty or not. Irrespective of the result of the curl output, your $? will carry a value which means, you'll never assert the if condition of your script. You probably need to check the return code that curl returns directly in your script
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ "$?" -eq 0 ]; then
which is same as saying
if [ "$(curl -s http://127.0.0.1:8000/simple.sh)" -eq 0 ]; then
or even more tersely written without the test operator to allow the return code to be directly used in the if condition
if curl -s http://127.0.0.1:8000/simple.sh; then
answered 1 hour ago
InianInian
5,0151429
add a comment |
Your idea is right, but you seem to have defined a wrong conditional for checking the return code with [ -z "$?" ] which checks if the return code string is empty or not. Irrespective of the result of the curl output, your $? will carry a value which means, you'll never assert the if condition of your script. You probably need to check the return code that curl returns directly in your script
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ "$?" -eq 0 ]; then
which is same as saying
if [ "$(curl -s http://127.0.0.1:8000/simple.sh)" -eq 0 ]; then
or even more tersely written without the test operator to allow the return code to be directly used in the if condition
if curl -s http://127.0.0.1:8000/simple.sh; then
answered 1 hour ago
InianInian
5,0151429
Your idea is right, but you seem to have defined a wrong conditional for checking the return code with [ -z "$?" ] which checks if the return code string is empty or not. Irrespective of the result of the curl output, your $? will carry a value which means, you'll never assert the if condition of your script. You probably need to check the return code that curl returns directly in your script
$(curl -s http://127.0.0.1:8000/simple.sh)
if [ "$?" -eq 0 ]; then
which is same as saying
if [ "$(curl -s http://127.0.0.1:8000/simple.sh)" -eq 0 ]; then
or even more tersely written without the test operator to allow the return code to be directly used in the if condition
if curl -s http://127.0.0.1:8000/simple.sh; then
answered 1 hour ago
InianInian
5,0151429
answered 1 hour ago
InianInian
5,0151429
answered 1 hour ago
InianInian
5,0151429
answered 1 hour ago
InianInian
5,0151429
5,0151429
add a comment |
add a comment |
Thanks for contributing an answer to Unix & Linux Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f505984%2fgetting-exit-code-from-curl-in-bash-script%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Try adding the full path to
curl, i.e. the output fromtype curl. Probably a path issue.– datUser
3 hours ago
try
eval "$(curl ...)"– Jonas
2 hours ago