Error converting a bash function to a csh alias
3
I am writing a csh alias so that I can use the following bash function in my csh :
function up( )
{
LIMIT=$1
P=$PWD
for ((i=1; i <= LIMIT; i++))
do
P=$P/..
done
cd $P
export MPWD=$P
}
(I stole the above bash function from here)
I have written this:
alias up 'set LIMIT=$1; set P=$PWD; set counter = LIMIT; while[counter!=0] set counter = counter-1; P=$P/.. ; end cd $P; setenv MPWD=$P'
However, I am getting the following error:
while[counter!=0]: No match.
P=/net/devstorage/home/rghosh/..: Command not found.
end: Too many arguments.
and my script is not working as intended. I have been reading up on csh from here.
csh
edited 2 hours ago
Rui F Ribeiro
41.5k1483140
asked Jan 21 '13 at 17:03
ChaniChani
229414
add a comment |
3
I am writing a csh alias so that I can use the following bash function in my csh :
function up( )
{
LIMIT=$1
P=$PWD
for ((i=1; i <= LIMIT; i++))
do
P=$P/..
done
cd $P
export MPWD=$P
}
(I stole the above bash function from here)
I have written this:
alias up 'set LIMIT=$1; set P=$PWD; set counter = LIMIT; while[counter!=0] set counter = counter-1; P=$P/.. ; end cd $P; setenv MPWD=$P'
However, I am getting the following error:
while[counter!=0]: No match.
P=/net/devstorage/home/rghosh/..: Command not found.
end: Too many arguments.
and my script is not working as intended. I have been reading up on csh from here.
csh
edited 2 hours ago
Rui F Ribeiro
41.5k1483140
asked Jan 21 '13 at 17:03
ChaniChani
229414
add a comment |
3
3
3
I am writing a csh alias so that I can use the following bash function in my csh :
function up( )
{
LIMIT=$1
P=$PWD
for ((i=1; i <= LIMIT; i++))
do
P=$P/..
done
cd $P
export MPWD=$P
}
(I stole the above bash function from here)
I have written this:
alias up 'set LIMIT=$1; set P=$PWD; set counter = LIMIT; while[counter!=0] set counter = counter-1; P=$P/.. ; end cd $P; setenv MPWD=$P'
However, I am getting the following error:
while[counter!=0]: No match.
P=/net/devstorage/home/rghosh/..: Command not found.
end: Too many arguments.
and my script is not working as intended. I have been reading up on csh from here.
csh
edited 2 hours ago
Rui F Ribeiro
41.5k1483140
asked Jan 21 '13 at 17:03
ChaniChani
229414
I am writing a csh alias so that I can use the following bash function in my csh :
function up( )
{
LIMIT=$1
P=$PWD
for ((i=1; i <= LIMIT; i++))
do
P=$P/..
done
cd $P
export MPWD=$P
}
(I stole the above bash function from here)
I have written this:
alias up 'set LIMIT=$1; set P=$PWD; set counter = LIMIT; while[counter!=0] set counter = counter-1; P=$P/.. ; end cd $P; setenv MPWD=$P'
However, I am getting the following error:
while[counter!=0]: No match.
P=/net/devstorage/home/rghosh/..: Command not found.
end: Too many arguments.
and my script is not working as intended. I have been reading up on csh from here.
csh
csh
edited 2 hours ago
Rui F Ribeiro
41.5k1483140
asked Jan 21 '13 at 17:03
ChaniChani
229414
edited 2 hours ago
Rui F Ribeiro
41.5k1483140
asked Jan 21 '13 at 17:03
ChaniChani
229414
edited 2 hours ago
Rui F Ribeiro
41.5k1483140
edited 2 hours ago
Rui F Ribeiro
41.5k1483140
edited 2 hours ago
Rui F Ribeiro
41.5k1483140
41.5k1483140
asked Jan 21 '13 at 17:03
ChaniChani
229414
asked Jan 21 '13 at 17:03
ChaniChani
229414
asked Jan 21 '13 at 17:03
ChaniChani
229414
229414
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
I’m not sure it’s even possible to do a while loop all on one line.
But there are several fixable errors:
while[counter!=0]should bewhile ($counter != 1)
(note the spaces before and after the “!=”).
set counter = counter-1should be@ counter = $counter – 1
(note the spaces before and after the ‘–’).
P=$P/..should beset P=$P/..–– or better yet,set P="$P/.."(in case$Pcontains space(s).- Which reminds me,
set P=$PWDshould beset P="$PWD",cd $Pshould becd "$P", andsetenv MPWD=$Pshould besetenv MPWD="$P", all for the same reason. - And, if you do manage to get the
whileloop all on one line to work, you’re probably going to need a;after theend.
answered Jan 22 '13 at 3:46
ScottScott
6,99252751
I had to write the while loop in a single line because I was getting a horde of errors while using the the next line facility using/
– Chani
Jan 22 '13 at 5:26
OK, but my point is: have you ever gotten a ‘while loop in a single line’ to work? If yes, please post an example; even if it’s something trivial likemkdir –p foo/foo/foo; while { cd foo } pwd; end.
– Scott
Jan 22 '13 at 16:07
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
I’m not sure it’s even possible to do a while loop all on one line.
But there are several fixable errors:
while[counter!=0]should bewhile ($counter != 1)
(note the spaces before and after the “!=”).
set counter = counter-1should be@ counter = $counter – 1
(note the spaces before and after the ‘–’).
P=$P/..should beset P=$P/..–– or better yet,set P="$P/.."(in case$Pcontains space(s).- Which reminds me,
set P=$PWDshould beset P="$PWD",cd $Pshould becd "$P", andsetenv MPWD=$Pshould besetenv MPWD="$P", all for the same reason. - And, if you do manage to get the
whileloop all on one line to work, you’re probably going to need a;after theend.
answered Jan 22 '13 at 3:46
ScottScott
6,99252751
I had to write the while loop in a single line because I was getting a horde of errors while using the the next line facility using/
– Chani
Jan 22 '13 at 5:26
OK, but my point is: have you ever gotten a ‘while loop in a single line’ to work? If yes, please post an example; even if it’s something trivial likemkdir –p foo/foo/foo; while { cd foo } pwd; end.
– Scott
Jan 22 '13 at 16:07
add a comment |
1
I’m not sure it’s even possible to do a while loop all on one line.
But there are several fixable errors:
while[counter!=0]should bewhile ($counter != 1)
(note the spaces before and after the “!=”).
set counter = counter-1should be@ counter = $counter – 1
(note the spaces before and after the ‘–’).
P=$P/..should beset P=$P/..–– or better yet,set P="$P/.."(in case$Pcontains space(s).- Which reminds me,
set P=$PWDshould beset P="$PWD",cd $Pshould becd "$P", andsetenv MPWD=$Pshould besetenv MPWD="$P", all for the same reason. - And, if you do manage to get the
whileloop all on one line to work, you’re probably going to need a;after theend.
answered Jan 22 '13 at 3:46
ScottScott
6,99252751
I had to write the while loop in a single line because I was getting a horde of errors while using the the next line facility using/
– Chani
Jan 22 '13 at 5:26
OK, but my point is: have you ever gotten a ‘while loop in a single line’ to work? If yes, please post an example; even if it’s something trivial likemkdir –p foo/foo/foo; while { cd foo } pwd; end.
– Scott
Jan 22 '13 at 16:07
add a comment |
1
1
1
I’m not sure it’s even possible to do a while loop all on one line.
But there are several fixable errors:
while[counter!=0]should bewhile ($counter != 1)
(note the spaces before and after the “!=”).
set counter = counter-1should be@ counter = $counter – 1
(note the spaces before and after the ‘–’).
P=$P/..should beset P=$P/..–– or better yet,set P="$P/.."(in case$Pcontains space(s).- Which reminds me,
set P=$PWDshould beset P="$PWD",cd $Pshould becd "$P", andsetenv MPWD=$Pshould besetenv MPWD="$P", all for the same reason. - And, if you do manage to get the
whileloop all on one line to work, you’re probably going to need a;after theend.
answered Jan 22 '13 at 3:46
ScottScott
6,99252751
I’m not sure it’s even possible to do a while loop all on one line.
But there are several fixable errors:
while[counter!=0]should bewhile ($counter != 1)
(note the spaces before and after the “!=”).
set counter = counter-1should be@ counter = $counter – 1
(note the spaces before and after the ‘–’).
P=$P/..should beset P=$P/..–– or better yet,set P="$P/.."(in case$Pcontains space(s).- Which reminds me,
set P=$PWDshould beset P="$PWD",cd $Pshould becd "$P", andsetenv MPWD=$Pshould besetenv MPWD="$P", all for the same reason. - And, if you do manage to get the
whileloop all on one line to work, you’re probably going to need a;after theend.
answered Jan 22 '13 at 3:46
ScottScott
6,99252751
answered Jan 22 '13 at 3:46
ScottScott
6,99252751
answered Jan 22 '13 at 3:46
ScottScott
6,99252751
answered Jan 22 '13 at 3:46
ScottScott
6,99252751
6,99252751
I had to write the while loop in a single line because I was getting a horde of errors while using the the next line facility using/
– Chani
Jan 22 '13 at 5:26
OK, but my point is: have you ever gotten a ‘while loop in a single line’ to work? If yes, please post an example; even if it’s something trivial likemkdir –p foo/foo/foo; while { cd foo } pwd; end.
– Scott
Jan 22 '13 at 16:07
add a comment |
I had to write the while loop in a single line because I was getting a horde of errors while using the the next line facility using/
– Chani
Jan 22 '13 at 5:26
OK, but my point is: have you ever gotten a ‘while loop in a single line’ to work? If yes, please post an example; even if it’s something trivial likemkdir –p foo/foo/foo; while { cd foo } pwd; end.
– Scott
Jan 22 '13 at 16:07
I had to write the while loop in a single line because I was getting a horde of errors while using the the next line facility using
/– Chani
Jan 22 '13 at 5:26
I had to write the while loop in a single line because I was getting a horde of errors while using the the next line facility using
/– Chani
Jan 22 '13 at 5:26
OK, but my point is: have you ever gotten a ‘while loop in a single line’ to work? If yes, please post an example; even if it’s something trivial like
mkdir –p foo/foo/foo; while { cd foo } pwd; end.– Scott
Jan 22 '13 at 16:07
OK, but my point is: have you ever gotten a ‘while loop in a single line’ to work? If yes, please post an example; even if it’s something trivial like
mkdir –p foo/foo/foo; while { cd foo } pwd; end.– Scott
Jan 22 '13 at 16:07
add a comment |
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