No system call when malloc after free












0















Hello StackExchange community.



While I was playing a little with kernel audit system, I made a small C program:



#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv){
void *t;
while(1){
t = malloc(1);
free(t);

}
return 0;
}


And applied the following filters to audit:



-a always,exit -F arch=b32 -S open,openat -F exit=-EACCES -F key=access
-a always,exit -F arch=b64 -S open,openat -F exit=-EACCES -F key=access
-a always,exit -F arch=b32 -S brk
-a always,exit -F arch=b64 -S brk


After compiling and running, I noticed that sys_brk wasn't showing up in the audit log.
Furthermore it didn't also appear in strace, even tho malloc was called (checked with ltrace).
Lastly I removed the free and the calls to sys_brk started showing up.



My question is what is causing this type of behaviour? Does glibc make some kind of optimization in malloc and free functions to prevent useless syscalls?



Thank you for your time.



TL;DR: free followed by malloc makes neither call the kernel. Why?










share|improve this question























  • It might use brk () or mmap ()

    – 炸鱼薯条德里克
    10 mins ago


















0















Hello StackExchange community.



While I was playing a little with kernel audit system, I made a small C program:



#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv){
void *t;
while(1){
t = malloc(1);
free(t);

}
return 0;
}


And applied the following filters to audit:



-a always,exit -F arch=b32 -S open,openat -F exit=-EACCES -F key=access
-a always,exit -F arch=b64 -S open,openat -F exit=-EACCES -F key=access
-a always,exit -F arch=b32 -S brk
-a always,exit -F arch=b64 -S brk


After compiling and running, I noticed that sys_brk wasn't showing up in the audit log.
Furthermore it didn't also appear in strace, even tho malloc was called (checked with ltrace).
Lastly I removed the free and the calls to sys_brk started showing up.



My question is what is causing this type of behaviour? Does glibc make some kind of optimization in malloc and free functions to prevent useless syscalls?



Thank you for your time.



TL;DR: free followed by malloc makes neither call the kernel. Why?










share|improve this question























  • It might use brk () or mmap ()

    – 炸鱼薯条德里克
    10 mins ago
















0












0








0








Hello StackExchange community.



While I was playing a little with kernel audit system, I made a small C program:



#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv){
void *t;
while(1){
t = malloc(1);
free(t);

}
return 0;
}


And applied the following filters to audit:



-a always,exit -F arch=b32 -S open,openat -F exit=-EACCES -F key=access
-a always,exit -F arch=b64 -S open,openat -F exit=-EACCES -F key=access
-a always,exit -F arch=b32 -S brk
-a always,exit -F arch=b64 -S brk


After compiling and running, I noticed that sys_brk wasn't showing up in the audit log.
Furthermore it didn't also appear in strace, even tho malloc was called (checked with ltrace).
Lastly I removed the free and the calls to sys_brk started showing up.



My question is what is causing this type of behaviour? Does glibc make some kind of optimization in malloc and free functions to prevent useless syscalls?



Thank you for your time.



TL;DR: free followed by malloc makes neither call the kernel. Why?










share|improve this question














Hello StackExchange community.



While I was playing a little with kernel audit system, I made a small C program:



#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv){
void *t;
while(1){
t = malloc(1);
free(t);

}
return 0;
}


And applied the following filters to audit:



-a always,exit -F arch=b32 -S open,openat -F exit=-EACCES -F key=access
-a always,exit -F arch=b64 -S open,openat -F exit=-EACCES -F key=access
-a always,exit -F arch=b32 -S brk
-a always,exit -F arch=b64 -S brk


After compiling and running, I noticed that sys_brk wasn't showing up in the audit log.
Furthermore it didn't also appear in strace, even tho malloc was called (checked with ltrace).
Lastly I removed the free and the calls to sys_brk started showing up.



My question is what is causing this type of behaviour? Does glibc make some kind of optimization in malloc and free functions to prevent useless syscalls?



Thank you for your time.



TL;DR: free followed by malloc makes neither call the kernel. Why?







linux linux-kernel linux-audit






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 18 mins ago









Jorge HelenoJorge Heleno

1114




1114













  • It might use brk () or mmap ()

    – 炸鱼薯条德里克
    10 mins ago





















  • It might use brk () or mmap ()

    – 炸鱼薯条德里克
    10 mins ago



















It might use brk () or mmap ()

– 炸鱼薯条德里克
10 mins ago







It might use brk () or mmap ()

– 炸鱼薯条德里克
10 mins ago












0






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