Selecting elements from lists based on string pattern












1












$begingroup$


I have a list:



lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}


I would like to select list items that have first elements that end in the string "bc" to give:



res = {{1,2},{5,6}}


This is a variant on this question which has to do with strings only. Thank you as always for suggestions.






list-manipulation string-manipulation







share|improve this question









$endgroup$

















    1












    $begingroup$


    I have a list:



    lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}


    I would like to select list items that have first elements that end in the string "bc" to give:



    res = {{1,2},{5,6}}


    This is a variant on this question which has to do with strings only. Thank you as always for suggestions.






    list-manipulation string-manipulation







    share|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      I have a list:



      lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}


      I would like to select list items that have first elements that end in the string "bc" to give:



      res = {{1,2},{5,6}}


      This is a variant on this question which has to do with strings only. Thank you as always for suggestions.






      list-manipulation string-manipulation







      share|improve this question









      $endgroup$




      I have a list:



      lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}


      I would like to select list items that have first elements that end in the string "bc" to give:



      res = {{1,2},{5,6}}


      This is a variant on this question which has to do with strings only. Thank you as always for suggestions.






      list-manipulation string-manipulation




      list-manipulation string-manipulation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 3 hours ago









      Suite401Suite401

      988312




      988312






















          3 Answers
          3






          active

          oldest

          votes


















          2












          $begingroup$

          Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



          {{1, 2}, {5, 6}}




          Also



          f[{_String?(StringEndsQ["bc"]), x__}] := {x}
          
f[_] := Sequence
          
f /@ lis



          {{1, 2}, {5, 6}}







          share|improve this answer









          $endgroup$





















            1












            $begingroup$

            This uses string matching on the first element of each sublist and then discards the first element from the matches.



            lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
            
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
            

            
(* {{1, 2}, {5, 6}} *)


            You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.






            share|improve this answer









            $endgroup$





















              1












              $begingroup$

              lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


              Using Cases



              Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
              
  Infinity]
              

              
(* {{1, 2}, {5, 6}} *)


              or



              Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
              

              
(* {{1, 2}, {5, 6}} *)


              Or using Select



              Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
              

              
(* {{1, 2}, {5, 6}} *)


              Or using DeleteCases



              Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
              
  Infinity]
              

              
(* {{1, 2}, {5, 6}} *)





              share|improve this answer









              $endgroup$













                Your Answer





                StackExchange.ifUsing("editor", function () {
                return StackExchange.using("mathjaxEditing", function () {
                StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
                StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
                });
                });
                }, "mathjax-editing");

                StackExchange.ready(function() {
                var channelOptions = {
                tags: "".split(" "),
                id: "387"
                };
                initTagRenderer("".split(" "), "".split(" "), channelOptions);

                StackExchange.using("externalEditor", function() {
                // Have to fire editor after snippets, if snippets enabled
                if (StackExchange.settings.snippets.snippetsEnabled) {
                StackExchange.using("snippets", function() {
                createEditor();
                });
                }
                else {
                createEditor();
                }
                });

                function createEditor() {
                StackExchange.prepareEditor({
                heartbeatType: 'answer',
                autoActivateHeartbeat: false,
                convertImagesToLinks: false,
                noModals: true,
                showLowRepImageUploadWarning: true,
                reputationToPostImages: null,
                bindNavPrevention: true,
                postfix: "",
                imageUploader: {
                brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
                contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
                allowUrls: true
                },
                onDemand: true,
                discardSelector: ".discard-answer"
                ,immediatelyShowMarkdownHelp:true
                });


                }
                });














                draft saved

                draft discarded


















                StackExchange.ready(
                function () {
                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f190698%2fselecting-elements-from-lists-based-on-string-pattern%23new-answer', 'question_page');
                }
                );

                Post as a guest















                Required, but never shown

























                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                2












                $begingroup$

                Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



                {{1, 2}, {5, 6}}




                Also



                f[{_String?(StringEndsQ["bc"]), x__}] := {x}
                
f[_] := Sequence
                
f /@ lis



                {{1, 2}, {5, 6}}







                share|improve this answer









                $endgroup$


















                  2












                  $begingroup$

                  Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



                  {{1, 2}, {5, 6}}




                  Also



                  f[{_String?(StringEndsQ["bc"]), x__}] := {x}
                  
f[_] := Sequence
                  
f /@ lis



                  {{1, 2}, {5, 6}}







                  share|improve this answer









                  $endgroup$
















                    2












                    2








                    2





                    $begingroup$

                    Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



                    {{1, 2}, {5, 6}}




                    Also



                    f[{_String?(StringEndsQ["bc"]), x__}] := {x}
                    
f[_] := Sequence
                    
f /@ lis



                    {{1, 2}, {5, 6}}







                    share|improve this answer









                    $endgroup$



                    Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



                    {{1, 2}, {5, 6}}




                    Also



                    f[{_String?(StringEndsQ["bc"]), x__}] := {x}
                    
f[_] := Sequence
                    
f /@ lis



                    {{1, 2}, {5, 6}}








                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 27 mins ago









                    kglrkglr

                    181k10200413




                    181k10200413























                        1












                        $begingroup$

                        This uses string matching on the first element of each sublist and then discards the first element from the matches.



                        lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
                        
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
                        

                        
(* {{1, 2}, {5, 6}} *)


                        You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.






                        share|improve this answer









                        $endgroup$


















                          1












                          $begingroup$

                          This uses string matching on the first element of each sublist and then discards the first element from the matches.



                          lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
                          
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
                          

                          
(* {{1, 2}, {5, 6}} *)


                          You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.






                          share|improve this answer









                          $endgroup$
















                            1












                            1








                            1





                            $begingroup$

                            This uses string matching on the first element of each sublist and then discards the first element from the matches.



                            lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
                            
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
                            

                            
(* {{1, 2}, {5, 6}} *)


                            You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.






                            share|improve this answer









                            $endgroup$



                            This uses string matching on the first element of each sublist and then discards the first element from the matches.



                            lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
                            
Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]
                            

                            
(* {{1, 2}, {5, 6}} *)


                            You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 2 hours ago









                            BillBill

                            5,62569




                            5,62569























                                1












                                $begingroup$

                                lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


                                Using Cases



                                Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
                                
  Infinity]
                                

                                
(* {{1, 2}, {5, 6}} *)


                                or



                                Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
                                

                                
(* {{1, 2}, {5, 6}} *)


                                Or using Select



                                Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
                                

                                
(* {{1, 2}, {5, 6}} *)


                                Or using DeleteCases



                                Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
                                
  Infinity]
                                

                                
(* {{1, 2}, {5, 6}} *)





                                share|improve this answer









                                $endgroup$


















                                  1












                                  $begingroup$

                                  lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


                                  Using Cases



                                  Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
                                  
  Infinity]
                                  

                                  
(* {{1, 2}, {5, 6}} *)


                                  or



                                  Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
                                  

                                  
(* {{1, 2}, {5, 6}} *)


                                  Or using Select



                                  Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
                                  

                                  
(* {{1, 2}, {5, 6}} *)


                                  Or using DeleteCases



                                  Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
                                  
  Infinity]
                                  

                                  
(* {{1, 2}, {5, 6}} *)





                                  share|improve this answer









                                  $endgroup$
















                                    1












                                    1








                                    1





                                    $begingroup$

                                    lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


                                    Using Cases



                                    Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
                                    
  Infinity]
                                    

                                    
(* {{1, 2}, {5, 6}} *)


                                    or



                                    Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
                                    

                                    
(* {{1, 2}, {5, 6}} *)


                                    Or using Select



                                    Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
                                    

                                    
(* {{1, 2}, {5, 6}} *)


                                    Or using DeleteCases



                                    Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
                                    
  Infinity]
                                    

                                    
(* {{1, 2}, {5, 6}} *)





                                    share|improve this answer









                                    $endgroup$



                                    lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


                                    Using Cases



                                    Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
                                    
  Infinity]
                                    

                                    
(* {{1, 2}, {5, 6}} *)


                                    or



                                    Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]
                                    

                                    
(* {{1, 2}, {5, 6}} *)


                                    Or using Select



                                    Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]
                                    

                                    
(* {{1, 2}, {5, 6}} *)


                                    Or using DeleteCases



                                    Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
                                    
  Infinity]
                                    

                                    
(* {{1, 2}, {5, 6}} *)






                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 1 hour ago









                                    Bob HanlonBob Hanlon

                                    59.5k33596




                                    59.5k33596






























                                        draft saved

                                        draft discarded




















































                                        Thanks for contributing an answer to Mathematica Stack Exchange!


                                        • Please be sure to answer the question. Provide details and share your research!

                                        But avoid …



                                        • Asking for help, clarification, or responding to other answers.

                                        • Making statements based on opinion; back them up with references or personal experience.


                                        Use MathJax to format equations. MathJax reference.


                                        To learn more, see our tips on writing great answers.




                                        draft saved


                                        draft discarded














                                        StackExchange.ready(
                                        function () {
                                        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f190698%2fselecting-elements-from-lists-based-on-string-pattern%23new-answer', 'question_page');
                                        }
                                        );

                                        Post as a guest















                                        Required, but never shown





















































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown

































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown







                                        -

                                        Popular posts from this blog

                                        CARDNET

                                        Image
                                        CARDNET は日本カードネットワークが運営するクレジット決済ネットワーク。日本カードネットワークの略称としてもCARDNETが使用されている。 事件・事故 2017年4月15日午前11時8分からクレジットカードの決済がしづらくなる障害が発生した。障害は同日午後5時18分に復旧した。原因は、複数あるCARDNETセンターの拠点のうち1つで、2重化してあるL3スイッチの片方が故障し、1系統にトラフィックが集中したことによる輻輳が発生したため。対処としては、故障したL3スイッチ交換とシステム再起動が行われた [1] 。 出典 ^ 金子寛人 ( 2017年4月17日 ). “CARDNETのクレジット決済に6時間強障害、原因はL3スイッチ故障”. 日経コンピュータ. 2018年10月18日 閲覧。 この項目は、コンピュータに関連した 書きかけの項目 です。この項目を加筆・訂正などしてくださる協力者を求めています（PJ:コンピュータ/P:コンピュータ）。 この項目は、経済に関連した 書きかけの項目 です。この項目を加筆・訂正などしてくださる協力者を求めています（ポータル 経済学、プロジェクト 経済）。 This page is only for reference, If you need detailed information, please check here
                                        Read more

                                        Boot-repair Failure: Unable to locate package grub-common:i386

                                        Image
                                        0 I am on a system dual-booting Windows and Debian (usually using the latter), and a recent Windows update appears to have wreaked havoc on the Debian boot system. I managed to boot Windows again, but not Linux. Following online suggestions, I created a Live USB of Ubuntu, and booted from that. Then I have installed and run the boot-repair utility. The utility instructs me to type several lines including sudo chroot "/mnt/boot-sav/sda6" apt-get purge -y grub*-common grub-common:i386 To which I receive the error E: Unable to locate package grub-common:i386 I am given to understand the issue may have to do with having UEFI vs BIOS (I believe I have UEFI), but do not understand this well. In any case I have subsequently run the boot-repair BootInfo Summary utility which created the following file h...
                                        Read more

                                        濃尾地震

                                        Image
                                        濃尾地震 『岐阜市街大地震之図』 歌川国利画 本震 発生日 1891年（明治24年）10月28日 発生時刻 6時38分50秒（JST） 震央 日本 岐阜県本巣郡西根尾村（現・本巣市） 北緯35度35分 東経136度20分（ 地図 ） 規模    マグニチュード（M）8.0 最大震度    震度7： 注1 福井県今立郡鯖江町、愛知県葉栗郡大田島村、東春日井郡勝川村 地震の種類 直下型地震 被害 死傷者数 死者7,273人、負傷者17,175人 注1：当時の震度階級では「激烈」 プロジェクト:地球科学 プロジェクト:災害 テンプレートを表示 濃尾地震 （のうびじしん）は、1891年（明治24年）10月28日に濃尾地方で発生した、日本史上最大の内陸地殻内地震。「 美濃・尾張地震 （みの・おわりじしん）」とも呼ばれている。辛卯の年に発生したことから 辛卯震災 と呼んでいる報告書もある。 目次 1 概要 1.1 震源断層 2 被害 3 各地の震度 4 前兆現象 5 報道 6 学術的な意義 7 地震防災 8 脚注 9 関連項目 10 外部リンク 概要 濃尾地震発生当時の根尾谷断層 濃尾地震を引き起こした根尾谷断層 写真中央を斜めに走る段差が根尾谷断層 濃尾地震は、1891年10月28日6時38分50秒に発生した。震源は、岐阜県本巣郡西根尾村（現・本巣市）、北緯35度35分、東経136度20分付近。河角廣 (1951) は岐阜市付近（北緯35.6度、東経136.6度）に震央を仮定し規模 M K = 7.0 を与え [1] 、マグニチュードは M = 8.4 に換算されているが、明治・大正期の地震については0.5程度大きく見積もられているとされる [2] 。また、震央距離と震度との関係など当時のデータから後にM8.0 [3] とも推定される。アメリカ地質調査所 (USGS) でも8.0としている [4] 。「根尾谷断層帯」が活動した典型的な内陸地殻内地震（いわゆる直下型地震）であり、これは記録が残っている日本の内陸...
                                        Read more